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Concept explainers
(a)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction : The name of an organic compound has three parts, prefix, parent chain and suffix. The format of naming is prefix+parent chain+suffix. The parent chain is the longest chain of carbon atoms in the compound. Suffix denote the name of
(a)
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Answer to Problem 15E
The name of the compound is 1,3-dichlorobutane.
Explanation of Solution
The compound is as follows:
First identify the parent chain of the compound. The parent chain consists of four carbon atoms. So, the name of parent chain is ‘but’. The compound consist of only single bonds so, name of suffix ‘ane’ should be used. Two chlorine atoms present in C1 and C3. So, the name of the compound is 1,3-dichlorobutane.
(b)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction : The name of an organic compound has three parts, prefix, parent chain and suffix. The format of naming is prefix+parent chain+suffix. The parent chain is the longest chain of carbon atoms in the compound. Suffix denote the name of functional group and prefix denote the substituent present in the compound.
(b)
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Answer to Problem 15E
The name of the compound is 1,1,1-trichlorobutane
Explanation of Solution
The compound is
(c)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction : The name of an organic compound has three parts, prefix, parent chain and suffix. The format of naming is prefix+parent chain+suffix. The parent chain is the longest chain of carbon atoms in the compound. Suffix denote the name of functional group and prefix denote the substituent present in the compound.
(c)
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Answer to Problem 15E
The name of the compound is 2, 3-dichloro-2-4-dimethyhexane
Explanation of Solution
The compound is as follows:
The parent chain consists of six carbon atoms. So, the name of parent chain is ‘hex’. Only single bonds present in the compound. So, suffix would be ‘ane’. Two chlorine atoms present in C2 and C3 and two methyl atoms present in C2 and C4. So, the name of the compound is 2,3-dichloro-2-4-dimethyhexane.
(d)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction: The name of an organic compound has three parts, prefix, parent chain and suffix. The format of naming is prefix+parent chain+suffix. The parent chain is the longest chain of carbon atoms in the compound. Suffix denote the name of functional group and prefix denote the substituent present in the compound.
(d)
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Answer to Problem 15E
The name of the following compound is 1,2-difluoroethane
Explanation of Solution
In
(e)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction: The name of an organic compound has three parts, prefix, parent chain and suffix. The format of naming is prefix+parent chain+suffix. The parent chain is the longest chain of carbon atoms in the compound. Suffixdenote the name of functional group and prefix denote the substituent present in the compound.
(e)
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Answer to Problem 15E
The name of the compound is 3-iodobut-1-ene.
Explanation of Solution
The compound is,
The parent carbon chain consists of four carbon atoms. So, the name of the parent chain is ‘but’, double bond present. So, name of suffix is ‘ene’. One iodine atom present at C3. So, the name of the compound is 3-iodobut-1-ene.
(f)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction: In naming of benzene compound prefix is used to denote the substituents present in the compound before the word ’benzene’. If more than one substituent is present, then the substituents are arranged in alphabetical order.
(f)
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Answer to Problem 15E
The name of the compound is 1-bromo-2-methylbenzene.
Explanation of Solution
The name of the compound is as follows:
The compound is a benzene compound. One bromine atom is present at C1 and one methyl group is at C2. So, the name of the compound is 1-bromo-2-methylbenzene.
(g)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction: In naming of cyclic compound, naming is done in the format,
Prefix+Cyclo+parent chain+suffix
Prefix denotes the name of the substituent. If more than one substituent is present then they should be arranged in alphabetical order.
(g)
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Answer to Problem 15E
The name of the compound is 1-bromo-2-methylcyclohexane.
Explanation of Solution
The compound is as follows:
The above compound is cyclic compound. One bromine atom is present at C1 and one methyl atom is present at C2. And the parent chain consists of six carbon atoms. So, the name of the compound is 1-bromo-2-methylcyclohexane.
(h)
Interpretation: The name of the following compound needs to be determined.
Concept Introduction: In naming of cyclic compound, naming is done in the format,
Prefix+Cyclo+parent chain+suffix
Prefix denotes the name of the substituent. If more than one substituent is present, they should be arranged in alphabetical order.
(h)
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Answer to Problem 15E
The name of the compound is 1-bromo-2-methylcyclohex-3-ene.
