COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 23, Problem 24QAP
To determine
The fraction of the incident unpolarized light that passes through two linear polarizing filters placed one behind the other with their transmission directions at an angle 45o.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
•4 In Fig. 35-32a, a beam of light in material 1 is incident on a
boundary at an angle of 30°. The extent to which the light is ben
due to refraction depends, in part, on the index of refraction n, o
material 2. Figure 35-32b gives the angle of refraction Oz versus n
for a range of possible n2 values, from n, = 1.30 to n, = 1.90. Wha
is the speed of light in material 1?
в,
40°
300!
30°
в,
20°
по
(a)
(b)
20) A be am of
light of
infens idy
un polarized
Two polarizing
lo s incident
sheefs
The
sheets
on
placed
to p
of
The infensiy
are
on
each
other.
of the light emerging
trom
the
sheets
is lo/4.
what is
the
ange
the axes of
be tween
polariza tion
of
those
polarizes ?
a)
ws
b) os
(i12)
C) sin-'(v2/2)
d) cos
() sin - (ilu5)
+) sin-! (Il2)
9) sin(T3/2)
h) cos ! (r312)
•8 In Fig. 35-33, two light pulses
are sent through layers of plastic
Pulse
п
п
with thicknesses of either L or 2L
as shown and indexes of refraction
Pulse
n = 1.55, nz = 1.70, nz = 1.60, n4 = i
1.45, ng = 1.59, ng = 1.65, and n, =
1.50. (a) Which pulse travels
through the plastic in less time?
(b) What multiple of Lic gives the difference in the traversal
times of the pulses?
%3D
Figure 35-33 Problem 8.
Chapter 23 Solutions
COLLEGE PHYSICS
Ch. 23 - Prob. 1QAPCh. 23 - Prob. 2QAPCh. 23 - Prob. 3QAPCh. 23 - Prob. 4QAPCh. 23 - Prob. 5QAPCh. 23 - Prob. 6QAPCh. 23 - Prob. 7QAPCh. 23 - Prob. 8QAPCh. 23 - Prob. 9QAPCh. 23 - Prob. 10QAP
Ch. 23 - Prob. 11QAPCh. 23 - Prob. 12QAPCh. 23 - Prob. 13QAPCh. 23 - Prob. 14QAPCh. 23 - Prob. 15QAPCh. 23 - Prob. 16QAPCh. 23 - Prob. 17QAPCh. 23 - Prob. 18QAPCh. 23 - Prob. 19QAPCh. 23 - Prob. 20QAPCh. 23 - Prob. 21QAPCh. 23 - Prob. 22QAPCh. 23 - Prob. 23QAPCh. 23 - Prob. 24QAPCh. 23 - Prob. 25QAPCh. 23 - Prob. 26QAPCh. 23 - Prob. 27QAPCh. 23 - Prob. 28QAPCh. 23 - Prob. 29QAPCh. 23 - Prob. 30QAPCh. 23 - Prob. 31QAPCh. 23 - Prob. 32QAPCh. 23 - Prob. 33QAPCh. 23 - Prob. 34QAPCh. 23 - Prob. 35QAPCh. 23 - Prob. 36QAPCh. 23 - Prob. 37QAPCh. 23 - Prob. 38QAPCh. 23 - Prob. 39QAPCh. 23 - Prob. 40QAPCh. 23 - Prob. 41QAPCh. 23 - Prob. 42QAPCh. 23 - Prob. 43QAPCh. 23 - Prob. 44QAPCh. 23 - Prob. 45QAPCh. 23 - Prob. 46QAPCh. 23 - Prob. 47QAPCh. 23 - Prob. 48QAPCh. 23 - Prob. 49QAPCh. 23 - Prob. 50QAPCh. 23 - Prob. 51QAPCh. 23 - Prob. 52QAPCh. 23 - Prob. 53QAPCh. 23 - Prob. 54QAPCh. 23 - Prob. 55QAPCh. 23 - Prob. 56QAPCh. 23 - Prob. 57QAPCh. 23 - Prob. 58QAPCh. 23 - Prob. 59QAPCh. 23 - Prob. 60QAPCh. 23 - Prob. 61QAPCh. 23 - Prob. 62QAPCh. 23 - Prob. 63QAPCh. 23 - Prob. 64QAPCh. 23 - Prob. 65QAPCh. 23 - Prob. 66QAPCh. 23 - Prob. 67QAPCh. 23 - Prob. 68QAPCh. 23 - Prob. 69QAPCh. 23 - Prob. 70QAPCh. 23 - Prob. 71QAPCh. 23 - Prob. 72QAPCh. 23 - Prob. 73QAPCh. 23 - Prob. 74QAPCh. 23 - Prob. 75QAPCh. 23 - Prob. 76QAPCh. 23 - Prob. 77QAPCh. 23 - Prob. 78QAPCh. 23 - Prob. 79QAPCh. 23 - Prob. 80QAPCh. 23 - Prob. 81QAPCh. 23 - Prob. 82QAPCh. 23 - Prob. 83QAPCh. 23 - Prob. 84QAPCh. 23 - Prob. 85QAPCh. 23 - Prob. 86QAPCh. 23 - Prob. 87QAPCh. 23 - Prob. 88QAPCh. 23 - Prob. 89QAPCh. 23 - Prob. 90QAPCh. 23 - Prob. 91QAPCh. 23 - Prob. 92QAPCh. 23 - Prob. 93QAPCh. 23 - Prob. 94QAPCh. 23 - Prob. 95QAPCh. 23 - Prob. 96QAPCh. 23 - Prob. 97QAPCh. 23 - Prob. 98QAPCh. 23 - Prob. 99QAPCh. 23 - Prob. 100QAPCh. 23 - Prob. 101QAPCh. 23 - Prob. 102QAPCh. 23 - Prob. 103QAPCh. 23 - Prob. 104QAPCh. 23 - Prob. 105QAPCh. 23 - Prob. 106QAPCh. 23 - Prob. 107QAPCh. 23 - Prob. 108QAPCh. 23 - Prob. 109QAPCh. 23 - Prob. 110QAPCh. 23 - Prob. 111QAPCh. 23 - Prob. 112QAPCh. 23 - Prob. 113QAPCh. 23 - Prob. 114QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Figure 25.54 shows a ray of light passing from one medium into a second and then a third. Show that 3 is the same as it would be if the second medium were not present (provided total internal reflection does not occur). Figure 25.54 A ray of light passes from one medium to a third by traveling through a second. The final direction is the same as if the second medium were not present, but the ray is displaced by x (Shawn exaggerated).arrow_forwardYou are told not to shoot until you see the whites of their eyes. If the eyes are separated by 6.5 cm and the diameter of your pupil is 5.0 mm, at what distance can you resolve the two eyes using light of wavelength 555 nm?arrow_forwardAt the end of Example 17, it was stated that the intensity of polarized light is reduced to 90.0% of its original value by passing through a polarizing filter with its axis at an angle of 18.4° to the direction of polarization. Verify this statement.arrow_forward
- Components of some computers communicate with each other through optical fibers having an index of refraction n = 1.55. What time in nanoseconds is required for a signal to travel 0.200 m through such a fiber?arrow_forwardProve that, if I is the intensity of light transmitted by two polarizing filters with axes at an angle and I is the intensity when the axes are at an angle 90.0, then I+I=I0, the original intensity. (Hint: Use the trigonometric identities cos(90.0)=sin and cos2+sin2=1 .)arrow_forwardGive an example of a wave characteristic of light that is easily observed outside the laboratory.arrow_forward
- Referring to the electric room heater considered in the first example in this section, calculate the intensity of IR radiation in W/m2 projected by the concave mirror on a person 3.00 m away. Assume that the healing element radiates 1500 W and has an area of 100 cm2, and that half of the radiated power is reflected and focused by the mirror.arrow_forwardShow that if you have three polarizing filters, with the second at an angle of 45° to the first and the third at an angle of 90.0° to the first, the intensity of light passed by the first will be reduced to 25.0% of its value. (This is in contrast to having only the first and third, which reduces the intensity to zero, so that placing the second between them increases the intensity of the transmitted light.)arrow_forwardOn the Moon’s surface, lunar astronauts placed a comet reflector, off which a laser beam Is periodically reflected. The distance to the Moon is calculated from the round-trip time. What percent correction Is needed to account for the delay in time due to the slowing of light in Earth’s atmosphere? Assume the distance to the Moon is precisely 3.84108 m and Earth’s atmosphere (which varies in density with altitude) is equivalent to a layer 30.0 km thick with a constant index of refraction n= l.000293.arrow_forward
- Check Your Understanding Although we did no specify the direction in Example 1.7, let’s say the polarizing filter was rotated clockwise by 71.6° to reduce the light intensity by 90.0%. What would be the intensity reduction if the polarizing filter were rotated counterclockwise by 71.6°’arrow_forwardIf b is Brewster's angle for light reflected from the top of an interface between two substances, and b is Brewster's angle for light reflected from below, prove that b+b=90.0.arrow_forwardWhile using a Michelson interferometer (shown in Fig. 37.13), you see a dark circle at the center of the interference pattern, (i) As you gradually move the light source toward the central mirror M0, through a distance /2, what do you see? (a) There is no change in the pattern, (b) The dark circle changes into a bright circle. (c) The dark circle changes into a bright circle and then back into a dark circle. (d) The dark circle changes into a bright circle, then into a dark circle, and then into a bright circle. (ii) As you gradually move the moving mirror toward the central mirror M0, through a distance /2, what tit) you see? Choose from the same possibilities.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStaxCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Polarization of Light: circularly polarized, linearly polarized, unpolarized light.; Author: Physics Videos by Eugene Khutoryansky;https://www.youtube.com/watch?v=8YkfEft4p-w;License: Standard YouTube License, CC-BY