COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 23, Problem 50QAP
To determine
(a)
The angle at which the beam of light emerges from the opposite face.
To determine
(b)
The distance along the right face of the prism between the points where red light and violet light emerges back into air.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
•1 In Fig. 35-31, a light wave along
ray r, reflects once from a mirror and
a light wave along ray r, reflects twice
from that same mirror and once from
a tiny mirror at distance L from the
bigger mirror. (Neglect the slight tilt Figure 35-31 Problems 1 and 2.
of the rays.) The waves have wave-
length 620 nm and are initially in phase. (a) What is the smallest value
of L that puts the final light waves exactly out of phase? (b) With the
tiny mirror initially at that value of L, how far must it be moved away
from the bigger mirror to again put the final waves out of phase?
•45 When the rectangular metal
tank in Fig. 33-46 is filled to the top
with an unknown liquid, observer o-
O, with eyes level with the top of
the tank, can just see corner E. A
ray that refracts toward O at the top
surface of the liquid is shown. If
D = 85.0 cm and L = 1.10 m, what
-Normal to
liquid surface
is the index of refraction of the
liquid?
-L-
•34 G In Fig. 33-41, a beam of unpolarized
light, with intensity 43 W/m?, is sent into a
system of two polarizing sheets with
polarizing directions at angles 6,= 70° and
02 = 90° to the y axis. What is the intensity of
-x-
Ө.
the light transmitted by the system?
Chapter 23 Solutions
COLLEGE PHYSICS
Ch. 23 - Prob. 1QAPCh. 23 - Prob. 2QAPCh. 23 - Prob. 3QAPCh. 23 - Prob. 4QAPCh. 23 - Prob. 5QAPCh. 23 - Prob. 6QAPCh. 23 - Prob. 7QAPCh. 23 - Prob. 8QAPCh. 23 - Prob. 9QAPCh. 23 - Prob. 10QAP
Ch. 23 - Prob. 11QAPCh. 23 - Prob. 12QAPCh. 23 - Prob. 13QAPCh. 23 - Prob. 14QAPCh. 23 - Prob. 15QAPCh. 23 - Prob. 16QAPCh. 23 - Prob. 17QAPCh. 23 - Prob. 18QAPCh. 23 - Prob. 19QAPCh. 23 - Prob. 20QAPCh. 23 - Prob. 21QAPCh. 23 - Prob. 22QAPCh. 23 - Prob. 23QAPCh. 23 - Prob. 24QAPCh. 23 - Prob. 25QAPCh. 23 - Prob. 26QAPCh. 23 - Prob. 27QAPCh. 23 - Prob. 28QAPCh. 23 - Prob. 29QAPCh. 23 - Prob. 30QAPCh. 23 - Prob. 31QAPCh. 23 - Prob. 32QAPCh. 23 - Prob. 33QAPCh. 23 - Prob. 34QAPCh. 23 - Prob. 35QAPCh. 23 - Prob. 36QAPCh. 23 - Prob. 37QAPCh. 23 - Prob. 38QAPCh. 23 - Prob. 39QAPCh. 23 - Prob. 40QAPCh. 23 - Prob. 41QAPCh. 23 - Prob. 42QAPCh. 23 - Prob. 43QAPCh. 23 - Prob. 44QAPCh. 23 - Prob. 45QAPCh. 23 - Prob. 46QAPCh. 23 - Prob. 47QAPCh. 23 - Prob. 48QAPCh. 23 - Prob. 49QAPCh. 23 - Prob. 50QAPCh. 23 - Prob. 51QAPCh. 23 - Prob. 52QAPCh. 23 - Prob. 53QAPCh. 23 - Prob. 54QAPCh. 23 - Prob. 55QAPCh. 23 - Prob. 56QAPCh. 23 - Prob. 57QAPCh. 23 - Prob. 58QAPCh. 23 - Prob. 59QAPCh. 23 - Prob. 60QAPCh. 23 - Prob. 61QAPCh. 23 - Prob. 62QAPCh. 23 - Prob. 63QAPCh. 23 - Prob. 64QAPCh. 23 - Prob. 65QAPCh. 23 - Prob. 66QAPCh. 23 - Prob. 67QAPCh. 23 - Prob. 68QAPCh. 23 - Prob. 69QAPCh. 23 - Prob. 70QAPCh. 23 - Prob. 71QAPCh. 23 - Prob. 72QAPCh. 23 - Prob. 73QAPCh. 23 - Prob. 74QAPCh. 23 - Prob. 75QAPCh. 23 - Prob. 76QAPCh. 23 - Prob. 77QAPCh. 23 - Prob. 78QAPCh. 23 - Prob. 79QAPCh. 23 - Prob. 80QAPCh. 23 - Prob. 81QAPCh. 23 - Prob. 82QAPCh. 23 - Prob. 83QAPCh. 23 - Prob. 84QAPCh. 23 - Prob. 85QAPCh. 23 - Prob. 86QAPCh. 23 - Prob. 87QAPCh. 23 - Prob. 88QAPCh. 23 - Prob. 89QAPCh. 23 - Prob. 90QAPCh. 23 - Prob. 91QAPCh. 23 - Prob. 92QAPCh. 23 - Prob. 93QAPCh. 23 - Prob. 94QAPCh. 23 - Prob. 95QAPCh. 23 - Prob. 96QAPCh. 23 - Prob. 97QAPCh. 23 - Prob. 98QAPCh. 23 - Prob. 99QAPCh. 23 - Prob. 100QAPCh. 23 - Prob. 101QAPCh. 23 - Prob. 102QAPCh. 23 - Prob. 103QAPCh. 23 - Prob. 104QAPCh. 23 - Prob. 105QAPCh. 23 - Prob. 106QAPCh. 23 - Prob. 107QAPCh. 23 - Prob. 108QAPCh. 23 - Prob. 109QAPCh. 23 - Prob. 110QAPCh. 23 - Prob. 111QAPCh. 23 - Prob. 112QAPCh. 23 - Prob. 113QAPCh. 23 - Prob. 114QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- •39 In Fig. 34-38, a beam of parallel light rays from a laser is in- cident on a solid transparent sphere of index of refraction n. (a) If a point image is produced at the back of the sphere, what is the index of refraction of the sphere? (b) What index of refraction, if any, will produce a point image at the center of the sphere?arrow_forward•• ENGINEERING APPLICATION An optical fiber allows rays of light to propagate long distances by using total internal reflec- tion. Optical fibers are used extensively in medicine and in digital communications. As shown in Figure 31-58 the fiber consists of a core material that has an index of refraction n, and radius b sur- rounded by a cladding material that has an index of refraction n3 < n2. The numerical aperture of the fiber is defined as sine, where 0, is the angle of incidence of a ray of light that impinges on the center of the end of the fiber and then reflects off the core- cladding interface just at the critical angle. Using the figure as a guide, show that the numerical aperture is given by sine, = Vn3 - n? assuming the ray is initially in air. Hint: Use of the Pythagorean theorem may be required. 44arrow_forward•• A slab of glass that has an index of refraction of 1.50 is submerged in water that has an index of refraction of 1.33. Light in the water is incident on the glass. Find the angle of refraction if the angle of incidence is (a) 60°, (b) 45°, and (c) 30°. SSM 31arrow_forward
