PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
8th Edition
ISBN: 9781337904285
Author: Larson
Publisher: CENGAGE L
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Concept explainers

Transformation of Graphs
The word ‘transformation’ means modification. Transformation of the graph of a function is a process by which we modify or change the original graph and make a new graph.
Exponential Functions
The exponential function is a type of mathematical function which is used in real-world contexts. It helps to find out the exponential decay model or exponential growth model, in mathematical models. In this topic, we will understand descriptive rules, c…
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Question
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Chapter 1.3, Problem 80E

(a)

To determine

To calculate: To find the coordinates of a second point on the graph of a function if the given point is on the graph and the function is even

(a)

Expert Solution
Check Mark

Answer to Problem 80E

Second coordinate is (53,−7)

Explanation of Solution

  

Given: Point is (−53,−7)

Formula Used:

Even Function: If the graph of function has symmetry about y-axis as shown below:

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 1.3, Problem 80E , additional homework tip 1

For point (x,y) lying on the graph, (−x,y) also lies on the graph

Calculation:

Point is given as follows:

  (−53,−7)

Since the function is even and point lies on graph.

Thus, coordinates of second point that lies on graph is as follows:

  (53,−7)

Conclusion:

Hence, second coordinate is (53,−7)

(b)

To determine

To calculate: To find the coordinates of a second point on the graph of a function if the given point is on the graph and the function is odd

(b)

Expert Solution
Check Mark

Answer to Problem 80E

Second coordinate is (53,7)

Explanation of Solution

  

Given: Point is (−53,−7)

Formula Used:

Odd Function: If the graph of function has symmetry about origin as shown below:

  PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS), Chapter 1.3, Problem 80E , additional homework tip 2

For point (x,y) lying on the graph, (−x,−y) also lies on the graph

Calculation:

Point is given as follows:

  (−53,−7)

Since the function is odd and point lies on graph.

Thus, coordinates of second point that lies on graph is as follows:

  (53,7)

Conclusion:

Hence, second coordinate is (53,7)

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Chapter 1.3, Problem 79E
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Chapter 1.3, Problem 81E

Chapter 1 Solutions

PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)

