Concept explainers
a.
To describe: A polynomial function that could represent the given graph by indicating the degree of the function and the sign of its leading coefficient.
a.
Answer to Problem 106E
Degree is odd and leading coefficient is positive.
Explanation of Solution
Given Information: A graph is given.
The graph falls to the left and rises to the right, applying the leading coefficient test, this implies that the degree is odd and leading coefficient is positive.
Thus, degree is odd and leading coefficient is positive.
b.
To describe: A polynomial function that could represent the given graph by indicating the degree of the function and the sign of its leading coefficient.
b.
Answer to Problem 106E
Degree is even and leading coefficient is positive.
Explanation of Solution
Given Information: A graph is given.
The graph rises to the left and to the right, applying the leading coefficient test, this implies that degree is even and leading coefficient is positive.
Thus, degree is even and leading coefficient is positive.
c.
To describe: A polynomial function that could represent the given graph by indicating the degree of the function and the sign of its leading coefficient.
c.
Answer to Problem 106E
Degree is even and leading coefficient is positive.
Explanation of Solution
Given Information: A graph is given.
The graph rises to the left and to the right, applying the leading coefficient test, this implies that degree is even and leading coefficient is positive.
Thus, degree is even and leading coefficient is positive.
d.
To describe: A polynomial function that could represent the given graph by indicating the degree of the function and the sign of its leading coefficient.
d.
Answer to Problem 106E
Degree is odd and leading coefficient is positive.
Explanation of Solution
Given Information: A graph is given.
The graph falls to the left and rises to the right, applying the leading coefficient test, this implies that the degree is odd and leading coefficient is positive.
Thus, degree is odd and leading coefficient is positive.
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
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