- Physics Many nocturnal animals demonstrate the phenomenon of eyeshine, in which their eyes glow various colors at night when illuminated by a flashlight or the headlights of a car (see the photo). Their eyes react this way because of a thin layer of reflective tissue called the tapetum lucidum that is located directly behind the retina. This tissue reflects the light back through the retina, which increases the available light that can activate photoreceptors, and thus improve the animal’s vision in low-light conditions. If we assume the tapetum lucidum acts like a concave spherical mirror with a radius of curvature of 0.750 cm, how far in front of the tapetum lucidum would an image form of an object located 30.0 cm away? Neglect the effects of the other structures of the eye, such as the cornea and lens.arrow_forwardImagine holding a circular disk in a beam of monochromatic light (Fig. 24-56). If diffraction occurs at the edge of the disk, the center of the shadow is (a) darker than the rest of the shadow. (b) a bright spot. (c) bright or dark, depending on the wavelength. (d) bright or dark, depending on the distance to the screen. Disk Shadow FIGURE 24-56 MisConceptual Question 8. Screenarrow_forward112 You look down at a coin that lies at the bottom of a pool of liquid of depth d and index of refractionn To left (Fig. 34-57). Because you view with two eyes, which intercept different rays of light from the coin, you per- To right eye eye Air ceive the coin to be where extensions of the intercepted rays cross, at depth d, instead of d. Assuming that the intercepted rays in Fig. 34-57 are close to a vertical axis through the coin, show that d, = din. (Hint: Use the small-angle approximation sin 0 tan 6- 0.) Figure 34-57 Problem 112.arrow_forward
- 33.37 • BIO Heart Sonogram. Physicians use high-frequency (f = 1–5 MHz) sound waves, called ultrasound, to image internal or- gans. The speed of these ultrasound waves is 1480 m/s in muscle and 344 m/s in air. We define the index of refraction of a material for sound waves to be the ratio of the speed of sound in air to the speed of sound in the material. Snell's law then applies to the refraction of sound waves. (a) At what angle from the normal does an ultrasound beam enter the heart if it leaves the lungs at an angle of 9.73° from the normal to the heart wall? (Assume that the speed of sound in the lungs is 344 m/s.) (b) What is the critical angle for sound waves in air incident on muscle?arrow_forwardLight takes 499 seconds to travel from Sun to Earth. During that time, the Sun moves across our sky (499/3600)•(360°/24) ≈ 2° ≈ 4 sun-widths. If I want my high-powered laser to have its beam hit the sun, where should I aim? East west or directly at the sun (with explanation )thanksarrow_forwardThe luminous intensity of a emall plane source of light along the forward normal is 160 candela. Assuming the Source to be perfectly diffused, find the luminous flux emitted into a cone of solid angle 0-02 sr around a line making an angle of 60° with the forward normal B 0.02sr/ 60° Forward normal Figure 22-W2arrow_forward
- When you look at the Moon's reflection from a ripply sea, it appears elongated (Fig. 23–47). Explain. FIGURE 23-47 Question 7.arrow_forward1. a) b) c) Consider transmitted light through a thin film of liquid "x" on a lake as shown nair = 1.00 nwater = 1.33 Water = 480 nm (Wavelength of light in the water) Vair = 3.00 x 108 m/s (Speed of light in air) = 2.36 x 108 m/s Vx (Speed of light in "x") AIR WATER 55-1 Determine the index of refraction, nx, for the thin film of liquid "x" Determine the angle of refraction in water, 0, as shown in the picture. The thickness of the film is equal to 2.5 λ is the wavelength of air the light in the air. Determine this thickness. where λ airarrow_forwardTwo sources S, and S, emitting light of wavelength - 2 ст араrt. 600 nm are placed a distance 1.0 x 10 detector can be moved on the line S,P which is perpendicular to S,S,. (a) What would be the minimum and maximum path difference at the detector as it is moved along the line S,P? (b) Locate the position of the farthest minimum detected. A 2•arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Spectra Interference: Crash Course Physics #40; Author: CrashCourse;https://www.youtube.com/watch?v=-ob7foUzXaY;License: Standard YouTube License, CC-BY