Chapter 21, Problem 58A

To determine

Charge on a test charge.

Answer to Problem 58A

  $q=6.67\times {10}^{-7}\text{C}$ .

Explanation of Solution

Given:

Force experienced by test charge, $F=0.3\text{N}$

Strength of electric field $E=4.5\times {10}^5\text{N/C}$ .

Formula Used:

As strength of an electric field is given by,

  $E=\frac{F}{q}$

Where, $E$ is electric field strength, $F$ is force experienced by charge in electric field and $q$ is the test charge.

Calculation:

So, on putting the given values in above formula,

  $\begin{array}{c}4.5\times {10}^5=\frac{0.3}{q}\\ q=\frac{0.3}{4.5\times {10}^5}\text{C}\\ =6.67\times {10}^{-7}\text{C}\end{array}$

Conclusion:

Therefore, the magnitude of charge on the test charge is $q=6.67\times {10}^{-7}\text{C}$ .