Chapter 1, Problem 4CT

a.

To determine

To find : the value of independent variable and simplify.

Answer to Problem 4CT

the value is $-9$.

Explanation of Solution

Given information :

The function is $f\left(x\right)=|x+2|-15$.

Calculation: since here $x=-8$ ,so first substitute then add and subtract,

  $\begin{array}{l}f\left(x\right)=|x+2|-15\\ f\left(-8\right)=|-8+2|-15\text{ [substitute]}\\ f\left(-8\right)=6-15\text{ [subtract]}\\ f\left(-8\right)=-9\text{ [subtract]}\end{array}$

The value is $-9$.

b.

To determine

To find : the value of independent variable and simplify.

Answer to Problem 4CT

the value is $1$.

Explanation of Solution

Given information :

The function is $f\left(x\right)=|x+2|-15$.

Calculation: since here $x=14$ ,so first substitute then add and subtract,

  $\begin{array}{l}f\left(x\right)=|x+2|-15\\ f\left(14\right)=|14+2|-15\text{ [substitute]}\\ f\left(14\right)=16-15\text{ [subtract]}\\ f\left(14\right)=1\text{ [subtract]}\end{array}$

The value is $1$.

c.

To determine

To find : the value of independent variable and simplify.

Answer to Problem 4CT

the value is $|t-4|-15$.

Explanation of Solution

Given information :

The function is $f\left(x\right)=|x+2|-15$.

Calculation: since here $x=t-6$ ,so first substitute then add and subtract,

  $\begin{array}{l}f\left(x\right)=|x+2|-15\\ f\left(t-6\right)=|t-6+2|-15\text{ [substitute]}\\ f\left(t-6\right)=|t-4|-15\text{ [subtract]}\end{array}$

The value is $|t-4|-15$.