(a)
Interpretation:
IUPAC name for the given
Concept Introduction:
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon
atoms are numbered 1 and 2 in a direction where the substituent gets the lower number. - If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.
(b)
Interpretation:
IUPAC name for the given unsaturated hydrocarbon has to be assigned.
Concept Introduction:
IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkene.
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.
- If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.
(c)
Interpretation:
IUPAC name for the given unsaturated hydrocarbon has to be assigned.
Concept Introduction:
IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkene.
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.
- If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.
(d)
Interpretation:
IUPAC name for the given unsaturated hydrocarbon has to be assigned.
Concept Introduction:
IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkenes.
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.
- If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.

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Chapter 2 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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