Concept explainers
(a)
The graph of the function
(a)
Answer to Problem 49E
The point of intersection is (0, 0) and (2.5, 0)
Explanation of Solution
Given information:
The given polynomial function as shown below,
Formula used:
The horizontal axis is x axis and the vertical axis is y axis.
Calculation:
Let us first draw the graph of the polynomial function,
Conclusion:
The point of intersection is (0, 0) and (2.5, 0)
(b)
The x-intercepts of the graph.
(b)
Answer to Problem 49E
The x -intercepts of the graph are at (0,0) and
Explanation of Solution
Given information:
The given polynomial function as shown below,
Formula used:
The horizontal axis is x axis and the vertical axis is y axis.
Calculation:
By observing the graph of the polynomial function, we can see that the x -intercepts of the graph are at (0,0) and
Conclusion:
The x -intercepts of the graph are at (0,0) and
(c)
The real zeros of the function.
(c)
Answer to Problem 49E
The real zeroes for the polynomial function are at x = 0 and
Explanation of Solution
Given information:
The given polynomial function as shown below,
Formula used:
The polynomial equation is equated to zero.
Calculation:
Now set
So, the real zeroes for the polynomial function are at x = 0 and
Conclusion:
The real zeroes for the polynomial function are at x = 0 and
(d)
The comparisonof zeros of the polynomial.
(d)
Answer to Problem 49E
The x-intercepts occur at the same points where the real zeroes occur.
Explanation of Solution
Given information:
The given polynomial function as shown below,
Formula used:
The polynomial is equated to zero.
Calculation:
By comparing the results of part (c) with any xThe polynomial is equated to zero.
-intercepts, we can see that the x-intercepts occur at the same points where the real zeroes occur.
Conclusion:
The x-intercepts occur at the same points where the real zeroes occur.
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
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