a. Answer − 2 , 1 , 4 Explanation Calculation: Consider the folwing table int e r v a l v a l u e , o f , f ( x ) ( − ∞ , − 2 ) p o s i t i v e ( − 2 , 1 ) N e g a t i v e ( 1 , 4 ) N e g a t i v e ( 4 , ∞ ) p o s i t i v e From the above table, note that the polynomial function f is positive in ( − ∞ , − 2 ) and negative from ( − 2 , 1 ) , so the graph crosses x-axis at − 2 , similarly at 4 but touches at 1 Hence, the real zeros of polynomial function f aer − 2 , 1 , 4 b. To determine Explain the behaviour of the graph of f at X = 1 . Answer x − a x i s at x = 1 Explanation Calculation: The graph of the polynomial is negative in the intervals ( − 2 , 1 ) and ( 1 , 4 ) so, the graph touches the x − a x i s at x = 1 c. To determine Find the least possible degree of f ? Answer 4 Explanation Calculation: Since, there are four zeros for polynomial function ( 12 , 4 a n d 1 o f m u l t i p l i c i t y 2 ) and a function can have degree equal to the no. Of zeros Hence, the least possible degree for polynomial function f is 4 d. To determine Verify that the leading coefficient of f positive or negative. Answer The leading coefficient is positive since the degree is even and the graph eventually rises to the left and right Explanation Calculation: The graph is positive in the intervals ( − ∞ , − 2 ) and ( 4 , ∞ ) which means the graph eventually rises to the left and right. According to leading coefficient test, when the degree is even and if the graph rises to the left and right then the leading coefficient is positive Hence, the leading coefficient is positive since the degree is even and the graph eventually rises to the left and right. e. To determine Sketch a graph of a function according to the table. Answer Explanation Calculation: Use the T 1 − 83 calculator and click on Y = button and enter the above expression The display is as shown below Step2: Click on WINDOW button and set the range of the axis The display is as shown below Step3: Click on GRAPH button to plot the graph of the above function The display is as shown below

4th Edition

ISBN: 9781337516853

Author: Larson

Publisher: CENGAGE CO

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Question

Chapter 2.5, Problem 120E

To determine

Find the three real zeros of the polynomial function f .

Expert Solution

Answer to Problem 120E

−2,1,4

Explanation of Solution

Calculation:

Consider the folwing table

intervalvalue,of,f(x)(−∞,−2)positive(−2,1)Negative(1,4)Negative(4,∞)positive

From the above table, note that the polynomial function f is positive in (−∞,−2) and negative from (−2,1) , so the graph crosses x-axis at −2, similarly at 4 but touches at 1

Hence, the real zeros of polynomial function f aer −2,1,4

To determine

Explain the behaviour of the graph of f at X=1 .

Expert Solution

Answer to Problem 120E

x−axis at x=1

Explanation of Solution

Calculation:

The graph of the polynomial is negative in the intervals (−2,1) and (1,4) so, the graph touches the x−axis at x=1

To determine

Find the least possible degree of f ?

Expert Solution

Answer to Problem 120E

Explanation of Solution

Calculation:

Since, there are four zeros for polynomial function (12,4and1ofmultiplicity2) and a function can have degree equal to the no. Of zeros

Hence, the least possible degree for polynomial function f is 4

To determine

Verify that the leading coefficient of f positive or negative.

Expert Solution

Answer to Problem 120E

The leading coefficient is positive since the degree is even and the graph eventually rises to the left and right

Explanation of Solution

Calculation:

The graph is positive in the intervals (−∞,−2) and (4,∞) which means the graph eventually rises to the left and right.

According to leading coefficient test, when the degree is even and if the graph rises to the left and right then the leading coefficient is positive

Hence, the leading coefficient is positive since the degree is even and the graph eventually rises to the left and right.

To determine

Sketch a graph of a function according to the table.

