Concept explainers
(a)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(b)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(c)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(d)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
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Chapter 2 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Part C IN H N. Br₂ (2 equiv.) AlBr3 Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and + e (×) H± 12D T EXP. L CONT. דarrow_forward9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer appropriately in the box. Only the answer in the box will be graded. (3) points) OH OH بر بد بدید 2 3arrow_forwardThere is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forward
- A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forwardProvide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forward
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