COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 23, Problem 28QAP
To determine
The minimum diameter of the aperture of a space telescope that would be required to resolve Proxima b from its star Proxima Centauri.
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Two sources S, and S, emitting light of wavelength
- 2
ст араrt.
600 nm are placed a distance 1.0 x 10
detector can be moved on the line S,P which is
perpendicular to S,S,. (a) What would be the minimum
and maximum path difference at the detector as it is
moved along the line S,P? (b) Locate the position of the
farthest minimum detected.
A
2•
•48 A high-powered laser beam (A = 600 nm) with a beam diam-
eter of 12 cm is aimed at the Moon, 3.8 x 10° km distant. The beam
spreads only because of diffraction. The angular location of the
edge of the central diffraction disk (see Eq. 36-12) is given by
1.22A
sin 0
where d is the diameter of the beam aperture. What is the diameter
of the central diffraction disk on the Moon's surface?
•1 In Fig. 35-31, a light wave along
ray r, reflects once from a mirror and
a light wave along ray r, reflects twice
from that same mirror and once from
a tiny mirror at distance L from the
bigger mirror. (Neglect the slight tilt Figure 35-31 Problems 1 and 2.
of the rays.) The waves have wave-
length 620 nm and are initially in phase. (a) What is the smallest value
of L that puts the final light waves exactly out of phase? (b) With the
tiny mirror initially at that value of L, how far must it be moved away
from the bigger mirror to again put the final waves out of phase?
Chapter 23 Solutions
COLLEGE PHYSICS
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- Radio telescopes are telescopes used for the detection of radio emission from space. Because radio waves have much longer wavelengths than visible light, the diameter of a radio telescope must be very large to provide good resolution. For example, the radio telescope in Penticton, BC in Canada, has a diameter of 26 m and can be operated at frequencies as high as 6.6 GHz. (a) What is the wavelength corresponding to this frequency? (b) What is the angular separation of two radio sources that can be resolved by this telescope? (c) Compare the telescope’s resolution with the angular size of the moon.arrow_forwardWhen dots are placed on a page from a laser printer, they must be close enough so that you do not see the individual dots of ink. To do this, the separation of the dots must be less than Raleigh’s criterion. Take the pupil of the eye to be 3.0 mm and the distance from the paper to the eye of 35 cm; find the minimum separation of two dots such that they cannot be resolved. How many dots per inch (dpi) does this correspond to?arrow_forwardA telescope can be used to enlarge the diameter of a laser beam and limit diffraction spreading. The laser beam is sent through the telescope in opposite the normal direction and can then be projected onto a satellite or the moon. (a) If this is done with the Mount Wilson telescope, producing a 2.54-m-diameter beam of 633-nm light, what is the minimum angular spread of the beam? (b) Neglecting atmospheric effects, what is the size of the spot this beam would make on the moon, assuming a lunar distance of 3.84108 m?arrow_forward
- How far apart must two objects be on the moon to be distinguishable by eye if only the diffraction effects of the eye’s pupil limit the resolution? Assume 550 nm for the wavelength of light, the pupil diameter 5.0 mm, and 400,000 km for the distance to the moon.arrow_forwardA Michelson interferometer has two equal arms. A mercury light of wavelength 546 nm is used for the interferometer and stable fringes are found. One of the arms is moved by 1.5 m. How many fringes will cross the observing field?arrow_forwardAssuming the angular resolution found for the Hubble Telescope in Example 27.5, what is the smallest detail that could be observed on the Moon?arrow_forward
- In a thermally stabilized lab, a Michelson interferometer is used to monitor the temperature to ensure it stays constant. The movable mirror is mounted on the end of a 1.00-m-long aluminum rod, held fixed at the other end. The light source is a He Ne laser, =632.8 nm . The resolution of this apparatus corresponds to the temperature difference when a change of just one fringe is observed. What is this temperature difference?arrow_forward•10 GO Manufacturers of wire (and other objects of small dimension) sometimes use a laser to continually monitor the thickness of the product. The wire intercepts the laser beam, pro- ducing a diffraction pattern like that of a single slit of the same width as the wire diameter (Fig. 36-37). Suppose a helium-neon laser, of wavelength 632.8 nm, illuminates a wire, and the diffrac- tion pattern appears on a screen at distance L = 2.60 m. If the desired wire diameter is 1.37 mm, what is the observed distance between the two tenth-order minima (one on each side of the central maximum)? Wire He-Ne laser L Figure 36-37 Problem 10. Wire-making machinearrow_forwardDetermine the maximum distance at which an observer can still distinguish two small bright sources 15 mm apart emitting the light of 432 nm, given that the eye pupil size is around 4.0 mm. Give your answer in SI unitarrow_forward
- Q: An optical fiber with core radius = 62µm, n, = 1.49, n; = 1.45. If the time delay between the longest and shortest paths = 68.506nsec. a) What is the fiber type? b) Calculate the fiber length. c) Calculate the critical angle. « d) Calculate the numerical aperture. e) In this fiber, what is the main reason of dispersion? What is the effect of dispersion on this optical communication system? What do you suggest to do to reduce the dispersion effect?arrow_forward4) The distance between the first and fifth minima of a single-slit diffraction pattern is 0.35 mm with the screen 40 cm away from the slit, when light of wavelength 550 nm is used.arrow_forwardDetermine the angular deflection of wavelength 656 nm to the second order.arrow_forward
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