Chapter 21, Problem 83A

To determine

Electric potential difference between the two points.

Answer to Problem 83A

  $\Delta V=439.2\text{V}$

Explanation of Solution

Given:

The given figure is,

  

Force required, $F=0.065\text{N}$

Charge, $q=37\mu \text{C}$

Distance to move, $d=25\text{cm}=0.25\text{m}$

Formula Used:

The electric potential difference is given as,

  $\Delta V=\frac{W}{q}=\frac{Fd}{q}\left(\text{Since, }W=Fd\right)$

Where, $W$ is work done, $q$ is charge, $F$ is force required and $d$ is distance moved.

Calculation:

On substituting the values,

  $\begin{array}{l}\Delta V=\frac{0.065\times 0.25}{37\times {10}^{-6}}\\ =439.2\text{V}\end{array}$

Conclusion:

Therefore, the size of electric potential difference between the two points is $\Delta V=439.2\text{V}$