EBK CHEMICAL PRINCIPLES
EBK CHEMICAL PRINCIPLES
8th Edition
ISBN: 9781305856745
Author: DECOSTE
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 21, Problem 153AE
Interpretation Introduction

Interpretation:The pH of lysine at isoelectric point needs to be determined.

Concept introduction:

The pH at which molecule does not carry any net electric charge is said to be its isoelectric point. In this case, it is electrically neutral and the amino acids do not migrate in an electric field.

Expert Solution & Answer
Check Mark

Answer to Problem 153AE

The pH of lysine at isoelectric point is 6.07

Explanation of Solution

The equilibrium constant of reaction Key is known and the value is as follows:

  Keq=7.3 x 10-13

This can be depicted as:

  Keq=Ka(COOH)Ka(NH3+)

Considering the equation

  [H2NCH2CO2-]=[H+3NCH2CO2H]2H+3NCH2CO2H2NCH2CO2-+H+3NCH2CO2H

The equilibrium constant can be represented as follows:

  Keq=[H2NCH2CO2-][H+3NCH2CO2H][ H + 3 NCH 2 CO 2 ]2

Since,

  NH2CH2COOHNH2CH2COO+H++NH3CH2COOHNH2CH2COOH+H+ + NH 3 CH 2 COOH NH 2 CH 2 COO +2 H + _¯

Thus,

  Keq=[ H +]2[H+3NCH2CO2H][H+3NCH2CO2H]

Since,

  [H2NCH2CO2-]=[H+3NCH2CO2H]

Thus,

  7.3 x 10-13=[H+]2[H+]=7 .3 x 10 -13          = 73 x 10 -14          =8.5 x 10-7 M

To compute the pH at isoelectric point is done below

  pH = - log [H+]

  [H+]=8.5 x 10-7 M

  pH = - log [H+]       = - log (8.5 x 10-7)       = 6.07

Hence, the pH of glycine at isoelectric point is 6.07.

Conclusion

The pH of glycine at isoelectric point is 6.07.

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Chapter 21 Solutions

EBK CHEMICAL PRINCIPLES

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