Ch. 1.1 - Prob. 1ECh. 1.1 - Prob. 2ECh. 1.1 - Prob. 3ECh. 1.1 - Prob. 4ECh. 1.1 - Prob. 5ECh. 1.1 - Prob. 6ECh. 1.1 - Prob. 7ECh. 1.1 - Prob. 8ECh. 1.1 - Prob. 9ECh. 1.1 - Prob. 10E
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Prob. 59ECh. 1.6 - Prob. 60ECh. 1.6 - Prob. 61ECh. 1.6 - Prob. 62ECh. 1.6 - Prob. 63ECh. 1.6 - Prob. 64ECh. 1.6 - Prob. 65ECh. 1.6 - Prob. 66ECh. 1.6 - Prob. 67ECh. 1.6 - Prob. 68ECh. 1.6 - Prob. 69ECh. 1.6 - Prob. 70ECh. 1.6 - Prob. 71ECh. 1.6 - Prob. 72ECh. 1.6 - Prob. 73ECh. 1.6 - Prob. 74ECh. 1.6 - Prob. 75ECh. 1.6 - Prob. 76ECh. 1.6 - Prob. 77ECh. 1.6 - Prob. 78ECh. 1.6 - Prob. 79ECh. 1.6 - Prob. 80ECh. 1.6 - Prob. 81ECh. 1.6 - Prob. 82ECh. 1.6 - Prob. 83ECh. 1.6 - Prob. 84ECh. 1.6 - Prob. 85ECh. 1.6 - Prob. 86ECh. 1.6 - Prob. 87ECh. 1.6 - Prob. 88ECh. 1.6 - Prob. 89ECh. 1.6 - Prob. 90ECh. 1.6 - Prob. 91ECh. 1.6 - Prob. 92ECh. 1.6 - Prob. 93ECh. 1.6 - Prob. 94ECh. 1.6 - Prob. 95ECh. 1.6 - Prob. 96ECh. 1.6 - Prob. 97ECh. 1.6 - Prob. 98ECh. 1.6 - Prob. 99ECh. 1.6 - Prob. 100ECh. 1.6 - Prob. 101ECh. 1.6 - Prob. 102ECh. 1.6 - Prob. 103ECh. 1.6 - Prob. 104ECh. 1.6 - Prob. 105ECh. 1.6 - Prob. 106ECh. 1.6 - Prob. 107ECh. 1.6 - Prob. 108ECh. 1.6 - Prob. 109ECh. 1.6 - Prob. 110ECh. 1.6 - Prob. 111ECh. 1.6 - Prob. 112ECh. 1.6 - Prob. 113ECh. 1.6 - Prob. 114ECh. 1.6 - Prob. 115ECh. 1.6 - Prob. 116ECh. 1.6 - Prob. 117ECh. 1.6 - Prob. 118ECh. 1.6 - Prob. 119ECh. 1.6 - Prob. 120ECh. 1.6 - Prob. 121ECh. 1.6 - Prob. 122ECh. 1.6 - Prob. 123ECh. 1.6 - Prob. 124ECh. 1.6 - Prob. 125ECh. 1.6 - Prob. 126ECh. 1.6 - Prob. 127ECh. 1.6 - Prob. 128ECh. 1.6 - Prob. 129ECh. 1.6 - Prob. 130ECh. 1.6 - Prob. 131ECh. 1.6 - Prob. 132ECh. 1.6 - Prob. 133ECh. 1.6 - Prob. 134ECh. 1.6 - Prob. 135ECh. 1.6 - Prob. 136ECh. 1.6 - Prob. 137ECh. 1.6 - Prob. 138ECh. 1.6 - Prob. 139ECh. 1.6 - Prob. 140ECh. 1.6 - Prob. 141ECh. 1.6 - Prob. 142ECh. 1.6 - Prob. 143ECh. 1.6 - Prob. 144ECh. 1.7 - Prob. 1ECh. 1.7 - Prob. 2ECh. 1.7 - Prob. 3ECh. 1.7 - Prob. 4ECh. 1.7 - Prob. 5ECh. 1.7 - Prob. 6ECh. 1.7 - Prob. 7ECh. 1.7 - Prob. 8ECh. 1.7 - Prob. 9ECh. 1.7 - Prob. 10ECh. 1.7 - Prob. 11ECh. 1.7 - Prob. 12ECh. 1.7 - Prob. 13ECh. 1.7 - Prob. 14ECh. 1.7 - Prob. 15ECh. 1.7 - Prob. 16ECh. 1.7 - Prob. 17ECh. 1.7 - Prob. 18ECh. 1.7 - Prob. 19ECh. 1.7 - Prob. 20ECh. 1.7 - Prob. 21ECh. 1.7 - Prob. 22ECh. 1.7 - Prob. 23ECh. 1.7 - Prob. 24ECh. 1.7 - Prob. 25ECh. 1.7 - Prob. 26ECh. 1.7 - Prob. 27ECh. 1.7 - Prob. 28ECh. 1.7 - Prob. 29ECh. 1.7 - Prob. 30ECh. 1.7 - Prob. 31ECh. 1.7 - Prob. 32ECh. 1.7 - Prob. 33ECh. 1.7 - Prob. 34ECh. 1 - Prob. 1CRCh. 1 - Prob. 2CRCh. 1 - Prob. 3CRCh. 1 - Prob. 4CRCh. 1 - Prob. 5CRCh. 1 - Prob. 6CRCh. 1 - Prob. 7CRCh. 1 - Prob. 8CRCh. 1 - Prob. 9CRCh. 1 - Prob. 10CRCh. 1 - Prob. 11CRCh. 1 - Prob. 12CRCh. 1 - Prob. 13CRCh. 1 - Prob. 14CRCh. 1 - Prob. 15CRCh. 1 - Prob. 16CRCh. 1 - Prob. 17CRCh. 1 - Prob. 18CRCh. 1 - Prob. 19CRCh. 1 - Prob. 20CRCh. 1 - Prob. 21CRCh. 1 - Prob. 22CRCh. 1 - Prob. 23CRCh. 1 - Prob. 24CRCh. 1 - Prob. 25CRCh. 1 - Prob. 26CRCh. 1 - Prob. 27CRCh. 1 - Prob. 28CRCh. 1 - Prob. 29CRCh. 1 - Prob. 30CRCh. 1 - Prob. 31CRCh. 1 - Prob. 32CRCh. 1 - Prob. 33CRCh. 1 - Prob. 34CRCh. 1 - Prob. 35CRCh. 1 - Prob. 36CRCh. 1 - Prob. 37CRCh. 1 - Prob. 38CRCh. 1 - Prob. 39CRCh. 1 - Prob. 40CRCh. 1 - Prob. 41CRCh. 1 - Prob. 42CRCh. 1 - Prob. 43CRCh. 1 - Prob. 44CRCh. 1 - Prob. 45CRCh. 1 - Prob. 46CRCh. 1 - Prob. 47CRCh. 1 - Prob. 48CRCh. 1 - Prob. 49CRCh. 1 - Prob. 50CRCh. 1 - Prob. 51CRCh. 1 - Prob. 52CRCh. 1 - Prob. 53CRCh. 1 - Prob. 54CRCh. 1 - Prob. 55CRCh. 1 - Prob. 56CRCh. 1 - Prob. 57CRCh. 1 - Prob. 58CRCh. 1 - Prob. 59CRCh. 1 - Prob. 60CRCh. 1 - Prob. 61CRCh. 1 - Prob. 62CRCh. 1 - Prob. 63CRCh. 1 - Prob. 64CRCh. 1 - Prob. 65CRCh. 1 - Prob. 66CRCh. 1 - Prob. 67CRCh. 1 - Prob. 68CRCh. 1 - Prob. 69CRCh. 1 - Prob. 70CRCh. 1 - Prob. 71CRCh. 1 - Prob. 72CRCh. 1 - Prob. 73CRCh. 1 - Prob. 74CRCh. 1 - Prob. 75CRCh. 1 - Prob. 76CRCh. 1 - Prob. 77CRCh. 1 - Prob. 78CRCh. 1 - Prob. 79CRCh. 1 - Prob. 80CRCh. 1 - Prob. 81CRCh. 1 - Prob. 82CRCh. 1 - Prob. 83CRCh. 1 - Prob. 84CRCh. 1 - Prob. 85CRCh. 1 - Prob. 86CRCh. 1 - Prob. 87CRCh. 1 - Prob. 88CRCh. 1 - Prob. 89CRCh. 1 - Prob. 90CRCh. 1 - Prob. 91CRCh. 1 - Prob. 92CRCh. 1 - Prob. 93CRCh. 1 - Prob. 94CRCh. 1 - Prob. 95CRCh. 1 - Prob. 96CRCh. 1 - Prob. 97CRCh. 1 - Prob. 98CRCh. 1 - Prob. 99CRCh. 1 - Prob. 100CRCh. 1 - Prob. 101CRCh. 1 - Prob. 102CRCh. 1 - Prob. 103CRCh. 1 - Prob. 104CRCh. 1 - Prob. 105CRCh. 1 - Prob. 106CRCh. 1 - Prob. 107CRCh. 1 - Prob. 108CRCh. 1 - Prob. 109CRCh. 1 - Prob. 110CRCh. 1 - Prob. 1CTCh. 1 - Prob. 2CTCh. 1 - Prob. 3CTCh. 1 - Prob. 4CTCh. 1 - Prob. 5CTCh. 1 - Prob. 6CTCh. 1 - Prob. 7CTCh. 1 - Prob. 8CTCh. 1 - Prob. 9CTCh. 1 - Prob. 10CTCh. 1 - Prob. 11CTCh. 1 - Prob. 12CTCh. 1 - Prob. 13CTCh. 1 - Prob. 14CTCh. 1 - Prob. 15CTCh. 1 - Prob. 16CTCh. 1 - Prob. 17CTCh. 1 - Prob. 18CTCh. 1 - Prob. 19CTCh. 1 - Prob. 20CT
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