To calculate: The vertical and horizontal asymptotes of the graphof the provided function.
Answer to Problem 14E
The vertical and horizontal asymptotes of the graph of the provided function is
Explanation of Solution
Given information:
Consider the provided function,
An asymptotes of a curve in a straight line which touches the given curve at infinitely.
Calculation:
First find the vertical asymptotes,
Consider the function,
To find vertical asymptote set denominator to 0.
Substitute the denominator is equal to 0,
Simplifying further,
Hence, the vertical asymptotes is
Consider the function
Here the provided function is a rational function.
If
And the degree
There will no horizontal asymptotes because there is a bigger exponent in the numerator which is 2.
Hence, the horizontal asymptote is does not exists.
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
- 3. Use the method of washers to find the volume of the solid that is obtained when the region between the graphs f(x) = √√2 and g(x) = secx over the interval ≤x≤ is rotated about the x-axis.arrow_forward4. Use cylindrical shells to find the volume of the solid generated when the region enclosed by the given curves is revolved about the x-axis. y = √√x, y = 0, y = √√3arrow_forward5 4 3 21 N -5-4-3-2 -1 -2 -3 -4 1 2 3 4 5 -5+ Write an equation for the function graphed above y =arrow_forward
- 6 5 4 3 2 1 -5 -4-3-2-1 1 5 6 -1 23 -2 -3 -4 -5 The graph above is a transformation of the function f(x) = |x| Write an equation for the function graphed above g(x) =arrow_forwardThe graph of y x² is shown on the grid. Graph y = = (x+3)² – 1. +10+ 69 8 7 5 4 9 432 6. 7 8 9 10 1 10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 -2 -3 -4 -5 -6- Clear All Draw:arrow_forwardSketch a graph of f(x) = 2(x − 2)² − 3 4 3 2 1 5 ས་ -5 -4 -3 -2 -1 1 2 3 4 -1 -2 -3 -4 -5+ Clear All Draw:arrow_forward
- 5. Find the arc length of the curve y = 3x³/2 from x = 0 to x = 4.arrow_forward-6 -5 * 10 8 6 4 2 -2 -1 -2 1 2 3 4 5 6 -6 -8 -10- The function graphed above is: Concave up on the interval(s) Concave down on the interval(s) There is an inflection point at:arrow_forward6 5 4 3 2 1 -6 -5 -3 -2 3 -1 -2 -3 -4 -5 The graph above is a transformation of the function x² Write an equation for the function graphed above g(x) =arrow_forward
- 6 5 4 3 2 1 -1 -1 -2 -3 -4 A -5 -6- The graph above shows the function f(x). The graph below shows g(x). 6 5 4 3 2 1 3 -1 -2 -3 -4 -5 -6 | g(x) is a transformation of f(x) where g(x) = Af(Bx) where: A = B =arrow_forward5+ 4 3 2 1. -B -2 -1 1 4 5 -1 -2 -3 -4 -5 Complete an equation for the function graphed above y =arrow_forward60 फं + 2 T 2 -2 -3 2 4 5 6 The graph above shows the function f(x). The graph below shows g(x). फ 3 -1 -2 2 g(x) is a transformation of f(x) where g(x) = Af(Bx) where: A = B =arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning