
a)
Interpretation:
The IUPAC name of the compound represented by the model shown is to be given.
Concept introduction:
The names of simple carboxylic acids which are derivatives of open-chain
To give:
The IUPAC name of the compound represented by the model shown.

Answer to Problem 17VC
The IUPAC name is 3-bromo-4-methoxybenzoic acid.
Explanation of Solution
The compound represented by the model is
It is a benzoic acid derivative with a bromine atom on C3 and a methoxyl group on C4.
The IUPAC name of the compound represented by the model shown is 3-bromo-4-methoxybenzoic acid.
b)
Interpretation:
The IUPAC name of the compound represented by the model shown is to be given.
Concept introduction:
The names of simple carboxylic acids which are derivatives of open-chain alkanes are arrived by replacing the terminal –e of the corresponding alkane name by –oic acid. The numbering starts from carboxyl carbon. Compounds with –COOH bonded to a ring are named using the suffix-carboxylic acid. The –COOH carbon in this case is not numbered as C1, instead the carbon to which it is attached is numbered as C1. As a substituent, the –COOH group is called as carboxyl group.
To give:
The IUPAC name of the compound represented by the model shown.

Answer to Problem 17VC
The IUPAC name of the compound represented by the model shown is 3-methyl-2-butenoic acid.
Explanation of Solution
The compound represented by the model is
The compound is an unsaturated acid having a four carbon straight chain with a double bond between C2 and C3.
The IUPAC name of the compound represented by the model shown is 3-methyl-2-butenoic acid.
c)
Interpretation:
The IUPAC name of the compound represented by the model shown is to be given.
Concept introduction:
The names of simple carboxylic acids which are derivatives of open-chain alkanes are arrived by replacing the terminal –e of the corresponding alkane name by –oic acid. The numbering starts from carboxyl carbon. Compounds with –COOH bonded to a ring are named using the suffix-carboxylic acid. The –COOH carbon in this case is not numbered as C1, instead the carbon to which it is attached is numbered as C1. As a substituent, the –COOH group is called as carboxyl group.
To give:
The IUPAC name of the compound represented by the model shown.

Answer to Problem 17VC
The IUPAC name of the compound represented by the model shown is cyclopenta-1,3-dienecarboxylic acid.
Explanation of Solution
The compound represented by the model is
The compound has a cyclopentadiene ring to which a carboxyl group is attached. The double bonds in the diene are in between C1 & C2 and C3 & C4.
The IUPAC name of the compound represented by the model shown is cyclopenta-1,3-dienecarboxylic acid.
d)
Interpretation:
The IUPAC name of the compound represented by the model shown is to be given.
Concept introduction:
The names of simple carboxylic acids which are derivatives of open-chain alkanes are arrived by replacing the terminal –e of the corresponding alkane name by –oic acid. The numbering starts from carboxyl carbon. Compounds with –COOH bonded to a ring are named using the suffix-carboxylic acid. The –COOH carbon in this case is not numbered as C1, instead the carbon to which it is attached is numbered as C1. As a substituent, the –COOH group is called as carboxyl group.
To give:
The IUPAC name of the compound represented by the model shown.

Answer to Problem 17VC
The IUPAC name of the compound represented by the model shown is (S)-3-cyclopentyl-2-methylpropanoic acid.
Explanation of Solution
The compound represented by the model is
The compound is a carboxylic acid with a three carbon straight chin and has a methyl group attached to C2 and cyclopentyl group attached to C3. The compound is optically active as C2 is chiral. The groups of first highest, second highest and third highest groups when viewed away from the group of last priority are arranged in the anti-clockwise direction. Hence the compound has S stereochemistry.
The IUPAC name of the compound represented by the model shown is (S)-3-cyclopentyl-2-methylpropanoic acid.
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Chapter 20 Solutions
Organic Chemistry
- Draw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forwardEpoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forward
- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- Select the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward5:45 Х Select the final product for the following reaction sequence. O O 1. Mg. ether 2.D.Oarrow_forwardBased on the chart Two similarities between the molecule with alpha glycosidic linkages. Two similarities between the molecules with beta glycosidtic linkages. Two differences between the alpha and beta glycosidic linkages.arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning

