Chapter 21, Problem 93A

To determine

To Write:A problem in which given equation $E=\frac{9\text{V}-0\text{ V}}{0.85\text{cm}}$ is the part of solution.

Explanation of Solution

Introduction:

Electric field: It is a three dimensional space of a charge where another charge can experience a force.

The Electric field is between parallel plates of capacitor is given as,

  $E=\frac{\Delta V}{d}$

Where, $\Delta V$ is potential difference between capacitor plates and $d$ is distance between the plates.

The problem can be, “What is the strength of electric field between the plates if the potential on the plates are 9 V and 0 V and they are 85 cm apart?”

So,

  $\begin{array}{c}E=\frac{9\text{V}-0\text{V}}{0.85\text{cm}}\\ =\frac{9}{0.85\times {10}^{-2}}\\ =1058.82\text{V/m}\end{array}$