PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
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Chapter 1.7, Problem 28E

(a)

To determine

To find: A linear model and the correlation coefficient using a graphing utility.

(a)

Expert Solution
Check Mark

Answer to Problem 28E

Linear model y=0.3401x+77.943

  Correlation coefficient(r)=0.9934

Explanation of Solution

Given:

The data set is:

  (14,81.2)     (28,87.1)         (42,93.7)(56,98.3)     (70,102.4)        (84,106.2)(98,110)

Formula used:

The regression line is written as:

  y=ax+b

Where,

a is the intercept coefficient

b is the slope coefficient.

The formula to compute the correlation coefficient is:

  r=n∑XY−∑X∑Yn∑X2−(∑X)2×n∑Y2−(∑Y)2

Calculation:

The provided data in tabular form could be written as:

  xy1481.22887.14293.75698.370102.484106.298110

Follow the provided steps of Ti-83 plus calculator to compute a linear model and the correlation coefficient:

  1. Turn on the calculator.
  2. Click on STAT > Edit > Enter.
  3. Enter the data of x in L1 and data of y in L2.
  4. Click om STAT > CALC >LinReg ( ax +b) > ENTER.
  5. Hit 2nd and 1 to choose L1 and Hit 2nd and 2 to choose L2.
  6. Hit Enter.

The obtained output is:

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 1.7, Problem 28E , additional homework tip 1

From the above output, linear model and correlation coefficients are y=0.3401x+77.943 and r=0.9934 respectively.

(b)

To determine

To explain: If the model is representing the data well using the correlation coefficient.

(b)

Expert Solution
Check Mark

Answer to Problem 28E

Yes.

Explanation of Solution

From the above part, it is known that r=0.9934 . Since, the value of the correlation coefficient is closer to the 1. Thus, it could be said that model is representing the data well.

(c)

To determine

To plot: The provided data.

(c)

Expert Solution
Check Mark

Explanation of Solution

Graph:

Using the Ti-83 calculator the figure is constructed as:

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 1.7, Problem 28E , additional homework tip 2

Interpretation:

In the above figure, the model is represented by the line and actual data by dots.

Since, the data points are lying on the line it could be concluded that model is well fitted for the actual data.

(d)

To determine

To predict: The average length of colt 112 days after birth.

(d)

Expert Solution
Check Mark

Answer to Problem 28E

The average length is 116.0342.

Explanation of Solution

Calculation:

The length could be calculated as:

  y=0.3401x+77.943=0.3401(112)+77.943=116.0342

The required average length is 116.0342.

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Chapter 1.7, Problem 27E
Next
Chapter 1.7, Problem 29E

Chapter 1 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

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Prob. 59ECh. 1.6 - Prob. 60ECh. 1.6 - Prob. 61ECh. 1.6 - Prob. 62ECh. 1.6 - Prob. 63ECh. 1.6 - Prob. 64ECh. 1.6 - Prob. 65ECh. 1.6 - Prob. 66ECh. 1.6 - Prob. 67ECh. 1.6 - Prob. 68ECh. 1.6 - Prob. 69ECh. 1.6 - Prob. 70ECh. 1.6 - Prob. 71ECh. 1.6 - Prob. 72ECh. 1.6 - Prob. 73ECh. 1.6 - Prob. 74ECh. 1.6 - Prob. 75ECh. 1.6 - Prob. 76ECh. 1.6 - Prob. 77ECh. 1.6 - Prob. 78ECh. 1.6 - Prob. 79ECh. 1.6 - Prob. 80ECh. 1.6 - Prob. 81ECh. 1.6 - Prob. 82ECh. 1.6 - Prob. 83ECh. 1.6 - Prob. 84ECh. 1.6 - Prob. 85ECh. 1.6 - Prob. 86ECh. 1.6 - Prob. 87ECh. 1.6 - Prob. 88ECh. 1.6 - Prob. 89ECh. 1.6 - Prob. 90ECh. 1.6 - Prob. 91ECh. 1.6 - Prob. 92ECh. 1.6 - Prob. 93ECh. 1.6 - Prob. 94ECh. 1.6 - Prob. 95ECh. 1.6 - Prob. 96ECh. 1.6 - Prob. 97ECh. 1.6 - Prob. 98ECh. 1.6 - Prob. 99ECh. 1.6 - Prob. 100ECh. 1.6 - Prob. 101ECh. 1.6 - Prob. 102ECh. 1.6 - Prob. 103ECh. 1.6 - Prob. 104ECh. 1.6 - Prob. 105ECh. 1.6 - Prob. 106ECh. 1.6 - Prob. 107ECh. 1.6 - Prob. 108ECh. 1.6 - Prob. 109ECh. 1.6 - Prob. 110ECh. 1.6 - Prob. 111ECh. 1.6 - Prob. 112ECh. 1.6 - Prob. 113ECh. 1.6 - Prob. 114ECh. 1.6 - Prob. 115ECh. 1.6 - Prob. 116ECh. 1.6 - Prob. 117ECh. 1.6 - Prob. 118ECh. 1.6 - Prob. 119ECh. 1.6 - Prob. 120ECh. 1.6 - Prob. 121ECh. 1.6 - Prob. 122ECh. 1.6 - Prob. 123ECh. 1.6 - Prob. 124ECh. 1.6 - Prob. 125ECh. 1.6 - Prob. 126ECh. 1.6 - Prob. 127ECh. 1.6 - Prob. 128ECh. 1.6 - Prob. 129ECh. 1.6 - Prob. 130ECh. 1.6 - Prob. 131ECh. 1.6 - Prob. 132ECh. 1.6 - Prob. 133ECh. 1.6 - Prob. 134ECh. 1.6 - Prob. 135ECh. 1.6 - Prob. 136ECh. 1.6 - Prob. 137ECh. 1.6 - Prob. 138ECh. 1.6 - Prob. 139ECh. 1.6 - Prob. 140ECh. 1.6 - Prob. 141ECh. 1.6 - Prob. 142ECh. 1.6 - Prob. 143ECh. 1.6 - Prob. 144ECh. 1.7 - Prob. 1ECh. 1.7 - Prob. 2ECh. 1.7 - Prob. 3ECh. 1.7 - Prob. 4ECh. 1.7 - Prob. 5ECh. 1.7 - Prob. 6ECh. 1.7 - Prob. 7ECh. 1.7 - Prob. 8ECh. 1.7 - Prob. 9ECh. 1.7 - Prob. 10ECh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1 - Prob. 1CRCh. 1 - Prob. 2CRCh. 1 - Prob. 3CRCh. 1 - Prob. 4CRCh. 1 - Prob. 5CRCh. 1 - Prob. 6CRCh. 1 - Prob. 7CRCh. 1 - Prob. 8CRCh. 1 - Prob. 9CRCh. 1 - Prob. 10CRCh. 1 - Prob. 11CRCh. 1 - Prob. 12CRCh. 1 - Prob. 13CRCh. 1 - Prob. 14CRCh. 1 - Prob. 15CRCh. 1 - Prob. 16CRCh. 1 - Prob. 17CRCh. 1 - Prob. 18CRCh. 1 - Prob. 19CRCh. 1 - Prob. 20CRCh. 1 - Prob. 21CRCh. 1 - Prob. 22CRCh. 1 - Prob. 23CRCh. 1 - Prob. 24CRCh. 1 - Prob. 25CRCh. 1 - Prob. 26CRCh. 1 - Prob. 27CRCh. 1 - Prob. 28CRCh. 1 - Prob. 29CRCh. 1 - Prob. 30CRCh. 1 - Prob. 31CRCh. 1 - Prob. 32CRCh. 1 - Prob. 33CRCh. 1 - Prob. 34CRCh. 1 - Prob. 35CRCh. 1 - Prob. 36CRCh. 1 - Prob. 37CRCh. 1 - Prob. 38CRCh. 1 - Prob. 39CRCh. 1 - Prob. 40CRCh. 1 - Prob. 41CRCh. 1 - Prob. 42CRCh. 1 - Prob. 43CRCh. 1 - Prob. 44CRCh. 1 - Prob. 45CRCh. 1 - Prob. 46CRCh. 1 - Prob. 47CRCh. 1 - Prob. 48CRCh. 1 - Prob. 49CRCh. 1 - Prob. 50CRCh. 1 - Prob. 51CRCh. 1 - Prob. 52CRCh. 1 - Prob. 53CRCh. 1 - Prob. 54CRCh. 1 - Prob. 55CRCh. 1 - Prob. 56CRCh. 1 - Prob. 57CRCh. 1 - Prob. 58CRCh. 1 - Prob. 59CRCh. 1 - Prob. 60CRCh. 1 - Prob. 61CRCh. 1 - Prob. 62CRCh. 1 - Prob. 63CRCh. 1 - Prob. 64CRCh. 1 - Prob. 65CRCh. 1 - Prob. 66CRCh. 1 - Prob. 67CRCh. 1 - Prob. 68CRCh. 1 - Prob. 69CRCh. 1 - Prob. 70CRCh. 1 - Prob. 71CRCh. 1 - Prob. 72CRCh. 1 - Prob. 73CRCh. 1 - Prob. 74CRCh. 1 - Prob. 75CRCh. 1 - Prob. 76CRCh. 1 - Prob. 77CRCh. 1 - Prob. 78CRCh. 1 - Prob. 79CRCh. 1 - Prob. 80CRCh. 1 - Prob. 81CRCh. 1 - Prob. 82CRCh. 1 - Prob. 83CRCh. 1 - Prob. 84CRCh. 1 - Prob. 85CRCh. 1 - Prob. 86CRCh. 1 - Prob. 87CRCh. 1 - Prob. 88CRCh. 1 - Prob. 89CRCh. 1 - Prob. 90CRCh. 1 - Prob. 91CRCh. 1 - Prob. 92CRCh. 1 - Prob. 93CRCh. 1 - Prob. 94CRCh. 1 - Prob. 95CRCh. 1 - Prob. 96CRCh. 1 - Prob. 97CRCh. 1 - Prob. 98CRCh. 1 - Prob. 99CRCh. 1 - Prob. 100CRCh. 1 - Prob. 101CRCh. 1 - Prob. 102CRCh. 1 - Prob. 103CRCh. 1 - Prob. 104CRCh. 1 - Prob. 105CRCh. 1 - Prob. 106CRCh. 1 - Prob. 107CRCh. 1 - Prob. 108CRCh. 1 - Prob. 109CRCh. 1 - Prob. 110CRCh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CT
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