COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 23, Problem 40QAP
To determine

(a)

Refractive Index of second medium n2

Expert Solution
Check Mark

Answer to Problem 40QAP

Refractive Index of second medium is n2=1.41

Explanation of Solution

Given:

COLLEGE PHYSICS, Chapter 23, Problem 40QAP , additional homework tip  1

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

  or,n2=n1sinθ1sinθ2or,n2=1.0×sin20°sin14°or,n2=( 1.0×0.342 0.242)or,n2=1.41

Hence, Refractive Index of second medium is n2=1.41

Conclusion:

Thus, Refractive Index of second medium is n2=1.41

To determine

(b)

Refractive Index of second medium n2

Expert Solution
Check Mark

Answer to Problem 40QAP

Refractive Index of second medium is n2=1.46

Explanation of Solution

Given:

COLLEGE PHYSICS, Chapter 23, Problem 40QAP , additional homework tip  2

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

  or,n2=n1sinθ1sinθ2or,n2=1.0×sin30°sin20°or,n2=1.46

Hence, Refractive Index of second medium is n2=1.46

Conclusion:

Thus, refractive index of second medium is n2=1.46

To determine

(c)

Refractive Index of first medium n1

Expert Solution
Check Mark

Answer to Problem 40QAP

Refractive Index of first medium is n1=0.843

Explanation of Solution

Given:

COLLEGE PHYSICS, Chapter 23, Problem 40QAP , additional homework tip  3

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

  or,n1=n2sinθ2sinθ1or,n1=1.50×sin10°sin18°or,n1=0.843

Hence, Refractive Index of first medium is n1=0.843

Conclusion:

Thus, Refractive Index of first medium is n1=0.843

To determine

(d)

Refractive Index of first medium n1

Expert Solution
Check Mark

Answer to Problem 40QAP

Refractive Index of first medium is n1=0.843

Explanation of Solution

Given:

COLLEGE PHYSICS, Chapter 23, Problem 40QAP , additional homework tip  4

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinθ1=n2sinθ2

  or,n1=n2sinθ2sinθ1or,n1=1.33×sin25°sin34.1°or,n1=1.001

Hence, Refractive Index of first medium is n1=1.001

Conclusion:

Thus, Refractive Index of first medium is n1=1.001

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Chapter 23 Solutions

COLLEGE PHYSICS

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