Chapter 15, Problem 15.61SP

Interpretation Introduction

(a)

Interpretation:

The value of the equilibrium constant $K_p$ for the reaction $2{\text{NO}}_{2(g)}\rightleftharpoons {\text{N}}_{\text{2}}{\text{O}}_4{}_{(g)}$ at $\text{400 K}$ is to be calculated.

Concept introduction:

The term equilibrium constant expresses the relationship between the reactants and the products of a reaction that is in the equilibrium state. This relationship using the partial pressures of reactants and products to calculate the equilibrium constant, it is denoted as $K_p$. The relationship is as follows:

$K_p=\frac{P_{(\text{products})}}{P_{(r\text{eactants})}}$

Interpretation Introduction

(b)

Interpretation:

The value of the equilibrium constant $K_p$ for the reaction $2{\text{N}}_{\text{2}}{\text{O}}_{\text{4}}{}_{(g)}\rightleftharpoons 4{\text{NO}}_{2(g)}$ at $400K$ is to be calculated.

Concept introduction:

The term equilibrium constant expresses the relationship between the reactants and the products of a reaction that is in the equilibrium state. The equilibrium constant can be obtained using concentration or the partial pressure of reactants and products.

But if the reaction is multiplied by a factor, then the new equilibrium constant can be obtained for the reaction by taking the equilibrium constant raised to power of that particularfactor. For example, on multiplying the reaction from $"n"$ then the new equilibrium constant will be,

$K_p{}^{\text{'}}=K_p{}^n$

Interpretation Introduction

(c)

Interpretation:

The value of the equilibrium constant $K_p$ for the reaction ${\text{NO}}_{2(g)}\rightleftharpoons 1/2{\text{N}}_{\text{2}}{\text{O}}_{\text{4}}{}_{(g)}$ at $4\text{00 K}$ is to be calculated.

Concept introduction:

The term equilibrium constant expresses the relationship between the reactants and the products of a reaction that is in the equilibrium state. The equilibrium constant can be obtained using concentration or the partial pressure of reactants and products.

But if the reaction is divided by a factor, then the new equilibrium constant can be obtained for the reaction by taking the root of the equilibrium constant using that factor. For example, if the reaction is divided byusing the factor $"n"$, then the $n^{th}$ root of the equilibrium constant is taken.