Expert Solution

Answer to Problem 120E

EBK PRECALCULUS W/LIMITS, Chapter 2.5, Problem 120E , additional homework tip 1

Explanation of Solution

Calculation:

Use the T1−83 calculator and click on Y= button and enter the above expression

The display is as shown below

EBK PRECALCULUS W/LIMITS, Chapter 2.5, Problem 120E , additional homework tip 2

Step2: Click on WINDOW button and set the range of the axis

The display is as shown below

EBK PRECALCULUS W/LIMITS, Chapter 2.5, Problem 120E , additional homework tip 3

Step3: Click on GRAPH button to plot the graph of the above function

The display is as shown below

EBK PRECALCULUS W/LIMITS, Chapter 2.5, Problem 120E , additional homework tip 4

Chapter 2.5, Problem 119E

Chapter 2.5, Problem 121E

Chapter 2 Solutions

EBK PRECALCULUS W/LIMITS

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Prob. 64E Ch. 2.6 - Prob. 65E Ch. 2.6 - Prob. 66E Ch. 2.6 - Prob. 67E Ch. 2.6 - Prob. 68E Ch. 2.6 - Prob. 69E Ch. 2.6 - Prob. 70E Ch. 2.6 - Prob. 71E Ch. 2.6 - Prob. 72E Ch. 2.6 - Prob. 73E Ch. 2.6 - Prob. 74E Ch. 2.6 - Prob. 75E Ch. 2.6 - Prob. 76E Ch. 2.6 - Prob. 77E Ch. 2.6 - Prob. 78E Ch. 2.6 - Prob. 79E Ch. 2.6 - Prob. 80E Ch. 2.6 - Prob. 81E Ch. 2.6 - Prob. 82E Ch. 2.7 - Prob. 1E Ch. 2.7 - Prob. 2E Ch. 2.7 - Prob. 3E Ch. 2.7 - Prob. 4E Ch. 2.7 - Prob. 5E Ch. 2.7 - Prob. 6E Ch. 2.7 - Prob. 7E Ch. 2.7 - Prob. 8E Ch. 2.7 - Prob. 9E Ch. 2.7 - Prob. 10E Ch. 2.7 - Prob. 11E Ch. 2.7 - Prob. 12E Ch. 2.7 - Prob. 13E Ch. 2.7 - Prob. 14E Ch. 2.7 - Prob. 15E Ch. 2.7 - Prob. 16E Ch. 2.7 - Prob. 17E Ch. 2.7 - Prob. 18E Ch. 2.7 - Prob. 19E Ch. 2.7 - Prob. 20E Ch. 2.7 - Prob. 21E Ch. 2.7 - Prob. 22E Ch. 2.7 - Prob. 23E Ch. 2.7 - Prob. 24E Ch. 2.7 - Prob. 25E Ch. 2.7 - Prob. 26E Ch. 2.7 - Prob. 27E Ch. 2.7 - Prob. 28E Ch. 2.7 - Prob. 29E Ch. 2.7 - Prob. 30E Ch. 2.7 - Prob. 31E Ch. 2.7 - Prob. 32E Ch. 2.7 - Prob. 33E Ch. 2.7 - Prob. 34E Ch. 2.7 - Prob. 35E Ch. 2.7 - Prob. 36E Ch. 2.7 - Prob. 37E Ch. 2.7 - Prob. 38E Ch. 2.7 - Prob. 39E Ch. 2.7 - Prob. 40E Ch. 2.7 - Prob. 41E Ch. 2.7 - Prob. 42E Ch. 2.7 - Prob. 43E Ch. 2.7 - Prob. 44E Ch. 2.7 - Prob. 45E Ch. 2.7 - Prob. 46E Ch. 2.7 - Prob. 47E Ch. 2.7 - Prob. 48E Ch. 2.7 - Prob. 49E Ch. 2.7 - Prob. 50E Ch. 2.7 - Prob. 51E Ch. 2.7 - Prob. 52E Ch. 2.7 - Prob. 53E Ch. 2.7 - Prob. 54E Ch. 2.7 - Prob. 55E Ch. 2.7 - Prob. 56E Ch. 2.7 - Prob. 57E Ch. 2.7 - Prob. 