Chapter 21, Problem 7STP

To determine

To Choose: The correct option.

Answer to Problem 7STP

C. $6.23\times {10}^2\text{}\text{V}$

Explanation of Solution

Given:

The capacitance of the capacitor, $C=0.093\mu \text{F}$

The charge on the capacitor, $q=58\mu \text{C}$

Formula used:

The capacitance is given by,

  $C=\frac{q}{\Delta V}$

Where,

  $\Delta V$ is the potential difference and q is the charge stored in the capacitor.

Calculation:

Using the above formula, the potential difference across the capacitor will be,

  $\begin{array}{c}q=C\Delta V\\ 58\times {10}^{-6}=\left(0.093\times {10}^{-6}\right)\Delta V\\ =6.23\times {10}^2\text{}\text{V}\end{array}$

Conclusion:

Hence, the potential difference across the capacitor is $6.23\times {10}^2\text{}\text{V}$ .