EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR

8th Edition

ISBN: 9780357022078

Author: Larson

Publisher: CENGAGE L

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Question

Chapter 2.7, Problem 81E

To determine

To show: that the total area A of the page is given by A=2x(2x+11)x−2.

Expert Solution

Answer to Problem 81E

A=2x(2x+11)x−2 .

Explanation of Solution

Given information: A page that is x inches wide and y inches high contains 30 square

inches of print. The margins at the top and bottom are 2 inches deep and margins on each side are 1 inch wide.

Formula used:

Area=length × width.

Calculation:

Length of page = y.

Width of the page= x.

Area A=xy ......( 1 ).

Since, margins at the top and bottom are 2 units each. And on edges it is 1 inch wide each and area of printed region is 30 inch square.

Length of printed area=( y -4).

Width of printed area=( x -2).

Area of printed area =30.

Therefore,

30=(y−4)(x−2).(y−4)=30(x−2).y=30(x−2)+4.y=(4x+22)x−2.xy=x(4x+22)x−2=2x(2x+11)x−2.A=2x(2x+11)x−2.

To determine

To find: the domain of the function based on the physical constraints of the problem.

Expert Solution

Answer to Problem 81E

xshould be greater than 2 , Since Area of the page cannot be no-positive.

The domain of the area function is x >2.

Explanation of Solution

Given information: A page that is x inches wide and y inches high contains 30 square

inches of print. The margins at the top and bottom are 2 inches deep and margins on each side are 1 inch wide.

Calculation:

xshould be greater than 2 , Since Area of the page cannot be no-positive.

If x is greater than 2 , is greater than 2 , y will automatically be greater than 4.

The domain of the area function is x >2.

To determine

To sketch: a graph of the area function using graphing utility and approximate the page size such that the minimum amount of paper will be used. Verify answer numerically using the table feature of the graphing utility.

Expert Solution

Answer to Problem 81E

At around x = 5 thenArea is minimum and is close to 70 square inches.

Explanation of Solution

Given information: A page that is x inches wide and y inches high contains 30 square

inches of print. The margins at the top and bottom are 2 inches deep and margins on each side are 1 inch wide.

Calculation:

The graph of the function A=2x(2x+11)x−2 is given below

EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR, Chapter 2.7, Problem 81E

Where x -axis shows width andy -axis shows area of the page.

To find page size for which paper will be minimum is the problem of finding x such that Area is minimum.

At around x = 5 then Area is minimum and is close to 70 square inches.

Chapter 2.7, Problem 80E

Chapter 2.7, Problem 82E

Chapter 2 Solutions

EP PRECALC.GRAPHING APPR.-WEBASSIGN-1YR

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Prob. 86E Ch. 2.7 - Prob. 87E Ch. 2.7 - Prob. 88E Ch. 2.7 - Prob. 89E Ch. 2.7 - Prob. 90E Ch. 2.7 - Prob. 91E Ch. 2.7 - Prob. 92E Ch. 2.7 - Prob. 93E Ch. 2.7 - Prob. 94E Ch. 2.7 - Prob. 95E Ch. 2.7 - Prob. 96E Ch. 2.7 - Prob. 97E Ch. 2.7 - Prob. 98E Ch. 2.7 - Prob. 99E Ch. 2.7 - Prob. 100E Ch. 2.7 - Prob. 101E Ch. 2.8 - Prob. 1E Ch. 2.8 - Prob. 2E Ch. 2.8 - Prob. 3E Ch. 2.8 - Prob. 4E Ch. 2.8 - Prob. 5E Ch. 2.8 - Prob. 6E Ch. 2.8 - Prob. 7E Ch. 2.8 - Prob. 8E Ch. 2.8 - Prob. 9E Ch. 2.8 - Prob. 10E Ch. 2.8 - Prob. 11E Ch. 2.8 - Prob. 12E Ch. 2.8 - Prob. 13E Ch. 2.8 - Prob. 14E Ch. 2.8 - Prob. 15E Ch. 2.8 - Prob. 16E Ch. 2.8 - Prob. 17E Ch. 2.8 - Prob. 18E Ch. 2.8 - Prob. 19E Ch. 2.8 - Prob. 20E Ch. 2.8 - Prob. 21E Ch. 2.8 - Prob. 22E Ch. 2.8 - Prob. 23E Ch. 2.8 - Prob. 24E Ch. 2.8 - Prob. 25E Ch. 2.8 - Prob. 26E Ch. 2.8 - Prob. 27E Ch. 2.8 - Prob. 28E Ch. 2.8 - Prob. 29E Ch. 2.8 - Prob. 30E Ch. 2.8 - Prob. 31E Ch. 2.8 - Prob. 32E Ch. 2.8 - Prob. 33E Ch. 2.8 - Prob. 34E Ch. 2.8 - Prob. 35E Ch. 2.8 - Prob. 36E Ch. 2.8 - Prob. 37E Ch. 2.8 - Prob. 38E Ch. 2.8 - Prob. 39E Ch. 2.8 - Prob. 40E Ch. 2 - Prob. 1CR Ch. 2 - Prob. 2CR Ch. 2 - Prob. 3CR Ch. 2 - Prob. 4CR Ch. 2 - Prob. 5CR Ch. 2 - Prob. 6CR Ch. 2 - Prob. 7CR Ch. 2 - Prob. 8CR Ch. 2 - Prob. 9CR Ch. 2 - Prob. 10CR Ch. 2 - Prob. 11CR Ch. 2 - Prob. 12CR Ch. 2 - Prob. 13CR Ch. 2 - Prob. 14CR Ch. 2 - Prob. 15CR Ch. 2 - Prob. 16CR Ch. 2 - Prob. 17CR Ch. 2 - Prob. 18CR Ch. 2 - Prob. 19CR Ch. 2 - Prob. 20CR Ch. 2 - Prob. 21CR Ch. 2 - Prob. 22CR Ch. 2 - Prob. 23CR Ch. 2 - Prob. 24CR Ch. 2 - Prob. 25CR Ch. 2 - Prob. 26CR Ch. 2 - Prob. 27CR Ch. 2 - Prob. 28CR Ch. 2 - Prob. 29CR Ch. 2 - Prob. 30CR Ch. 2 - Prob. 31CR Ch. 2 - Prob. 32CR Ch. 2 - Prob. 33CR Ch. 2 - Prob. 34CR Ch. 2 - Prob. 35CR Ch. 2 - Prob. 36CR Ch. 2 - Prob. 37CR Ch. 2 - Prob. 38CR Ch. 2 - Prob. 39CR Ch. 2 - Prob. 40CR Ch. 2 - Prob. 41CR Ch. 2 - Prob. 42CR Ch. 2 - Prob. 43CR Ch. 2 - Prob. 44CR Ch. 2 - Prob. 45CR Ch. 2 - Prob. 46CR Ch. 2 - Prob. 47CR Ch. 2 - Prob. 48CR Ch. 2 - Prob. 49CR Ch. 2 - Prob. 50CR Ch. 2 - Prob. 51CR Ch. 2 - Prob. 52CR Ch. 2 - Prob. 53CR Ch. 2 - Prob. 54CR Ch. 2 - Prob. 55CR Ch. 2 - Prob. 56CR Ch. 2 - Prob. 57CR Ch. 2 - Prob. 58CR Ch. 2 - Prob. 59CR Ch. 2 - Prob. 60CR Ch. 2 - Prob. 61CR Ch. 2 - Prob. 62CR Ch. 2 - Prob. 63CR Ch. 2 - Prob. 64CR Ch. 2 - Prob. 65CR Ch. 2 - Prob. 66CR Ch. 2 - Prob. 67CR Ch. 2 - Prob. 68CR Ch. 2 - Prob. 69CR Ch. 2 - Prob. 70CR Ch. 2 - Prob. 71CR Ch. 2 - Prob. 72CR Ch. 2 - Prob. 73CR Ch. 2 - Prob. 74CR Ch. 2 - Prob. 75CR Ch. 2 - Prob. 76CR Ch. 2 - Prob. 77CR Ch. 2 - Prob. 78CR Ch. 2 - Prob. 79CR Ch. 2 - Prob. 80CR Ch. 2 - Prob. 81CR Ch. 2 - Prob. 82CR Ch. 2 - Prob. 83CR Ch. 2 - Prob. 84CR Ch. 2 - Prob. 85CR Ch. 2 - Prob. 86CR Ch. 2 - Prob. 87CR Ch. 2 - Prob. 88CR Ch. 2 - Prob. 89CR Ch. 2 - Prob. 90CR Ch. 2 - Prob. 91CR Ch. 2 - Prob. 92CR Ch. 2 - Prob. 93CR Ch. 2 - Prob. 94CR Ch. 2 - Prob. 95CR Ch. 2 - Prob. 96CR Ch. 2 - Prob. 97CR Ch. 2 - Prob. 98CR Ch. 2 - Prob. 99CR Ch. 2 - Prob. 100CR Ch. 2 - Prob. 101CR Ch. 2 - Prob. 102CR Ch. 2 - Prob. 103CR Ch. 2 - Prob. 104CR Ch. 2 - Prob. 105CR Ch. 2 - Prob. 106CR Ch. 2 - Prob. 107CR Ch. 2 - Prob. 108CR Ch. 2 - Prob. 109CR Ch. 2 - Prob. 110CR Ch. 2 - Prob. 111CR Ch. 2 - Prob. 112CR Ch. 2 - Prob. 113CR Ch. 2 - Prob. 114CR Ch. 2 - Prob. 115CR Ch. 2 - Prob. 116CR Ch. 2 - Prob. 117CR Ch. 2 - Prob. 118CR Ch. 2 - Prob. 119CR Ch. 2 - Prob. 120CR Ch. 2 - Prob. 121CR Ch. 2 - Prob. 122CR Ch. 2 - Prob. 123CR Ch. 2 - Prob. 124CR Ch. 2 - Prob. 125CR Ch. 2 - Prob. 126CR Ch. 2 - Prob. 127CR Ch. 2 - Prob. 128CR Ch. 2 - Prob. 129CR Ch. 2 - Prob. 130CR Ch. 2 - Prob. 131CR Ch. 2 - Prob. 132CR Ch. 2 - Prob. 133CR Ch. 2 - Prob. 134CR Ch. 2 - Prob. 135CR Ch. 2 - Prob. 136CR Ch. 2 - Prob. 137CR Ch. 2 - Prob. 138CR Ch. 2 - Prob. 139CR Ch. 2 - Prob. 140CR Ch. 2 - Prob. 141CR Ch. 2 - Prob. 142CR Ch. 2 - Prob. 143CR Ch. 2 - Prob. 144CR Ch. 2 - Prob. 145CR Ch. 2 - Prob. 146CR Ch. 2 - Prob. 147CR Ch. 2 - Prob. 148CR Ch. 2 - Prob. 149CR Ch. 2 - Prob. 150CR Ch. 2 - Prob. 151CR Ch. 2 - Prob. 152CR Ch. 2 - Prob. 153CR Ch. 2 - Prob. 154CR Ch. 2 - Prob. 155CR Ch. 2 - Prob. 156CR Ch. 2 - Prob. 157CR Ch. 2 - Prob. 158CR Ch. 2 - Prob. 159CR Ch. 2 - Prob. 160CR Ch. 2 - Prob. 161CR Ch. 2 - Prob. 162CR Ch. 2 - Prob. 163CR Ch. 2 - Prob. 164CR Ch. 2 - Prob. 165CR Ch. 2 - Prob. 166CR Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 13CT Ch. 2 - Prob. 14CT Ch. 2 - Prob. 15CT Ch. 2 - Prob. 16CT Ch. 2 - Prob. 17CT Ch. 2 - Prob. 18CT Ch. 2 - Prob. 19CT Ch. 2 - Prob. 20CT Ch. 2 - Prob. 21CT

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that the total area A of the page is given by A = 2 x ( 2 x + 11 ) x − 2 .

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To show: that the total area A of the page is given by A=2x(2x+11)x−2.

Answer to Problem 81E

Explanation of Solution

To find: the domain of the function based on the physical constraints of the problem.

Answer to Problem 81E

Explanation of Solution

To sketch: a graph of the area function using graphing utility and approximate the page size such that the minimum amount of paper will be used. Verify answer numerically using the table feature of the graphing utility.

Answer to Problem 81E

Explanation of Solution

Chapter 2 Solutions