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(a)
Interpretation: The number of triple points in the given phase diagram of sulfur needs to be determined.
Concept Introduction:
The conversion of
The heating -cooling curve is the curve of temperature v/s time that interpret the change in the states of matter with increase in temperature.
The phase diagram represents the change in the physical state of given substance with temperature and pressure.
(a)
Answer to Problem 104E
There are three triple points in the given phase diagram of sulfur.
Explanation of Solution
A triple point is the point in the phase diagram at which all the three phases will join together. It indicates the point (temperature and pressure) at which all three states remain in equilibrium.
(b)
Interpretation: The phases at the triple points in the given phase diagram of sulfur needs to be determined.
Concept Introduction:
The conversion of solid to liquid and gas involves the change in temperature that can display in heat curve.
The heating -cooling curve is the curve of temperature v/s time that interpret the change in the states of matter with increase in temperature.
The phase diagram represents the change in the physical state of given substance with temperature and pressure.
(b)
Answer to Problem 104E
- At 95.31°C: rhombic, monoclinic, gas
- At 115.18°C: monoclinic, liquid, gas
- At 153°C: rhombic, monoclinic, and liquid
Explanation of Solution
A triple point is the point in the phase diagram at which all the three phases will join together. It indicates the point (temperature and pressure) at which all three states remain in equilibrium.
At 95.31°C, the rhombic, monoclinic and gaseous state of sulfur are in equilibrium whereas at 115.18°C monoclinic, liquid and gaseous state of sulfur. The 3rd triple point is at 153°C at which rhombic, monoclinic, and liquid state of sulfur.
(c)
Interpretation: The phases which are stable at room temperature and 1.0 atm pressure in the given phase diagram of sulfur needs to be determined.
Concept Introduction:
The conversion of solid to liquid and gas involves the change in temperature that can display in heat curve.
The heating -cooling curve is the curve of temperature v/s time that interpret the change in the states of matter with increase in temperature.
The phase diagram represents the change in the physical state of given substance with temperature and pressure.
(c)
Answer to Problem 104E
At room temperature and 1.0 atm pressure,the rhombic phase of sulfur is stable. The temperature is approximately ˜ 20°C and pressure is 1.0 atm.
Explanation of Solution
In the given phase diagram, there are four states of sulfur; monoclinic, rhombic, liquid and gaseous state of sulfur.
At room temperature and 1.0 atm pressure, the rhombic phase of sulfur is stable. The temperature is approximately ˜ 20°C and pressure is 1.0 atm.
(d)
Interpretation: The possibility of existence of monoclinic sulfur in equilibrium with sulfur vapor needs to be determined.
Concept Introduction:
The conversion of solid to liquid and gas involves the change in temperature that can display in heat curve.
The heating -cooling curve is the curve of temperature v/s time that interpret the change in the states of matter with increase in temperature.
The phase diagram represents the change in the physical state of given substance with temperature and pressure.
(d)
Answer to Problem 104E
The monoclinic sulfur and vapor or gaseous state of matter share the phase line therefore they can be in equilibrium in the phase diagram.
Explanation of Solution
In the given phase diagram, there are four states of sulfur; monoclinic, rhombic, liquid and gaseous state of sulfur. The monoclinic sulfur and vapor or gaseous state of matter share the phase line therefore they can be in equilibrium in the phase diagram.
(e)
Interpretation: The normal boiling point and normal melting point of sulfur according to given phase diagram needs to be determined.
Concept Introduction:
The conversion of solid to liquid and gas involves the change in temperature that can display in heat curve.
The heating -cooling curve is the curve of temperature v/s time that interpret the change in the states of matter with increase in temperature.
The phase diagram represents the change in the physical state of given substance with temperature and pressure.
(e)
Answer to Problem 104E
Normal melting point = 115.21°C
Normal boiling point = 444.6°C
Explanation of Solution
In the given phase diagram, there are four states of sulfur; monoclinic, rhombic, liquid and gaseous state of sulfur. Boiling point is the temperature at which liquid and gaseous state remain in equilibrium at 1 atm pressure. According to given phase diagram, the normal boiling point of sulfur must be 444.6°C. The melting point of substance is the temperature at which solid melts to liquid state which is 115.21 °C for sulfur.
(f)
Interpretation: The denser phase out of solid, monoclinic or rhombic sulfur according to given phase diagram needs to be determined.
Concept Introduction:
The conversion of solid to liquid and gas involves the change in temperature that can display in heat curve.
The heating -cooling curve is the curve of temperature v/s time that interpret the change in the states of matter with increase in temperature.
The phase diagram represents the change in the physical state of given substance with temperature and pressure.
(f)
Answer to Problem 104E
Rhombic sulfur is the densest phase of sulfur.
Explanation of Solution
In the given phase diagram, there are four states of sulfur; monoclinic, rhombic, liquid and gaseous state of sulfur. The Rhombic phase of sulfur is most dense phase of it compare to monoclinic and solid. This is because the rhombic-monoclinic equilibrium line has a positive slope therefore with increase in the temperature, the rhombic phase changes to monoclinic.
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Chapter 16 Solutions
Chemical Principles
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- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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