Chapter 21.2, Problem 28PP

To determine

Work done on electron.

Answer to Problem 28PP

  $W=2.9\times {10}^{-15}\text{J}$

Explanation of Solution

Given:

Potential difference, $\Delta V=18000\text{V}$

Formula Used:

The work done is given as,

  $W=q\Delta V$

Where, $W$ is work done, $q$ is charge and $\Delta V$ is potential difference.

Calculation:

As magnitude of charge on the electron is $\text{1}\text{.602}\times {\text{10}}^{-19}\text{C}$

So, on substituting the given values in above relation,

  $\begin{array}{c}W=\left(1.602\times {10}^{-19}\right)\times 18000\\ =2.9\times {10}^{-15}\text{J}\end{array}$

Conclusion:

Therefore, the work done on electron is $W=2.9\times {10}^{-15}\text{J}$ .