PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780134672090
Author: Demana
Publisher: PEARSON
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Expert Solution & Answer
Chapter 2.6, Problem 56E
Solution
The intercepts, analyse and graph the function.
The intercept are (1.19, 0) and (0, −2.5) .
Given:
The function is f(x)=2x3−2x2−x+5x−2 .
Concept Used:
The x -intercept is given by zeros of numerator that are not zero of denominator. And y -intercept is given by f(0) .
And,
If a polynomial function in the form y=f(x)g(x)=(anxn+....)(bmxm+....) , then, vertical asymptotes is given by real zeros of denominator provided it should not be zero of numerator.
And,
The end behaviour asymptote given by limx→∞−f(x)g(x) or limx→∞+f(x)g(x) is horizontal asymptotes.
The condition can be concluded as,
1) If n<m , the end behaviour is horizontal asymptotes that is y=0 ,
2) If n=m the end behaviour is horizontal asymptotes is horizontal asymptotes that is y=anbn
3) If n>m ,the quotient q(x) of f(x)/g(x) is the end behaviour asymptotes, where q(x) is given by f(x)=g(x)q(x)+r(x) with r(x) is remainder of f(x)/g(x) . Hence, no horizontal asymptotes.
Calculation:
Consider the function, f(x)=2x3−2x2−x+5x−2 .
Find the intercept, the x -intercept is given by zeros of numerator that are not zero of denominator.
So, find the zeros of the numerator as,
2x3−2x2−x+5=0x≈−1.19
Thus, x≈1.19 . The x- intercepts is (1.19, 0) .
And y -intercept is given by f(0) , so from f(x)=2x3−2x2−x+5x−2 .
f(0)=2(0)3−2(0)2−(0)+50−2=−2.5
Thus y -intercept is (0, −2.5) .
Hence the intercept are (1.19, 0) and (0, −2.5) .
Find vertical asymptotes, that is given by zeros of denominator x−2 ,
Since, the zeros of denominator of f(x) is x=2 , Vertical asymptotes is line x=2 .
To find end behaviour asymptotes, find m and n by comparing, f(x)=2x3−2x2−x+5x−2 with y=f(x)g(x)=(anxn+....)(bmxm+....) .
Since, n>m end behaviour asymptotes is the quotient of f(x)=2x3−2x2−x+5x−2 . Rewrite f(x) using division as follows,
2x2−x −(2x2−4x) ¯ 3x+5 −(3x−6) ¯ 11
Thus, write f(x) as,
f(x)=2x2+2x+3+11x−2
Hence, end behaviour asymptotes is y=2x2+2x+3 .
To graph f(x)=2x3−2x2−x+5x−2 , compute the value of f(x) for chosen values of x as follows:
The graph of f(x)=2x3−2x2−x+5x−2 obtain is as:
Interpretations form graph:
1) Domain of f(x) is (−∞, 2)∪(2, ∞)
2) Range is (−∞, ∞) .
3) Continuous everywhere except x=2
4) Increasing in (2.89, ∞) and decreasing in (−∞, 2)∪(2, 2.89) .
5) No Local maxima and local minima at (2.89, 37.84) .
6) Not symmetric.
7) Unbounded.
Conclusion:
The intercept are (1.19, 0) and (0, −2.5) .
Chapter 2 Solutions
PRECALCULUS:GRAPHICAL,...-NASTA ED.
