Concept explainers
(a)
Interpretation:
The physical state of propene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(b)
Interpretation:
The physical state of 1-hexene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(c)
Interpretation:
The physical state of cyclopentene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(d)
Interpretation:
The physical state of cycloheptene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.

Want to see the full answer?
Check out a sample textbook solution
Chapter 2 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Select the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forwardb. H3C CH3 H3O+ ✓ H OHarrow_forward
- 2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forwardIdentify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forward
- Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forwardC. NaOMe, Br Brarrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning




