Chapter 21.2, Problem 35PP

To determine

The amount of the net charge on the positively charged plate of the capacitor.

Answer to Problem 35PP

  $1.21\times {10}^{-3}\text{}\text{C}$

Explanation of Solution

Given:

The capacitance of the capacitor, $C=27\mu \text{F}$

The potential applied across the capacitors, $\Delta V=45\text{V}$

Formula used:

The capacitance is given by,

  $C=\frac{q}{\Delta V}$

Where,

  $\Delta V$ is the potential difference and q is the charge stored in the capacitor.

Calculation:

Using the above formula, the charge on the capacitor will be:

  $\begin{array}{c}q=C\Delta V\\ =\left(27\times {10}^{-6}\right)\left(45\right)\\ =1.21\times {10}^{-3}\text{}\text{C}\end{array}$

Conclusion:

Hence, the charge on the capacitor is $1.21\times {10}^{-3}\text{}\text{C}$ .