Concept explainers
For each of the following reactions, predict whether the equilibrium lies predominantly to the left or to the right. Explain your predictions briefly.
- (a) H2S(aq) + CO32−(aq) ⇄ HS−(aq) + HCO3−(aq)
- (b) HCN(aq) + SO42−(aq) ⇄ CN(aq) + HSO4(aq)
- (c) SO42−(aq) + CH3CO2H(aq) ⇄ HSO4−(aq) + CH3CO2−(aq)
(a)
Interpretation: The direction of the equilibrium for the given reaction is to be determined.
Concept introduction: An acid-base reaction reaction is represented as written below.
The base will take up the proton from acid and form its conjugate acid and simultaneously acid will form its conjugate base. The equilibrium will be forward or backward can be determined by using the dissociation constants
Answer to Problem 38PS
The equilibrium for the given reaction will lie in right direction predominantly.
Explanation of Solution
The equilibrium for the given reaction will move in left side is explained below.
Here, the acid
(b)
Interpretation: The direction of the equilibrium for the given reaction is to be determined.
Concept introduction: An acid-base reaction reaction is represented as written below.
The base will take up the proton from acid and form its conjugate acid and simultaneously acid will form its conjugate base. The equilibrium will be forward or backward can be determined by using the dissociation constants
Answer to Problem 38PS
The equilibrium for the given reaction will lie in left direction predominantly.
Explanation of Solution
The equilibrium for the given reaction will move in left side is explained below.
Here, the conjugate acid
(c)
Interpretation: The direction of the equilibrium for the given reaction is to be determined.
Concept introduction: An acid-base reaction reaction is represented as written below.
The base will take up the proton from acid and form its conjugate acid and simultaneously acid will form its conjugate base. The equilibrium will be forward or backward can be determined by using the dissociation constants
Answer to Problem 38PS
The equilibrium for the given reaction will lie in left side predominantly.
Explanation of Solution
The equilibrium for the given reaction will move in left side is explained below.
Here, the conjugate acid
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Chapter 16 Solutions
Chemistry & Chemical Reactivity
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- Identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction: (a) (CH3)3N(aq) +H2O(1) = (CH3)3NH+(aq)+ OH (aq) (b) HNO3 (aq) + H2O(1) = H3O+(aq) + NO3-(aq) Drag the appropriate items to their respective bins. Reset Help (CH3)3N H2O (a) (CH3)3NH+ OH HNO3 H2O (b) H30+ NO3 Brønsted- Lowry acid Brønsted- Lowry base Conjugate acid Conjugate basearrow_forwardSelect the reaction that depicts the ionization of a weak acid in water. Group of answer choices HNO3(aq) + H2O(l) ⇌ NO3‒(aq) + H3O+(aq) NH3(aq) + H2O(l) ⇌ NH2‒(aq) + H3O+(aq) NH3(aq) + H2O(l) ⇌ NH4+(aq) + OH‒(aq) HF(aq) + H2O(l) ⇌ F‒(aq) + H3O+(aq)arrow_forwardFor each reaction, identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base. C4H5N(aq)+H2O(l)⇌C4H5NH+aq)+OH(aq)C4H5N(aq)+H2O(l)⇌C4H5NH+(aq)+OH−(aq) Express your answers as chemical formulas. Enter your answers in the order given in the question separated by commas.arrow_forward
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- Assuming the forward reactions are favored in the chemical equations below, arrange the acids according to INCREASING acid strength. HNO2(aq) + HCOO–(aq) ⇌ NO2–(aq) + HCOOH(aq) HN3(aq) + BrO–(aq) ⇌ N3–(aq) + HBrO(aq) N3– + HCOOH(aq) ⇌ HN3(aq) + HCOO–(aq) (a) < (b) < (c) < (d) acids: HNO2, CHOOH, HN3, HBrOarrow_forwardIdentify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction: (a) C; H; N(aq) + H2O(1) = C; H;NH+(aq)+OH¯(aq) (b) HNO3 (aq) + H2O(1) = H3O+(aq) + NO3¯(aq) Drag the appropriate items to their respective bins. Reset Help C5H;N H2O (a) C,H;NH+ OH- HNO3 H2O (b) H30+ NO3 Brønsted- Lowry acid Brønsted- Lowry base Conjugate acid Conjugate basearrow_forwardFor each chemical reaction in the table below, decide whether the highlighted reactant is a Brønsted-Lowry acid, a Brønsted-Lowry base, or neither. highlighted reactant reaction Bronsted-Lowry Bronsted-Lowry neither acid base + HBr(aq) + H,O() Br (aq) + H,О (ад) HBr(aq) + H,O(1) → Br (aq) + H30'(aq) Br (aq) + H;О (ад) HBr(aq) + H,O(1) Br (aq) + H,O'(aq) – - HBr(aq) + H,0(1)arrow_forward
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