Tofind:if the given statement is true or false.
Answer to Problem 84E
True
Explanation of Solution
Given:
The statement, “The solution set of the inequality
Concept Used:
The zeros of the polynomial
Consider the inequality,
First step to solve the given inequality is to find the key numbers of the inequality. For that, find zeros of the polynomial
This shows that the polynomial has no real zeros. That implies that there are no key numbers.
So, this function never crosses the x -axis and asthe leading coefficient is positive so it always lies above the x -axis.
Hence, it can be said that the given inequality is true for all real numbers.
Conclusion:
The given statement is true.
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
- Find the equation of the line / in the figure below. Give exact values using the form y = mx + b. m = b = y WebAssign Plot f(x) = 10* log 9 Xarrow_forwardA particle travels along a straight line path given by s=9.5t3-2.2t2-4.5t+9.9 (in meters). What time does it change direction? Report the higher of the answers to the nearest 2 decimal places in seconds.arrow_forwardUse the method of disks to find the volume of the solid that is obtained when the region under the curve y = over the interval [4,17] is rotated about the x-axis.arrow_forward
- 1. Find the area of the region enclosed between the curves y = x and y = x. Sketch the region.arrow_forwardfor the given rectangular coordinates, find two sets of polar coordinates for which 0≤θ<2π, one with r>0 and the other with r<0. (-2sqrt(3),9)arrow_forwardI circled the correct answer, could you show me how to do it using divergence and polar coordinatesarrow_forward
- The correct answer is D Could you explain and show the steps pleasearrow_forwardTaylor Series Approximation Example- H.W More terms used implies better approximation f(x) 4 f(x) Zero order f(x + 1) = f(x;) First order f(x; + 1) = f(x;) + f'(x;)h 1.0 Second order 0.5 True f(x + 1) = f(x) + f'(x)h + ƒ"(x;) h2 2! f(x+1) 0 x; = 0 x+1 = 1 x h f(x)=0.1x4-0.15x³- 0.5x2 -0.25x + 1.2 51 Taylor Series Approximation H.w: Smaller step size implies smaller error Errors f(x) + f(x,) Zero order f(x,+ 1) = f(x) First order 1.0 0.5 Reduced step size Second order True f(x + 1) = f(x) + f'(x)h f(x; + 1) = f(x) + f'(x)h + "(xi) h2 f(x,+1) O x₁ = 0 x+1=1 Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5 iterations (or & s= 5%) for f(x)=0.1x 0.15x³-0.5x²- 0.25x + 1.2 52arrow_forwardCould you explain this using the formula I attached and polar coorindatesarrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning