Chapter 23, Problem 74A

Interpretation Introduction

Interpretation:

The mass of 0.886 L sample of palmitic acid at $62°\text{C}$ temperature should be calculated.

Concept introduction:

Density is defined as the ratio of mass to the volume.

The mathematical expression is:

$\mathrm{Density}=\frac{Mass}{Volume}$

Answer to Problem 74A

Mass of palmitic acid at $62°\text{C}$ is $756\text{ g}$.

Explanation of Solution

Density of Palmitic acid = $0.853\text{ g/mL}$

Temperature = $62°\text{C}$

Volume = 0.886 L

Convert the volume in L to mL

Since, 1 L to 1000 mL

Thus, volume in mL = $0.886\text{ L}\times \frac{1000\text{ mL}}{1\text{ L}}=886\text{ mL}$

$\mathrm{Density}=\frac{Mass}{Volume}$

Put the values,

$0.853\text{ g/mL}=\frac{Mass}{886\text{ mL}}$

Mass of palmitic acid = $0.853\text{ g/mL}\times \text{886 mL}$

= $755.758\text{ g}$

Thus, mass of palmitic acid at $62°\text{C}$ is $756\text{ g}$.