58E Ch. 2.7 - Prob. 59E Ch. 2.7 - Prob. 60E Ch. 2.7 - Prob. 61E Ch. 2.7 - Prob. 62E Ch. 2.7 - Prob. 63E Ch. 2.7 - Prob. 64E Ch. 2.7 - Prob. 65E Ch. 2.7 - Prob. 66E Ch. 2.7 - Prob. 67E Ch. 2.7 - Prob. 68E Ch. 2.7 - Prob. 69E Ch. 2.7 - Prob. 70E Ch. 2.7 - Prob. 71E Ch. 2.7 - Prob. 72E Ch. 2.7 - Prob. 73E Ch. 2.7 - Prob. 74E Ch. 2.7 - Prob. 75E Ch. 2.7 - Prob. 76E Ch. 2.7 - Prob. 77E Ch. 2.7 - Prob. 78E Ch. 2.7 - Prob. 79E Ch. 2.7 - Prob. 80E Ch. 2.7 - Prob. 81E Ch. 2.7 - Prob. 82E Ch. 2.7 - Prob. 83E Ch. 2.7 - Prob. 84E Ch. 2.7 - Prob. 85E Ch. 2.7 - Prob. 86E Ch. 2.7 - Prob. 87E Ch. 2.7 - Prob. 88E Ch. 2.7 - Prob. 89E Ch. 2.7 - Prob. 90E Ch. 2 - Prob. 1RE Ch. 2 - Prob. 2RE Ch. 2 - Prob. 3RE Ch. 2 - Prob. 4RE Ch. 2 - Prob. 5RE Ch. 2 - Prob. 6RE Ch. 2 - Prob. 7RE Ch. 2 - Prob. 8RE Ch. 2 - Prob. 9RE Ch. 2 - Prob. 10RE Ch. 2 - Prob. 11RE Ch. 2 - Prob. 12RE Ch. 2 - Prob. 13RE Ch. 2 - Prob. 14RE Ch. 2 - Prob. 15RE Ch. 2 - Prob. 16RE Ch. 2 - Prob. 17RE Ch. 2 - Prob. 18RE Ch. 2 - Prob. 19RE Ch. 2 - Prob. 20RE Ch. 2 - Prob. 21RE Ch. 2 - Prob. 22RE Ch. 2 - Prob. 23RE Ch. 2 - Prob. 24RE Ch. 2 - Prob. 25RE Ch. 2 - Prob. 26RE Ch. 2 - Prob. 27RE Ch. 2 - Prob. 28RE Ch. 2 - Prob. 29RE Ch. 2 - Prob. 30RE Ch. 2 - Prob. 31RE Ch. 2 - Prob. 32RE Ch. 2 - Prob. 33RE Ch. 2 - Prob. 34RE Ch. 2 - Prob. 35RE Ch. 2 - Prob. 36RE Ch. 2 - Prob. 37RE Ch. 2 - Prob. 38RE Ch. 2 - Prob. 39RE Ch. 2 - Prob. 40RE Ch. 2 - Prob. 41RE Ch. 2 - Prob. 42RE Ch. 2 - Prob. 43RE Ch. 2 - Prob. 44RE Ch. 2 - Prob. 45RE Ch. 2 - Prob. 46RE Ch. 2 - Prob. 47RE Ch. 2 - Prob. 48RE Ch. 2 - Prob. 49RE Ch. 2 - Prob. 50RE Ch. 2 - Prob. 51RE Ch. 2 - Prob. 52RE Ch. 2 - Prob. 53RE Ch. 2 - Prob. 54RE Ch. 2 - Prob. 55RE Ch. 2 - Prob. 56RE Ch. 2 - Prob. 57RE Ch. 2 - Prob. 58RE Ch. 2 - Prob. 59RE Ch. 2 - Prob. 60RE Ch. 2 - Prob. 61RE Ch. 2 - Prob. 62RE Ch. 2 - Prob. 63RE Ch. 2 - Prob. 64RE Ch. 2 - Prob. 65RE Ch. 2 - Prob. 66RE Ch. 2 - Prob. 67RE Ch. 2 - Prob. 68RE Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 13CT Ch. 2 - Prob. 14CT Ch. 2 - Prob. 15CT Ch. 2 - Prob. 16CT Ch. 2 - Prob. 17CT Ch. 2 - Prob. 18CT Ch. 2 - Prob. 1PS Ch. 2 - Prob. 2PS Ch. 2 - Prob. 3PS Ch. 2 - Prob. 4PS Ch. 2 - Prob. 5PS Ch. 2 - Prob. 6PS Ch. 2 - Prob. 7PS Ch. 2 - Prob. 8PS Ch. 2 - Prob. 9PS Ch. 2 - Prob. 10PS Ch. 2 - Prob. 11PS Ch. 2 - Prob. 12PS Ch. 2 - Prob. 13PS

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