
Concept explainers
(A)
The

Answer to Problem 36QAP
The speed of light in ice is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of ice
Let the speed of light in ice be
Formula used:
Refractive Index of ice
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in ice is
(B)
The speed of light in acetone.

Answer to Problem 36QAP
The speed of light in acetone is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of acetone
Let the speed of light in acetone be
Formula used:
Refractive Index of acetone
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in acetone is
(C)
The speed of light in Plexiglas.

Answer to Problem 36QAP
The speed of light in Plexiglas is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of Plexiglas
Let the speed of light in Plexiglas be
Formula used:
Refractive Index of Plexiglas
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in Plexiglas is
(d)
The speed of light in Sodium Chloride.

Answer to Problem 36QAP
The speed of light in Sodium Chloride is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of Sodium Chloride
Let the speed of light in Sodium Chloride be
Formula used:
Refractive Index of Sodium Chloride
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in Sodium Chloride is
(E)
The speed of light in Sapphire.

Answer to Problem 36QAP
The speed of light in Sapphire is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of Sapphire
Let the speed of light in Sapphire be
Formula used:
Refractive Index of Sapphire
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in Sapphire is
(F)
The speed of light in diamond.

Answer to Problem 36QAP
The speed of light in diamond is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of diamond
Let the speed of light in diamond be
Formula used:
Refractive Index of diamond
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in diamond is
(G)
The speed of light in water.

Answer to Problem 36QAP
The speed of light in water is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of water
Let the speed of light in water be
Formula used:
Refractive Index of water
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in water is
(H)
The speed of light in crow glass.

Answer to Problem 36QAP
The speed of light in crow glass is
Explanation of Solution
Given:
Speed of light in vacuum
Refractive Index of crow glass
Let the speed of light in crow glass be
Formula used:
Refractive Index of crow glass
Here, all alphabets are in their usual meanings.
Calculation:
Using the above formula,
Conclusion:
Hence, the speed of light in crow glass is
Want to see more full solutions like this?
Chapter 23 Solutions
COLLEGE PHYSICS
- (a) For a spherical capacitor with inner radius a and outer radius b, we have the following for the capacitance. ab C = k₂(b- a) 0.0695 m 0.145 m (8.99 × 10º N · m²/c²)( [0.145 m- 0.0695 m × 10-11 F = PF IIarrow_forwardA pendulum bob A (0.5 kg) is given an initialspeed of vA = 4 m/s when the chord ishorizontal. It then hits a stationary block B (1kg) which then slides to a maximum distanced before it stops. Determine the value of d.The coefficient of static friction between theblock and the plane is μk = 0.2. The coefficientof restitution between A and B is e = 0.8.Ans: d=1.0034 marrow_forwardFigure 29-43 Problem 12. ••13 In Fig. 29-44, point P₁ is at distance R = 13.1 cm on the perpendicular bisector of a straight wire of length L = 18.0 cm carrying current i = 58.2 mA. (Note that the wire is not long.) What is the magnitude of the magnetic field at P₁ due to i? P2° R R Larrow_forward
- Checkpoint 1 The figure shows the current i in a single-loop circuit with a battery B and a resistance R (and wires of neg- ligible resistance). (a) Should the emf arrow at B be drawn pointing leftward or rightward? At points a, B C R b, and c, rank (b) the magnitude of the current, (c) the electric potential, and (d) the electric potential energy of the charge carriers, greatest first.arrow_forwardPls help ASAParrow_forwardPls help asaparrow_forward
- Pls help asaparrow_forward3. If the force of gravity stopped acting on the planets in our solar system, what would happen? a) They would spiral slowly towards the sun. b) They would continue in straight lines tangent to their orbits. c) They would continue to orbit the sun. d) They would fly straight away from the sun. e) They would spiral slowly away from the sun. 4. 1 The free-body diagram of a wagon being pulled along a horizontal surface is best represented by A F N B C 0 Ꭰ FN E a) A b) B c) C app app The app 10 app d) e) ס ח D E 10 apparrow_forwardPls help ASAParrow_forward
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning





