Interpretation: To distinguish the polarity of the carbon-carbon double bond and a carbon-oxygen double bond.
Concept Introduction: The polarity of the atoms that are bonded together will depend on the electronegativity of the two atoms. If one of the atoms is more electronegative than the other atom electrons of the bond will move towards the atom with more electronegativity and will result in partial negative and positive charge. If both the atoms have similar electronegativity then there is no polarity as there is no movement of electrons and hence no charge will be developed.
Answer to Problem 49A
In a carbon-carbon double bond, the electronegativity of both carbons is the same therefore, there is no polarity. In the carbon-oxygen double bond, the electronegativity of oxygen is more than that of the carbon therefore, the bond is polar.
Explanation of Solution
When a carbon-carbon double bond is considered the electronegativity of both carbons are same. Due to this, there will be no charge distribution on both carbons. Therefore, the carbon-carbon bond will be non-polar. Whereas, in the case of the carbon-oxygen double bond oxygen is more electronegative than carbon. Due to this, there is a charge developed on both carbon and oxygen. The oxygen will gain a partial negative charge and the carbon will gain a partial positive charge that results in polarity.
If one of the atoms is more electronegative then that atom will gain the electron and become electron-rich and gains the partial negative charge. Since the other atom is less electronegative it will lose electrons and gain partial positive charge.
Chapter 23 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
- Draw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.arrow_forward✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cearrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Don't used hand raiting and don't used Ai solutionarrow_forwardDetermine whether the following reaction is an example of a nucleophilic substitution reaction: Br OH HO 2 -- Molecule A Molecule B + Br 义 ollo 18 Is this a nucleophilic substitution reaction? If this is a nucleophilic substitution reaction, answer the remaining questions in this table. Which of the reactants is referred to as the nucleophile in this reaction? Which of the reactants is referred to as the organic substrate in this reaction? Use a ŏ + symbol to label the electrophilic carbon that is attacked during the substitution. Highlight the leaving group on the appropriate reactant. ◇ Yes O No O Molecule A Molecule B Molecule A Molecule B टेarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Show work..don't give Ai generated solutionarrow_forwardPheromone G of the maize stalk borer, chilo partelus, can be synthesized based on the partial scheme shown below. Complete the scheme by identifying the structures of the intermediate compounds A, B, C, D, E, F and pheromone G. Indicate stereochemistry where relevantarrow_forwardQ8: Draw the resonance structures for the following molecule. Show the curved arrows (how you derive each resonance structure). Circle the major resonance contributor. одarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY