10th Edition

ISBN: 9780134672090

Author: Demana

Publisher: PEARSON

Concept explainers

The word “unitary” comes from the word “unit”, which means a single and complete entity. In this method, we find the value of a unit product from the given number of products, and then we solve for the other number of products.

Speed, Time, and Distance

Imagine you and 3 of your friends are planning to go to the playground at 6 in the evening. Your house is one mile away from the playground and one of your friends named Jim must start at 5 pm to reach the playground by walk. The other two friends are 3 …

Profit and Loss

The amount earned or lost on the sale of one or more items is referred to as the profit or loss on that item.

Units and Measurements

Measurements and comparisons are the foundation of science and engineering. We, therefore, need rules that tell us how things are measured and compared. For these measurements and comparisons, we perform certain experiments, and we will need the experime…

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Expert Solution & Answer

Chapter 2.1, Problem 59E

Solution

a.

To Determine:

The function Rx that models the total revenue where x represents the number of $0.05 increases in the price of a can.

The total monthly revenue is Rx=5026−x10+x in dollars, where x represents the number of $0.05 increases in the price of a can.

Given:

Monthly sales are 26000 cans when price per can is 50 cents.

For a nickel increase in the price of a can the monthly sales drop by 1000 cans.

Concepts Used:

Determining a linear relationship using rate of change and one point.

Definition of revenue as price times quantity sold.

Conversion factors: $0.01=1 cent , 1 nickel=$0.05 .

Calculations:

Determine the relation between number of cans sold y and the number of $0.05 increases x done on the original price of $0.50 (fifty cents). It is given that a nickel ( $0.05 ) increase in the per can price p decreases the sales by the number of the active rentals by 1000 cans. There is a linear relationship between y and x . Write the given information mathematically:

Change in salesChange in price=−10000.05sales number−original sales numbernumber of $0.05 increases ×0.05=−10000.05y−260000.05x=−10000.05y=26000−1000xy=100026−x

Note that the new price p will be:

p=original price − number of $0.05 increases ×0.05=0.50+0.05x=0.0510+x

Calculate the revenue function.

The total monthly revenue is the product of monthly sales number y and the price 0.0510+x .

Total monthly Revenue = monthly sales number × price per unitRx=y×0.0510+xRx=100026−x×0.0510+xRx=5026−x10+x

Conclusion:

The total monthly revenue is Rx=5026−x10+x in dollars, where x represents the number of $0.05 increases in the price of a can.

b.

To Graph:

The revenue function Rx that shows a maximum for Rx .

Given:

Monthly sales are 26000 cans when price per can is 50 cents.

For a nickel increase in the price of a can the monthly sales drop by 1000 cans.

Known from previous part:

The total monthly revenue is Rx=5026−x10+x in dollars, where x represents the number of $0.05 increases in the price of a can.

Concepts Used:

Graphing a function.

Calculations:

Plot the revenue function Rx=5026−x10+x . Indicate the point of maximum revenue.

Conclusion:

The revenue function Rx is plotted above. The graph shows a maximum for Rx=16200 when x=8 .

c.

To Calculate:

The price which will yield the maximum monthly revenue and the maximum revenue.

$0.90 is the price of each can which will yield the maximum monthly revenue. The corresponding maximum revenue is $16200 .

Given:

Monthly sales are 26000 cans when price per can is 50 cents.

For a nickel increase in the price of a can the monthly sales drop by 1000 cans.

Known from previous parts:

The total monthly revenue is Rx=5026−x10+x in dollars, where x represents the number of $0.05 increases in the price of a can.

The per can price is given by p=0.0510+x .

Maximum for Rx=16200 when x=8 .

Concepts Used:

Substitution.

Calculations:

The maximum revenue Rx=16200 is known to occur when x=8 . The corresponding price per can is :

Per can price when value of x is 8=0.0510+xx=8=0.0510+8=0.0518=0.90

Conclusion:

$0.90 is the price of each can which will yield the maximum monthly revenue. The corresponding maximum revenue is $16200 .

Chapter 2.1, Problem 58E

Chapter 2.1, Problem 60E

Chapter 2 Solutions

PRECALCULUS:GRAPHICAL,...-NASTA ED.

Ch. 2.1 - Prob. 1QR Ch. 2.1 - Prob. 2QR Ch. 2.1 - Prob. 3QR Ch. 2.1 - Prob. 4QR Ch. 2.1 - Prob. 5QR Ch. 2.1 - Prob. 6QR Ch. 2.1 - Prob. 7QR Ch. 2.1 - Prob. 8QR Ch. 2.1 - Prob. 9QR Ch. 2.1 - Prob. 10QR

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - 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Prob. 1QR Ch. 2.5 - Prob. 2QR Ch. 2.5 - Prob. 3QR Ch. 2.5 - Prob. 4QR Ch. 2.5 - Prob. 5QR Ch. 2.5 - Prob. 6QR Ch. 2.5 - Prob. 7QR Ch. 2.5 - Prob. 8QR Ch. 2.5 - Prob. 9QR Ch. 2.5 - Prob. 10QR Ch. 2.5 - Prob. 1E Ch. 2.5 - Prob. 2E Ch. 2.5 - Prob. 3E Ch. 2.5 - Prob. 4E Ch. 2.5 - Prob. 5E Ch. 2.5 - Prob. 6E Ch. 2.5 - Prob. 7E Ch. 2.5 - Prob. 8E Ch. 2.5 - Prob. 9E Ch. 2.5 - Prob. 10E Ch. 2.5 - Prob. 11E Ch. 2.5 - Prob. 12E Ch. 2.5 - Prob. 13E Ch. 2.5 - Prob. 14E Ch. 2.5 - Prob. 15E Ch. 2.5 - Prob. 16E Ch. 2.5 - Prob. 17E Ch. 2.5 - Prob. 18E Ch. 2.5 - Prob. 19E Ch. 2.5 - Prob. 20E Ch. 2.5 - Prob. 21E Ch. 2.5 - Prob. 22E Ch. 2.5 - Prob. 23E Ch. 2.5 - Prob. 24E Ch. 2.5 - Prob. 25E Ch. 2.5 - Prob. 26E Ch. 2.5 - Prob. 27E Ch. 2.5 - Prob. 28E Ch. 2.5 - In Exercises 2732, find all of the zeros and write...Ch. 2.5 - In Exercises 2732, find all of the zeros and write...Ch. 2.5 - Prob. 31E Ch. 2.5 - Prob. 32E Ch. 2.5 - Prob. 33E Ch. 2.5 - Prob. 34E Ch. 2.5 - Prob. 35E Ch. 2.5 - Prob. 36E Ch. 2.5 - Prob. 37E Ch. 2.5 - 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Prob. 21E Ch. 2.7 - Prob. 22E Ch. 2.7 - Prob. 23E Ch. 2.7 - Prob. 24E Ch. 2.7 - Prob. 25E Ch. 2.7 - Prob. 26E Ch. 2.7 - Prob. 27E Ch. 2.7 - Prob. 28E Ch. 2.7 - Prob. 29E Ch. 2.7 - Prob. 30E Ch. 2.7 - Prob. 31E Ch. 2.7 - Prob. 32E Ch. 2.7 - Prob. 33E Ch. 2.7 - Prob. 34E Ch. 2.7 - Prob. 35E Ch. 2.7 - Prob. 36E Ch. 2.7 - Prob. 37E Ch. 2.7 - Prob. 38E Ch. 2.7 - Prob. 39E Ch. 2.7 - Prob. 40E Ch. 2.7 - Prob. 41E Ch. 2.7 - Prob. 42E Ch. 2.7 - Prob. 43E Ch. 2.7 - Prob. 44E Ch. 2.7 - Prob. 45E Ch. 2.7 - Prob. 46E Ch. 2.7 - Prob. 47E Ch. 2.7 - Prob. 48E Ch. 2.7 - Prob. 49E Ch. 2.7 - Prob. 50E Ch. 2.7 - Prob. 51E Ch. 2.7 - Prob. 52E Ch. 2.7 - Prob. 53E Ch. 2.7 - Prob. 54E Ch. 2.7 - Prob. 55E Ch. 2.8 - Prob. 1QR Ch. 2.8 - Prob. 2QR Ch. 2.8 - Prob. 3QR Ch. 2.8 - Prob. 4QR Ch. 2.8 - Prob. 5QR Ch. 2.8 - Prob. 6QR Ch. 2.8 - Prob. 7QR Ch. 2.8 - Prob. 8QR Ch. 2.8 - Prob. 9QR Ch. 2.8 - Prob. 10QR Ch. 2.8 - Prob. 1E Ch. 2.8 - Prob. 2E Ch. 2.8 - Prob. 3E Ch. 2.8 - Prob. 4E Ch. 2.8 - Prob. 5E Ch. 2.8 - Prob. 6E Ch. 2.8 - Prob. 7E Ch. 2.8 - Prob. 8E Ch. 2.8 - Prob. 9E Ch. 2.8 - Prob. 10E Ch. 2.8 - Prob. 11E Ch. 2.8 - Prob. 12E Ch. 2.8 - Prob. 13E Ch. 2.8 - Prob. 14E Ch. 2.8 - Prob. 15E Ch. 2.8 - Prob. 16E Ch. 2.8 - Prob. 17E Ch. 2.8 - Prob. 18E Ch. 2.8 - Prob. 19E Ch. 2.8 - Prob. 20E Ch. 2.8 - Prob. 21E Ch. 2.8 - Prob. 22E Ch. 2.8 - Prob. 23E Ch. 2.8 - Prob. 24E Ch. 2.8 - Prob. 25E Ch. 2.8 - Prob. 26E Ch. 2.8 - Prob. 27E Ch. 2.8 - Prob. 28E Ch. 2.8 - Prob. 29E Ch. 2.8 - Prob. 30E Ch. 2.8 - Prob. 31E Ch. 2.8 - Prob. 32E Ch. 2.8 - Prob. 33E Ch. 2.8 - Prob. 34E Ch. 2.8 - Prob. 35E Ch. 2.8 - Prob. 36E Ch. 2.8 - Prob. 37E Ch. 2.8 - Prob. 38E Ch. 2.8 - Prob. 39E Ch. 2.8 - Prob. 40E Ch. 2.8 - Prob. 41E Ch. 2.8 - Prob. 42E Ch. 2.8 - Prob. 43E Ch. 2.8 - Prob. 44E Ch. 2.8 - Prob. 45E Ch. 2.8 - Prob. 46E Ch. 2.8 - Prob. 47E Ch. 2.8 - Prob. 48E Ch. 2.8 - Prob. 49E Ch. 2.8 - Prob. 50E Ch. 2.8 - Prob. 51E Ch. 2.8 - Prob. 52E Ch. 2.8 - Prob. 53E Ch. 2.8 - Prob. 54E Ch. 2.8 - Prob. 55E Ch. 2.8 - Prob. 56E Ch. 2.8 - Prob. 57E Ch. 2.8 - Prob. 58E Ch. 2.8 - Prob. 59E Ch. 2.8 - Prob. 60E Ch. 2.8 - Prob. 61E Ch. 2.8 - Prob. 62E Ch. 2.8 - Prob. 63E Ch. 2.8 - Prob. 64E Ch. 2.8 - Prob. 65E Ch. 2.8 - Prob. 66E Ch. 2.8 - Prob. 67E Ch. 2.8 - Prob. 68E Ch. 2.8 - Prob. 69E Ch. 2.8 - Prob. 70E Ch. 2.8 - Prob. 71E Ch. 2.8 - Prob. 72E Ch. 2.8 - Prob. 75E Ch. 2.8 - Prob. 76E Ch. 2 - Prob. 1RE Ch. 2 - Prob. 2RE Ch. 2 - Prob. 3RE Ch. 2 - Prob. 4RE Ch. 2 - Prob. 5RE Ch. 2 - Prob. 6RE Ch. 2 - Prob. 7RE Ch. 2 - Prob. 8RE Ch. 2 - Prob. 9RE Ch. 2 - Prob. 10RE Ch. 2 - Prob. 11RE Ch. 2 - Prob. 12RE Ch. 2 - Prob. 13RE Ch. 2 - Prob. 14RE Ch. 2 - Prob. 15RE Ch. 2 - Prob. 16RE Ch. 2 - Prob. 17RE Ch. 2 - Prob. 18RE Ch. 2 - Prob. 19RE Ch. 2 - Prob. 20RE Ch. 2 - Prob. 21RE Ch. 2 - Prob. 22RE Ch. 2 - Prob. 23RE Ch. 2 - Prob. 24RE Ch. 2 - Prob. 25RE Ch. 2 - Prob. 26RE Ch. 2 - Prob. 27RE Ch. 2 - Prob. 28RE Ch. 2 - Prob. 29RE Ch. 2 - Prob. 30RE Ch. 2 - Prob. 31RE Ch. 2 - Prob. 32RE Ch. 2 - Prob. 33RE Ch. 2 - Prob. 34RE Ch. 2 - Prob. 35RE Ch. 2 - Prob. 36RE Ch. 2 - Prob. 37RE Ch. 2 - Prob. 38RE Ch. 2 - Prob. 39RE Ch. 2 - Prob. 40RE Ch. 2 - Prob. 41RE Ch. 2 - Prob. 42RE Ch. 2 - Prob. 43RE Ch. 2 - Prob. 44RE Ch. 2 - Prob. 45RE Ch. 2 - Prob. 46RE Ch. 2 - Prob. 47RE Ch. 2 - Prob. 48RE Ch. 2 - Prob. 49RE Ch. 2 - Prob. 50RE Ch. 2 - Prob. 51RE Ch. 2 - Prob. 52RE Ch. 2 - Prob. 53RE Ch. 2 - Prob. 54RE Ch. 2 - Prob. 55RE Ch. 2 - Prob. 56RE Ch. 2 - Prob. 57RE Ch. 2 - Prob. 58RE Ch. 2 - Prob. 59RE Ch. 2 - Prob. 60RE Ch. 2 - Prob. 61RE Ch. 2 - Prob. 62RE Ch. 2 - Prob. 63RE Ch. 2 - Prob. 64RE Ch. 2 - Prob. 65RE Ch. 2 - Prob. 66RE Ch. 2 - Prob. 67RE Ch. 2 - Prob. 68RE Ch. 2 - Prob. 69RE Ch. 2 - Prob. 70RE Ch. 2 - Prob. 71RE Ch. 2 - Prob. 72RE Ch. 2 - Prob. 73RE Ch. 2 - Prob. 74RE Ch. 2 - Prob. 75RE Ch. 2 - Prob. 76RE Ch. 2 - Prob. 77RE Ch. 2 - Prob. 78RE Ch. 2 - Prob. 79RE Ch. 2 - Prob. 80RE Ch. 2 - Prob. 81RE Ch. 2 - Prob. 82RE Ch. 2 - Prob. 83RE Ch. 2 - Prob. 84RE Ch. 2 - Prob. 85RE Ch. 2 - Prob. 86RE Ch. 2 - Prob. 87RE Ch. 2 - Prob. 88RE Ch. 2 - Prob. 89RE Ch. 2 - Prob. 90RE Ch. 2 - Prob. 91RE Ch. 2 - Prob. 92RE Ch. 2 - Prob. 93RE Ch. 2 - Prob. 94RE Ch. 2 - Prob. 95RE Ch. 2 - Prob. 96RE Ch. 2 - Prob. 97RE Ch. 2 - Prob. 98RE Ch. 2 - Prob. 99RE

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