Concept explainers
(a)
To calculate: The zeros of polynomial.
(a)

Answer to Problem 38CR
The interval are (-3, -1) and (1, 2)
Explanation of Solution
Given information:
Calculation:
Intermediate value theorem states that if a continuous function takes two values say
By this theorem we can say that if at one point the function is having a positive value and at other point it is having a negative value then between those intervals have a zero of the polynomial.
The table for the polynomial
x | F(x) |
-3 | - |
-2 | + |
-1 | - |
0 | - |
1 | - |
2 | + |
The intervals are (-3,-1) and (1, 2)
(b)
To calculate: zeros of the polynomial to nearest thousand.
(b)

Answer to Problem 38CR
The zeros of polynomial are: -1.897 and 0.738.
Explanation of Solution
Given information:
The intervals are (-3,-1) and (1, 2)
Calculation:
a) Adjusting the interval by 0.1 ,0.01 ,0.001 and 0.0001
x | F(x) |
-1.8 | + |
-1.9 | - |
x | F(x) |
-1.89 | + |
-1.90 | - |
x | f(x) |
-1.897 | + |
-1.898 | - |
So one zero of polynomial is -1.897
Similarly for the interval (1, 2) the other zeros is 0.738
Chapter 2 Solutions
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