Explanation of Solution
The compound is as follows:
The above compound is cyclic compound. One bromine atom is present at C1 and one methyl atom is present at C2. The parent chain consists of six carbon atoms and one double bond at C3. So, the name of the compound is 1-bromo-2-methylcyclohex-3-ene.
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Chapter 21 Solutions
EBK CHEMICAL PRINCIPLES
- We learned four factors (ARIO) for comparing the relative acidity of compounds. When two of these factors are in competition, the order of priority is the order in which these factors were covered ("atom" being the most important factor and "orbital" being the least important). However, we also mentioned that there are exceptions to this order of priority. Compare the two compounds and identify the exception. OH PK-4.75 SH PK-10.6 5. "Resonance" is more important than "atom" because the conjugate base of first compound is more stable than the second. "Atom" is more important than "resonance" because the conjugate base of first compound is more stable than the second. "Resonance" is more important than "atom" because the conjugate base of second compound is more stable than the first. "Atom" is more important than "resonance" because the conjugate base of second compound is more stable than the first.arrow_forwardThe relative fitnesses of three genotypes are WA/A= 1.0, WA/a = 0.7, and Wa/a = 0.3. If the population starts at the allele frequency p = 0.5, what is the value of p in the next generation? (3 pts) 12pt v Paragraph V BIU ALarrow_forwardIdentify the most acidic proton in the compound: a d b Оа Ob Ос ○ darrow_forward
- A Standard Reference Material is certified to contain 94.6 ppm of an organic contaminant in soil. Your analysis gives values of 98.6, 98.4, 97.2, 94.6, and 96.2. Do your results differ from the expected results at the 95% confidence interval?arrow_forwardThe percentage of an additive in gasoline was measured six times with the following results: 0.13, 0.12, 0.16, 0.17, 0.20, and 0.11%. Find the 95% confidence interval for the percentage of additive.arrow_forwardExplain why this data led Rayleigh to look for and to discover Ar.arrow_forward
- 5) Confidence interval. Berglund and Wichardt investigated the quantitative determination of Cr in high-alloy steels using a potentiometric titration of Cr(VI). Before the titration, samples of the steel were dissolved in acid and the chromium oxidized to Cr(VI) using peroxydisulfate. Shown here are the results (as %w/w Cr) for the analysis of a reference steel. 16.968, 16.922, 16.840, 16.883, 16.887, 16.977, 16.857, 16.728 Calculate the mean, the standard deviation, and the 95% confidence interval about the mean. What does this confidence interval mean?arrow_forwardIn the Nitrous Acid Test for Amines, what is the observable result for primary amines? Group of answer choices nitrogen gas bubbles form a soluble nitrite salt yellow oily layer of nitrosoaminearrow_forward3. a. Use the MS to propose at least two possible molecular formulas. For an unknown compound: 101. 27.0 29.0 41.0 50.0 52.0 55.0 57.0 100 57.5 58.0 58.5 62.0 63.0 64.0 65.0 74.0 40 75.0 76.0 20 20 40 60 80 100 120 140 160 180 200 220 m/z 99.5 68564810898409581251883040 115.0 116.0 77404799 17417M 117.0 12.9 118.0 33.5 119.0 36 133 0 1.2 157.0 2.1 159.0 16 169.0 219 170.0 17 171.0 21.6 172.0 17 181.0 1.3 183.0 197.0 100.0 198.0 200. 784 Relative Intensity 2 2 8 ō (ppm) 6 2arrow_forward
- Solve the structure and assign each of the following spectra (IR and C-NMR)arrow_forward1. For an unknown compound with a molecular formula of C8H100: a. What is the DU? (show your work) b. Solve the structure and assign each of the following spectra. 8 6 2 ō (ppm) 4 2 0 200 150 100 50 ō (ppm) LOD D 4000 3000 2000 1500 1000 500 HAVENUMBERI -11arrow_forward16. The proton NMR spectral information shown in this problem is for a compound with formula CioH,N. Expansions are shown for the region from 8.7 to 7.0 ppm. The normal carbon-13 spec- tral results, including DEPT-135 and DEPT-90 results, are tabulated: 7 J Normal Carbon DEPT-135 DEPT-90 19 ppm Positive No peak 122 Positive Positive cus и 124 Positive Positive 126 Positive Positive 128 No peak No peak 4° 129 Positive Positive 130 Positive Positive (144 No peak No peak 148 No peak No peak 150 Positive Positive してしarrow_forward
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