The Table 17 − 1 showing reduction potential values of various elements is given. The reason behind the corrosion of most of the metals and the difficulty in corrosion of noble metals like, gold, platinum, and silver is to be stated. Concept introduction: The metal undergoes oxidation and the oxygen undergoes reduction during corrosion. So, the metal with reduction potential values lower than oxygen easily gets corroded in the air. To determine: The reason of corrosion of most of the metals in air and the reason of difficulty in the corrosion of noble metals like gold, platinum, and silver.
The Table 17 − 1 showing reduction potential values of various elements is given. The reason behind the corrosion of most of the metals and the difficulty in corrosion of noble metals like, gold, platinum, and silver is to be stated. Concept introduction: The metal undergoes oxidation and the oxygen undergoes reduction during corrosion. So, the metal with reduction potential values lower than oxygen easily gets corroded in the air. To determine: The reason of corrosion of most of the metals in air and the reason of difficulty in the corrosion of noble metals like gold, platinum, and silver.
Solution Summary: The author analyzes the relationship between cell potential and Gibbs free energy change by analyzing the Table 17-1 showing reduction potential values of various elements.
The Table
17−1 showing reduction potential values of various elements is given. The reason behind the corrosion of most of the metals and the difficulty in corrosion of noble metals like, gold, platinum, and silver is to be stated.
Concept introduction:
The metal undergoes oxidation and the oxygen undergoes reduction during corrosion. So, the metal with reduction potential values lower than oxygen easily gets corroded in the air.
To determine: The reason of corrosion of most of the metals in air and the reason of difficulty in the corrosion of noble metals like gold, platinum, and silver.
3. Synthesize the following synthon from the indicated
starting material.
i
HO.
Identifying the stereochemistry of natural
Write the complete common (not IUPAC) name of each molecule below.
Note: if a molecule is one of a pair of enantiomers, be sure you start its name with D- or L- so we know which enantiomer it is.
molecule
H
O-C-CH2
H3N.
HN
N
H
C=O
common name
(not the IUPAC
name)
NH3
☐
H3N
H
☐
CH2
X
>
Draw the structure of alanine at pH 1.2.
Click and drag to start drawing a
structure.
Chapter 17 Solutions
Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell