
(a)
Interpretation:
The value of
Concept introduction:
At equilibrium, the constant which is used to express the relationship between reactants and products at the given temperature in a reversible chemical heat reaction is known as equilibrium constant.
For a reversible
The equilibrium constant is given by the following expression:
Where,
Equilibrium concentration of
Equilibrium concentration of
Equilibrium concentration of
Equilibrium concentration of
(b)
Interpretation:
The partial pressure of cyclopropane for the given condition at
Concept introduction:
A general equilibrium reaction can be written as follows:
For a general reaction, the expression for Kc can be represented as follows:
It can also be written in the form of partial pressure of all the gases as follows:
(c)
Interpretation:
The changes after altering the ratio of the two concentrations at equilibrium needs to be explained by adding cyclopropane or decreasing the volume of a container
Concept introduction:
A general equilibrium reaction can be written as follows:
For a general reaction, the expression for Kc can be represented as follows:
It can also be written in the form of partial pressure of all the gases as follows:
(d)
Interpretation:
The reaction with the larger rate constant out of reverse and forward needs to be determined.
Concept introduction:
A general equilibrium reaction can be written as follows:
For a general reaction, the expression for Kc can be represented as follows:
It can also be written in the form of partial pressure of all the gases as follows:
(e)
Interpretation:
Thereason of reactive cyclopropane needs to be explained.
Concept introduction:
A general equilibrium reaction can be written as follows:
For a general reaction, the expression for Kc can be represented as follows:
It can also be written in the form of partial pressure of all the gases as follows:

Want to see the full answer?
Check out a sample textbook solution
Chapter 15 Solutions
CHEMISTRY-TEXT
- curved arrows are used to illustrate the flow of electrons. using the provided starting and product structures, draw the cured electron-pushing arrows for thw following reaction or mechanistic steps. be sure to account for all bond-breaking and bond making stepsarrow_forwardUsing the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.arrow_forwardSynthesis of Dibenzalacetone [References] Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below. Question 1 1 pt Question 2 1 pt Question 3 1 pt H Question 4 1 pt Question 5 1 pt Question 6 1 pt Question 7 1pt Question 8 1 pt Progress: 7/8 items Que Feb 24 at You do not have to consider stereochemistry. . Draw the enolate ion in its carbanion form. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. ⚫ Separate multiple reactants using the + sign from the drop-down menu. ? 4arrow_forward
- Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)arrow_forwardHi I need help on the question provided in the image.arrow_forwardDraw a reasonable mechanism for the following reaction:arrow_forward
- Draw the mechanism for the following reaction: CH3 CH3 Et-OH Et Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron-flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. H± EXP. L CONT. י Α [1] осн CH3 а CH3 :Ö Et H 0 N о S 0 Br Et-ÖH | P LL Farrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCl. What is the molarity of the HCl?arrow_forward20.00 mL of 0.025 M HCl is titrated with 0.035 M KOH. What volume of KOH is needed?arrow_forward
- 20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCl. What is the molarity of the HCl?arrow_forward20.00 mL of 0.025 M HCl is titrated with 0.035 M KOH. What volume of KOH is needed?arrow_forward20.00 mL of 0.150 M HCl is titrated with 37.75 mL of NaOH. What is the molarity of the NaOH?arrow_forward
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning





