Chapter 21.2, Problem 36PP

To determine

The capacitor which has a greater net charge on its positively charged plate and the magnitude of its charge.

Answer to Problem 36PP

2^nd capacitor will have great net charge on its positively charged plate with the magnitude of $16.3\times {10}^{-5}\text{}\text{C}$ .

Explanation of Solution

Given:

The capacitance of the 1^st capacitor, $C_1=3.3\mu \text{F}$

The capacitance of the 2^nd capacitor, $C_2=6.8\mu \text{F}$

The potential applied across the capacitors, $\Delta V=24\text{V}$

Formula used:

The capacitance is given by,

  $C=\frac{q}{\Delta V}$

Where,

Where,

  $\Delta V$ is the potential difference and q is the charge stored in the capacitor.

Calculation:

The charge on 1^st capacitor will be,

  $\begin{array}{c}{q}_1=C_1\Delta V\\ =\left(3.3\times {10}^{-6}\right)\left(24\right)\\ =7.9\times {10}^{-5}\text{}\text{C}\end{array}$

And, the charge on 2^nd capacitor will be,

  $\begin{array}{c}{q}_2=C_2\Delta V\\ =\left(6.8\times {10}^{-6}\right)\left(24\right)\\ =16.3\times {10}^{-5}\text{}\text{C}\end{array}$

Conclusion:

Hence, the charge on 2^nd capacitor with capacitance $6.8\mu \text{F}$ is greater than the charge on the 1^st capacitor.