(a)
Interpretation:
IUPAC name for the given
Concept Introduction:
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon
atoms are numbered 1 and 2 in a direction where the substituent gets the lower number. - If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.
(b)
Interpretation:
IUPAC name for the given unsaturated hydrocarbon has to be assigned.
Concept Introduction:
IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkene.
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.
- If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.
(c)
Interpretation:
IUPAC name for the given unsaturated hydrocarbon has to be assigned.
Concept Introduction:
IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkene.
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.
- If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.
(d)
Interpretation:
IUPAC name for the given unsaturated hydrocarbon has to be assigned.
Concept Introduction:
IUPAC nomenclature for alkene: There are about eight rules to be followed in giving IUPAC name for alkenes.
- The suffix –ane has to be replaced with the suffix –ene. This is used to indicate the presence of double bond.
- The longest continuous chain of carbon atoms has to be chosen that contains both carbon atoms of the double bond.
- The parent carbon chain has to be numbered in a way so that the numbering begins at the end near to the double bond. In case if the double bond is equidistant from both ends, then numbering has to be done from the end that is closer to substituents.
- The position of the double bond has to be given a single number which is lower‑numbered carbon atom that is present in the double bond.
- Suffixes like –diene, -triene, -tetrene, and so on are used when the compound contains more than one double bond.
- In case of cycloalkenes which do not have any substitution, the numbering is not needed to locate the double bond because the bond is assumed to be between the carbons 1 and 2.
- In case if substituents are present in cycloalkene, then the double‑bonded carbon atoms are numbered 1 and 2 in a direction where the substituent gets the lower number.
- If the cycloalkenes contain more than one double bond, then one double bond is assigned the numbers 1 and 2 followed by the other double bond so that the lowest number possible is given.

Want to see the full answer?
Check out a sample textbook solution
Chapter 2 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- Post Lab Questions. 1) Draw the mechanism of your Diels-Alder cycloaddition. 2) Only one isomer of product is formed in the Diels-Alder cycloaddition. Why? 3) Imagine that you used isoprene as diene - in that case you don't have to worry about assigning endo vs exo. Draw the "endo" and "exo" products of the Diels-Alder reaction between isoprene and maleic anhydride, and explain why the distinction is irrelevant here. 4) This does not hold for other dienes. Draw the exo and endo products of the reaction of cyclohexadiene with maleic anhydride. Make sure you label your answers properly as endo or exo. 100 °C Xylenes ??? 5) Calculate the process mass intensity for your specific reaction (make sure to use your actual amounts of reagent).arrow_forwardIndicate the product(s) A, B C and D that are formed in the reaction: H + NH-NH-CH [A+B] [C+D] hydrazonesarrow_forwardHow can you prepare a 6 mL solution of 6% H2O2, if we have a bottle of 30% H2O2?arrow_forward
- How many mL of H2O2 from the 30% bottle must be collected to prepare 6 mL of 6% H2O2.arrow_forwardIndicate the product(s) B and C that are formed in the reaction: HN' OCH HC1 B + mayoritario C minoritario OCH3arrow_forwardIndicate the product(s) that are formed in the reaction: NH-NH, OCH3 -H₂O OCH3arrow_forward
- 21.38 Arrange the molecules in each set in order of increasing acidity (from least acidic to most acidic). OH OH SH NH2 8 NH3 OH (b) OH OH OH (c) & & & CH3 NO2 21.39 Explain the trends in the acidity of phenol and the monofluoro derivatives of phenol. OH OH OH OH PK 10.0 PK 8.81 PK 9.28 PK 9.81arrow_forwardidentify which spectrum is for acetaminophen and which is for phenacetinarrow_forwardThe Concept of Aromaticity 21.15 State the number of 2p orbital electrons in each molecule or ion. (a) (b) (e) (f) (c) (d) (h) (i) DA (k) 21.16 Which of the molecules and ions given in Problem 21.15 are aromatic according to the Hückel criteria? Which, if planar, would be antiaromatic? 21.17 Which of the following structures are considered aromatic according to the Hückel criteria? ---0-0 (a) (b) (c) (d) (e) (h) H -H .8.0- 21.18 Which of the molecules and ions from Problem 21.17 have electrons donated by a heteroatom?arrow_forward
- 1. Show the steps necessary to make 2-methyl-4-nonene using a Wittig reaction. Start with triphenylphosphine and an alkyl halide. After that you may use any other organic or inorganic reagents. 2. Write in the product of this reaction: CH3 CH₂ (C6H5)₂CuLi H₂O+arrow_forward3. Name this compound properly, including stereochemistry. H₂C H3C CH3 OH 4. Show the step(s) necessary to transform the compound on the left into the acid on the right. Bri CH2 5. Write in the product of this LiAlH4 Br H₂C OHarrow_forwardWhat are the major products of the following reaction? Please provide a detailed explanation and a drawing to show how the reaction proceeds.arrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningOrganic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning





