The figure 2 shows a cantilever truss connected to a weight of 50 kN at it end E. The truss is connected via a pin at A and a roller at I. Determine: (a) Draw the free body diagram of the truss (FBD). (b) Determine the reactions at pin A and the roller I. (c) Find the force in members IB and IH using the method of joints. Indicate if each member is in tension or compression. "N.B. a solution by the method of sections will get a mark of zero (0)". (d) Find the force in members CD, GD, and GF using the method of sections. Specify in each case whether the member is in tension or compression. "N.B. a solution by the method of joints will get a mark of zero (0)". 3 m A B D 3 m H 3 m 3 m F 3 m Figure 2 E

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Chapter8: Rotational Motion
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The figure 2 shows a cantilever truss connected to a weight of 50 kN at it end E. The truss
is connected via a pin at A and a roller at I. Determine:
(a) Draw the free body diagram of the truss (FBD).
(b) Determine the reactions at pin A and the roller I.
(c) Find the force in members IB and IH using the method of joints. Indicate if each
member is in tension or compression. "N.B. a solution by the method of sections will
get a mark of zero (0)".
(d) Find the force in members CD, GD, and GF using the method of sections. Specify
in each case whether the member is in tension or compression. "N.B. a solution by
the method of joints will get a mark of zero (0)".
3 m
A
B
D
3 m
H
3 m
3 m
F
3 m
Figure 2
E
Transcribed Image Text:The figure 2 shows a cantilever truss connected to a weight of 50 kN at it end E. The truss is connected via a pin at A and a roller at I. Determine: (a) Draw the free body diagram of the truss (FBD). (b) Determine the reactions at pin A and the roller I. (c) Find the force in members IB and IH using the method of joints. Indicate if each member is in tension or compression. "N.B. a solution by the method of sections will get a mark of zero (0)". (d) Find the force in members CD, GD, and GF using the method of sections. Specify in each case whether the member is in tension or compression. "N.B. a solution by the method of joints will get a mark of zero (0)". 3 m A B D 3 m H 3 m 3 m F 3 m Figure 2 E
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