Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 20.4, Problem 8P
The pKa of p-cyclopropylbenzoic acid is 4.45. Is cyclopropylbenzene likely to be more reactive or less reactive than benzene toward electrophilic bromination? Explain.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
The pKa of p-cyclopropylbenzoic acid is 4.45 . Is cyclopropylbenzene likely to be more reactive or less
reactive than benzene toward electrophilic brornination? Explain.
The following questions concern ethyl (2-oxocyclohexane)carboxylate.(a) Write a chemical equation showing how you could prepare ethyl (2-oxocyclohexane)-carboxylate by a Dieckmann cyclization.(b) Write a chemical equation showing how you could prepare ethyl (2-oxocyclohexane)-carboxylate by acylation of a ketone.(c) Write structural formulas for the two most stable enol forms of ethyl (2-oxocyclohexane)carboxylate.(d) Write the three most stable resonance contributors to the most stable enolate derived from ethyl (2-oxocyclohexane)carboxylate.(e) Show how you could use ethyl (2-oxocyclohexane)carboxylate to prepare 2-methylcyclohexanone.(f) Give the structure of the product formed on treatment of ethyl (2-oxocyclohexane)-carboxylate with acrolein (H2C=CHCH=O) in ethanol in the presence of sodium ethoxide
Arrange the following compounds in order of increasing reactivity towards electrophilic aromatic substitution:
Aniline
Benzoic acid
Chlorobenzene
Ethylbenzene
Chapter 20 Solutions
Organic Chemistry
Ch. 20.1 - Give IUPAC names for the following compounds:Ch. 20.1 - Draw structures corresponding to the following...Ch. 20.2 - Prob. 3PCh. 20.2 - The Ka for dichloroacetic acid is 3.32 Ă— 10-2....Ch. 20.3 - Calculate the percentages of dissociated and...Ch. 20.4 - Which would you expect to be a stronger acid, the...Ch. 20.4 - Dicarboxylic acids have two dissociation...Ch. 20.4 - The pKa of p-cyclopropylbenzoic acid is 4.45. Is...Ch. 20.4 - Prob. 9PCh. 20.5 - Prob. 10P
Ch. 20.6 - Prob. 11PCh. 20.6 - How might you carry out the following...Ch. 20.7 - Prob. 13PCh. 20.7 - Prob. 14PCh. 20.8 - Cyclopentanecarboxylic acid and...Ch. 20.8 - Prob. 16PCh. 20.SE - Prob. 17VCCh. 20.SE - Prob. 18VCCh. 20.SE - The following carboxylic acid can’t be prepared...Ch. 20.SE - Electrostatic potential maps of anisole and...Ch. 20.SE - Predict the product(s) and provide the mechanism...Ch. 20.SE - Predict the product(s) and provide the mechanism...Ch. 20.SE - Prob. 23MPCh. 20.SE - Predict the product(s) and provide the complete...Ch. 20.SE - Acid-catalyzed hydrolysis of a nitrile to give a...Ch. 20.SE - Prob. 26MPCh. 20.SE - Naturally occurring compounds called cyanogenic...Ch. 20.SE - 2-Bromo-6, 6-dimethylcyclohexanone gives 2,...Ch. 20.SE - Naturally occurring compounds called terpenoids,...Ch. 20.SE - In the Ritter reaction, an alkene reacts with a...Ch. 20.SE - Give IUPAC names for the following compounds:Ch. 20.SE - Prob. 32APCh. 20.SE - Prob. 33APCh. 20.SE - Prob. 34APCh. 20.SE - Prob. 35APCh. 20.SE - Prob. 36APCh. 20.SE - Prob. 37APCh. 20.SE - Prob. 38APCh. 20.SE - Calculate the Ka's for the following acids: (a)...Ch. 20.SE - Thioglycolic acid, HSCH2CO2H, a substance used in...Ch. 20.SE - Prob. 41APCh. 20.SE - Prob. 42APCh. 20.SE - How could you convert butanoic acid into the...Ch. 20.SE - How could you convert each of the following...Ch. 20.SE - How could you convert butanenitrile into the...Ch. 20.SE - How would you prepare the following compounds from...Ch. 20.SE - Prob. 47APCh. 20.SE - Using 13CO2 as your only source of labeled carbon,...Ch. 20.SE - Prob. 49APCh. 20.SE - Which method-Grignard carboxylation or nitrile...Ch. 20.SE - Prob. 51APCh. 20.SE - Prob. 52APCh. 20.SE - Propose a structure for a compound C6H12O2 that...Ch. 20.SE - Prob. 54APCh. 20.SE - How would you use NMR (either 13C or 1H) to...Ch. 20.SE - Prob. 56APCh. 20.SE - A chemist in need of 2,2-dimethylpentanoic acid...Ch. 20.SE - Prob. 58APCh. 20.SE - Prob. 59APCh. 20.SE - Prob. 60APCh. 20.SE - Prob. 61APCh. 20.SE - Prob. 62APCh. 20.SE - Prob. 63APCh. 20.SE - The following pKa values have been measured....Ch. 20.SE - Identify the missing reagents a-f in the following...Ch. 20.SE - Propose a structure for a compound, C4H7N, that...Ch. 20.SE - Prob. 67APCh. 20.SE - The 1H and 13C NMR spectra below belong to a...Ch. 20.SE - Propose structures for carboxylic acids that show...Ch. 20.SE - Carboxylic acids having a second carbonyl group...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- East Indian sandalwood oil contains a hydrocarbon given the name santene (C9H14). Ozonolysis of santene gives the compound shown. What is the structure of santene?arrow_forwardWhat groups favor the nitration of benzene and what groups do not favor it?arrow_forwardTreatment of indene with NaNH2 forms its conjugate base in a Brønsted–Lowry acid–base reaction. Draw all reasonable resonance structures forindene's conjugate base, and explain why the pKa of indene is lower thanthe pKa of most hydrocarbons.arrow_forward
- Carbonyl compounds can be protonated on the carbonyl oxygen. Protonation of the carbonyl oxygen gives a species whose positive charge is delocalized by resonance. Explain why acetic acid (ethanoic acid) is more readily protonated than acetone (propanone).arrow_forward19.58 For each of the following questions, please provide a route that could reasonably be expected to convert the starting material into the product. In each case, more than one reaction is required, and reactions you have learned in previous chapters may be needed to solve the problem. -8 8 (b) Jos 1-3 (d) NH₂ OEt OEt OEt Eto OH LOH 5- OH H₂N OH "NH₂ Oarrow_forwardWhich is more acidic, p-methylphenol or phenol? why? Why is water more acidic than ethanol but slightly less acidic than methanol? Explain the acidity trend of alcohols: 1>2 > 3arrow_forward
- What reactions and reagents can be used to make phenol from benzene if electrophilic aromatic substitution reactions are excluded and benzene is the only source of carbon?arrow_forwardArrange the the compounds in order of increasing reactivity towards electrophilic aromatic substitution.arrow_forwardCompound F may be synthesised by the method attached: Draw the structural formulas of compounds A, C, D, E and F in the boxes providedarrow_forward
- Propranolol, an antihypertensive agent used in the treatment of high blood pressure, can be prepared from 1-naphthol, epichlorohydrin, and isopropylamine using two successive nucleophilic substitution reactions. Devise a stepwise synthesis of propranolol from these starting materials.arrow_forwardAs a method for the synthesis of cinnamaldehyde (3-phenyl-2-propenal), a chemist treated 3-phenyl-2-propen-1-ol with K2Cr2O7 in sulfuric acid. The product obtained from the reaction gave a signal at δ5 in its 13C NMR spectrum. Alternatively, when the chemist treated 3-phenyl-2-propen-1-ol with PCC in CH2Cl2, the 13C NMR spectrum of the product displayed a signal at δ193.8. (All other signals in the spectra of both compounds appeared at similar chemical shifts.) (a) Which reaction produced cinnamaldehyde? (b) What was the other product?arrow_forwardCompound F may be synthesised by the method attached: When 2-chloropropane treated with NaOH and 1-chloropropane treated with NaOH separately produce two different functional groups. Provide both reactions and explain the two different functional groups produced.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY