Concept explainers
(a)
Interpretation:
The physical state of ethene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(b)
Interpretation:
The physical state of 1-pentene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(c)
Interpretation:
The physical state of cyclobutene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(d)
Interpretation:
The physical state of cyclohexene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.

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Chapter 2 Solutions
EBK ORGANIC AND BIOLOGICAL CHEMISTRY
- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
- In the following reaction, the OH- acts as which of these? NO2-(aq) + H2O(l) ⇌ OH-(aq) + HNO2(aq)arrow_forwardUsing spectra attached, can the unknown be predicted? Draw the predicition. Please explain and provide steps. Molecular focrmula:C16H13ClOarrow_forwardCalculate the percent ionization for 0.0025 M phenol. Use the assumption to find [H3O+] first. K = 1.0 x 10-10arrow_forward
- The Ka for sodium dihydrogen phosphate is 6.32 x 10-8. Find the pH of a buffer made from 0.15 M H2PO4- and 0.25 M HPO42- .arrow_forwardThe Ka for lactic acid is 1.4 x 10-4. Find the pH of a buffer made from 0.066 M lactic acid and 0.088 M sodium lactate.arrow_forwardZaitsev's Rule 3) (a) Rank the following alkenes in order of decreasing stability. most stable A B C D > > > (b) Rank the following carbocations in order of decreasing stability least stable B C Darrow_forward
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