The set up of a galvanic cell is given. The reducing agent and the oxidizing agent, and the direction of the electron flow are to be stated. Concept introduction: In galvanic cell, the oxidation occurs at anode while reduction occurs at cathode. The species that undergoes oxidation reaction loses electrons and reduces other species. Therefore, it acts as a reducing agent. On the other hand, the species that undergoes reduction reaction gains electrons and oxidizes other species. Therefore, it acts as an oxidizing agent. To determine: The oxidizing agent and the reducing agent, and the direction of the electron flow.
The set up of a galvanic cell is given. The reducing agent and the oxidizing agent, and the direction of the electron flow are to be stated. Concept introduction: In galvanic cell, the oxidation occurs at anode while reduction occurs at cathode. The species that undergoes oxidation reaction loses electrons and reduces other species. Therefore, it acts as a reducing agent. On the other hand, the species that undergoes reduction reaction gains electrons and oxidizes other species. Therefore, it acts as an oxidizing agent. To determine: The oxidizing agent and the reducing agent, and the direction of the electron flow.
Solution Summary: The author explains the set up of a galvanic cell. The oxidation reaction occurs at anode and the reduction reaction at catho.
The set up of a galvanic cell is given. The reducing agent and the oxidizing agent, and the direction of the electron flow are to be stated.
Concept introduction:
In galvanic cell, the oxidation occurs at anode while reduction occurs at cathode. The species that undergoes oxidation reaction loses electrons and reduces other species. Therefore, it acts as a reducing agent. On the other hand, the species that undergoes reduction reaction gains electrons and oxidizes other species. Therefore, it acts as an oxidizing agent.
To determine: The oxidizing agent and the reducing agent, and the direction of the electron flow.
PLEASE READ!!! I DONT WANT EXAMPLES, I DONT WANT WORDS OR PARAGRAPHS FOR THE MECHANISM!!! THANKS
First image: QUESTION 6. I have to show, with ARROWS and STRUCTURES, the mechanism of the reaction at the bottom. Also I have to show by mecanism why the reaction wouldn't work if the alcohol was primary.
I also tried to draw the mechanism, tell me what to change. Please note that its an AMIDE thats formed not an AMINE the nitrogen has ONE hydrogen and one Phenyl-C-Phenyl. I already asked for this mechanism and got as a final product ...-NH2 not whats shown on the picture, thank you
Ths second part. QUESTION 3. I just need a way to synthesize the lactone A, I already started please continue from where I left it
Second image: I simply need the products, substrates or reagents, thank you
Indicate how to prepare a 10% sodium hydroxide (NaOH) solution to a slightly alkaline pH.
Chapter 17 Solutions
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell