Chapter 21, Problem 107A

To determine

The image position.

Answer to Problem 107A

  $103.63\text{cm}$ to the right of the lens.

Explanation of Solution

Given:

The focal length of the converging lens, $f=38.0\text{cm}$

The object distance from the lens, $d_o=60.0\text{cm}$

Formula used:

Thin lens equation,

  $\frac{1}{f}=\frac{1}{d_i}+\frac{1}{d_o}$

Where,

  $\begin{array}{l}f=\text{focal length of the lens}\\ d_i=\text{ image distance}\\ d_o=\text{object distance}\end{array}$

Calculation:

Using the given values in Thin lens equation, the image distance will be,

  $\begin{array}{c}\frac{1}{f}=\frac{1}{d_i}+\frac{1}{d_o}\\ \frac{1}{38}=\frac{1}{d_i}+\frac{1}{60}\\ d_i=\left(\frac{60\times 38}{60-38}\right)\\ =103.63\text{cm}\end{array}$

Conclusion:

Hence, the image is formed at a distance of $103.63\text{cm}$ to the right of the lens.