COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 23, Problem 42QAP
To determine

(a)

Critical angle ic

Expert Solution
Check Mark

Answer to Problem 42QAP

Critical angle is ic=41.8°

Explanation of Solution

Given:

Angle of refraction r=90°

Let the critical angle be ic

Refractive index of plastic n1=1.50

Refractive index of air n2=1.00

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

  or,sinic=n2sinrn1or,ic=sin1( n2 sinr n1 )or,ic=sin1( 1.0×sin90° 1.50)or,ic=41.8°

Hence, the critical angle is ic=41.8°

Conclusion:

Thus, the critical angle is ic=41.8°

To determine

(b)

Critical angle ic

Expert Solution
Check Mark

Answer to Problem 42QAP

Critical angle is ic=48.8°

Explanation of Solution

Given:

Angle of refraction r=90°

Let the critical angle be ic

Refractive index of water n1=1.33

Refractive index of air n2=1.00

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

  or,sinic=n2sinrn1or,ic=sin1( n2 sinr n1 )or,ic=sin1( 1.0×sin90° 1.33)or,ic=48.8°

Hence, the critical angle is ic=48.8°

Conclusion:

Thus, the critical angle is ic=48.8°

To determine

(c)

Critical angle ic

Expert Solution
Check Mark

Answer to Problem 42QAP

Critical angle is ic=58.5°

Explanation of Solution

Given:

Angle of refraction r=90°

Let the critical angle be ic

Refractive index of glass n1=1.56

Refractive index of water n2=1.33

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

  or,sinic=n2sinrn1or,ic=sin1( n2 sinr n1 )or,ic=sin1( 1.33×sin90° 1.56)or,ic=58.5°

Hence, the critical angle is ic=58.5°

Conclusion:

Thus, the critical angle is ic=58.5°

To determine

(d)

Critical angle ic

Expert Solution
Check Mark

Answer to Problem 42QAP

Critical angle is ic=40.2°

Explanation of Solution

Given:

NOTE: in the given question, light goes from air to glass which is impossible at critical angle. It should be from glass to air.

Angle of refraction r=90°

Let the critical angle be ic

Refractive index of air n2=1.00

Refractive index of glass n1=1.55

Formula used:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

Here, all alphabets are in their usual meanings.

Calculation:

Apply the refraction condition from Snell's Law,

  n1sinic=n2sinr

  or,sinic=n2sinrn1or,ic=sin1( n2 sinr n1 )or,ic=sin1( 1.00×sin90° 1.55)or,ic=40.2°

Hence, the critical angle is ic=40.2°

Conclusion:

Thus, the critical angle is ic=40.2°

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Chapter 23 Solutions

COLLEGE PHYSICS

Ch. 23 - Prob. 11QAPCh. 23 - Prob. 12QAPCh. 23 - Prob. 13QAPCh. 23 - Prob. 14QAPCh. 23 - Prob. 15QAPCh. 23 - Prob. 16QAPCh. 23 - Prob. 17QAPCh. 23 - Prob. 18QAPCh. 23 - Prob. 19QAPCh. 23 - Prob. 20QAPCh. 23 - Prob. 21QAPCh. 23 - Prob. 22QAPCh. 23 - Prob. 23QAPCh. 23 - Prob. 24QAPCh. 23 - Prob. 25QAPCh. 23 - Prob. 26QAPCh. 23 - Prob. 27QAPCh. 23 - Prob. 28QAPCh. 23 - Prob. 29QAPCh. 23 - Prob. 30QAPCh. 23 - Prob. 31QAPCh. 23 - Prob. 32QAPCh. 23 - Prob. 33QAPCh. 23 - Prob. 34QAPCh. 23 - Prob. 35QAPCh. 23 - Prob. 36QAPCh. 23 - Prob. 37QAPCh. 23 - Prob. 38QAPCh. 23 - Prob. 39QAPCh. 23 - Prob. 40QAPCh. 23 - Prob. 41QAPCh. 23 - Prob. 42QAPCh. 23 - Prob. 43QAPCh. 23 - Prob. 44QAPCh. 23 - Prob. 45QAPCh. 23 - Prob. 46QAPCh. 23 - Prob. 47QAPCh. 23 - Prob. 48QAPCh. 23 - Prob. 49QAPCh. 23 - Prob. 50QAPCh. 23 - Prob. 51QAPCh. 23 - Prob. 52QAPCh. 23 - Prob. 53QAPCh. 23 - Prob. 54QAPCh. 23 - Prob. 55QAPCh. 23 - Prob. 56QAPCh. 23 - Prob. 57QAPCh. 23 - Prob. 58QAPCh. 23 - Prob. 59QAPCh. 23 - Prob. 60QAPCh. 23 - Prob. 61QAPCh. 23 - Prob. 62QAPCh. 23 - Prob. 63QAPCh. 23 - Prob. 64QAPCh. 23 - Prob. 65QAPCh. 23 - Prob. 66QAPCh. 23 - Prob. 67QAPCh. 23 - Prob. 68QAPCh. 23 - Prob. 69QAPCh. 23 - Prob. 70QAPCh. 23 - Prob. 71QAPCh. 23 - Prob. 72QAPCh. 23 - Prob. 73QAPCh. 23 - Prob. 74QAPCh. 23 - Prob. 75QAPCh. 23 - Prob. 76QAPCh. 23 - Prob. 77QAPCh. 23 - Prob. 78QAPCh. 23 - Prob. 79QAPCh. 23 - Prob. 80QAPCh. 23 - Prob. 81QAPCh. 23 - Prob. 82QAPCh. 23 - Prob. 83QAPCh. 23 - Prob. 84QAPCh. 23 - Prob. 85QAPCh. 23 - Prob. 86QAPCh. 23 - Prob. 87QAPCh. 23 - Prob. 88QAPCh. 23 - Prob. 89QAPCh. 23 - Prob. 90QAPCh. 23 - Prob. 91QAPCh. 23 - Prob. 92QAPCh. 23 - Prob. 93QAPCh. 23 - Prob. 94QAPCh. 23 - Prob. 95QAPCh. 23 - Prob. 96QAPCh. 23 - Prob. 97QAPCh. 23 - Prob. 98QAPCh. 23 - Prob. 99QAPCh. 23 - Prob. 100QAPCh. 23 - Prob. 101QAPCh. 23 - Prob. 102QAPCh. 23 - Prob. 103QAPCh. 23 - Prob. 104QAPCh. 23 - Prob. 105QAPCh. 23 - Prob. 106QAPCh. 23 - Prob. 107QAPCh. 23 - Prob. 108QAPCh. 23 - Prob. 109QAPCh. 23 - Prob. 110QAPCh. 23 - Prob. 111QAPCh. 23 - Prob. 112QAPCh. 23 - Prob. 113QAPCh. 23 - Prob. 114QAP
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Laws of Refraction of Light | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=4l2thi5_84o;License: Standard YouTube License, CC-BY