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Prob. 53ECh. 2.7 - Prob. 54ECh. 2.7 - Prob. 55ECh. 2.8 - Prob. 1QRCh. 2.8 - Prob. 2QRCh. 2.8 - Prob. 3QRCh. 2.8 - Prob. 4QRCh. 2.8 - Prob. 5QRCh. 2.8 - Prob. 6QRCh. 2.8 - Prob. 7QRCh. 2.8 - Prob. 8QRCh. 2.8 - Prob. 9QRCh. 2.8 - Prob. 10QRCh. 2.8 - Prob. 1ECh. 2.8 - Prob. 2ECh. 2.8 - Prob. 3ECh. 2.8 - Prob. 4ECh. 2.8 - Prob. 5ECh. 2.8 - Prob. 6ECh. 2.8 - Prob. 7ECh. 2.8 - Prob. 8ECh. 2.8 - Prob. 9ECh. 2.8 - Prob. 10ECh. 2.8 - Prob. 11ECh. 2.8 - Prob. 12ECh. 2.8 - Prob. 13ECh. 2.8 - Prob. 14ECh. 2.8 - Prob. 15ECh. 2.8 - Prob. 16ECh. 2.8 - Prob. 17ECh. 2.8 - Prob. 18ECh. 2.8 - Prob. 19ECh. 2.8 - Prob. 20ECh. 2.8 - Prob. 21ECh. 2.8 - Prob. 22ECh. 2.8 - Prob. 23ECh. 2.8 - Prob. 24ECh. 2.8 - Prob. 25ECh. 2.8 - Prob. 26ECh. 2.8 - Prob. 27ECh. 2.8 - Prob. 28ECh. 2.8 - Prob. 29ECh. 2.8 - Prob. 30ECh. 2.8 - Prob. 31ECh. 2.8 - Prob. 32ECh. 2.8 - Prob. 33ECh. 2.8 - Prob. 34ECh. 2.8 - Prob. 35ECh. 2.8 - Prob. 36ECh. 2.8 - Prob. 37ECh. 2.8 - Prob. 38ECh. 2.8 - Prob. 39ECh. 2.8 - Prob. 40ECh. 2.8 - Prob. 41ECh. 2.8 - Prob. 42ECh. 2.8 - Prob. 43ECh. 2.8 - Prob. 44ECh. 2.8 - Prob. 45ECh. 2.8 - Prob. 46ECh. 2.8 - Prob. 47ECh. 2.8 - Prob. 48ECh. 2.8 - Prob. 49ECh. 2.8 - Prob. 50ECh. 2.8 - Prob. 51ECh. 2.8 - Prob. 52ECh. 2.8 - Prob. 53ECh. 2.8 - Prob. 54ECh. 2.8 - Prob. 55ECh. 2.8 - Prob. 56ECh. 2.8 - Prob. 57ECh. 2.8 - Prob. 58ECh. 2.8 - Prob. 59ECh. 2.8 - Prob. 60ECh. 2.8 - Prob. 61ECh. 2.8 - Prob. 62ECh. 2.8 - Prob. 63ECh. 2.8 - Prob. 64ECh. 2.8 - Prob. 65ECh. 2.8 - Prob. 66ECh. 2.8 - Prob. 67ECh. 2.8 - Prob. 68ECh. 2.8 - Prob. 69ECh. 2.8 - Prob. 70ECh. 2.8 - Prob. 71ECh. 2.8 - Prob. 72ECh. 2.8 - Prob. 75ECh. 2.8 - Prob. 76ECh. 2 - Prob. 1RECh. 2 - Prob. 2RECh. 2 - Prob. 3RECh. 2 - Prob. 4RECh. 2 - Prob. 5RECh. 2 - Prob. 6RECh. 2 - Prob. 7RECh. 2 - Prob. 8RECh. 2 - Prob. 9RECh. 2 - Prob. 10RECh. 2 - Prob. 11RECh. 2 - Prob. 12RECh. 2 - Prob. 13RECh. 2 - Prob. 14RECh. 2 - Prob. 15RECh. 2 - Prob. 16RECh. 2 - Prob. 17RECh. 2 - Prob. 18RECh. 2 - Prob. 19RECh. 2 - Prob. 20RECh. 2 - Prob. 21RECh. 2 - Prob. 22RECh. 2 - Prob. 23RECh. 2 - Prob. 24RECh. 2 - Prob. 25RECh. 2 - Prob. 26RECh. 2 - Prob. 27RECh. 2 - Prob. 28RECh. 2 - Prob. 29RECh. 2 - Prob. 30RECh. 2 - Prob. 31RECh. 2 - Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RECh. 2 - Prob. 56RECh. 2 - Prob. 57RECh. 2 - Prob. 58RECh. 2 - Prob. 59RECh. 2 - Prob. 60RECh. 2 - Prob. 61RECh. 2 - Prob. 62RECh. 2 - Prob. 63RECh. 2 - Prob. 64RECh. 2 - Prob. 65RECh. 2 - Prob. 66RECh. 2 - Prob. 67RECh. 2 - Prob. 68RECh. 2 - Prob. 69RECh. 2 - Prob. 70RECh. 2 - Prob. 71RECh. 2 - Prob. 72RECh. 2 - Prob. 73RECh. 2 - Prob. 74RECh. 2 - Prob. 75RECh. 2 - Prob. 76RECh. 2 - Prob. 77RECh. 2 - Prob. 78RECh. 2 - Prob. 79RECh. 2 - Prob. 80RECh. 2 - Prob. 81RECh. 2 - Prob. 82RECh. 2 - Prob. 83RECh. 2 - Prob. 84RECh. 2 - Prob. 85RECh. 2 - Prob. 86RECh. 2 - Prob. 87RECh. 2 - Prob. 88RECh. 2 - Prob. 89RECh. 2 - Prob. 90RECh. 2 - Prob. 91RECh. 2 - Prob. 92RECh. 2 - Prob. 93RECh. 2 - Prob. 94RECh. 2 - Prob. 95RECh. 2 - Prob. 96RECh. 2 - Prob. 97RECh. 2 - Prob. 98RECh. 2 - Prob. 99RE
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