The Table 17 − 1 showing reduction potential values of various elements is given. The reason behind the corrosion of most of the metals and the difficulty in corrosion of noble metals like, gold, platinum, and silver is to be stated. Concept introduction: The metal undergoes oxidation and the oxygen undergoes reduction during corrosion. So, the metal with reduction potential values lower than oxygen easily gets corroded in the air. To determine: The reason of corrosion of most of the metals in air and the reason of difficulty in the corrosion of noble metals like gold, platinum, and silver.
The Table 17 − 1 showing reduction potential values of various elements is given. The reason behind the corrosion of most of the metals and the difficulty in corrosion of noble metals like, gold, platinum, and silver is to be stated. Concept introduction: The metal undergoes oxidation and the oxygen undergoes reduction during corrosion. So, the metal with reduction potential values lower than oxygen easily gets corroded in the air. To determine: The reason of corrosion of most of the metals in air and the reason of difficulty in the corrosion of noble metals like gold, platinum, and silver.
Solution Summary: The author analyzes the relationship between cell potential and Gibbs free energy change by analyzing the Table 17-1 showing reduction potential values of various elements.
The Table
17−1 showing reduction potential values of various elements is given. The reason behind the corrosion of most of the metals and the difficulty in corrosion of noble metals like, gold, platinum, and silver is to be stated.
Concept introduction:
The metal undergoes oxidation and the oxygen undergoes reduction during corrosion. So, the metal with reduction potential values lower than oxygen easily gets corroded in the air.
To determine: The reason of corrosion of most of the metals in air and the reason of difficulty in the corrosion of noble metals like gold, platinum, and silver.
LTS
Solid:
AT=Te-Ti
Trial 1
Trial 2
Trial 3
Average
ΔΗ
Mass water, g
24.096
23.976
23.975
Moles of solid, mol
0.01763
001767
0101781
Temp. change, °C
2.9°C
11700
2.0°C
Heat of reaction, J
-292.37J -170.473
-193.26J
AH, kJ/mole
16.58K 9.647 kJ 10.85 kr
16.58K59.64701
KJ
mol
12.35k
Minimum AS,
J/mol K
41.582
mol-k
Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn &
Show your calculations for:
AH in J and then in kJ/mole for Trial 1:
qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J
qsin =
qrxn =
292.35 292.37J
AH in J = 292.375 0.2923kJ
0.01763m01
=1.65×107
AH in kJ/mol =
=
16.58K
0.01763mol
mol
qrx
Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con
Kelvin.)
AS=AHIT
(1.65×10(9.64×103) + (1.0
Jimai
For the compound: C8H17NO2
Use the following information to come up with a plausible structure:
8
This compound has "carboxylic acid amide" and ether functional groups.
The peaks at 1.2ppm are two signals that are overlapping one another.
One of the two signals is a doublet that represents 6 hydrogens; the
other signal is a quartet that represents 3 hydrogens.
Vnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling
point, choose 2 next to the substance with the next highest boiling point, and so on.
substance
C
D
chemical symbol,
chemical formula
or Lewis structure.
CH,-N-CH,
CH,
H
H 10: H
C-C-H
H H H
Cale
H 10:
H-C-C-N-CH,
Bri
CH,
boiling point
(C)
Сен
(C) B
(Choose
Chapter 17 Solutions
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