(a) Interpretation: The equilibrium constant expression K c needs to be determined. Concept introduction: The expression of equilibrium constant is basically the concentrations of the products to the reactant’s ratio. If K is greater than 1 , then the mixture comprises mostly products. If K is smaller than 1 , then the mixture comprises of reactants. If K is equal to one, then the reaction will reach equilibrium as an intermediate mixture, which, means there is same number of products and reactants present.
(a) Interpretation: The equilibrium constant expression K c needs to be determined. Concept introduction: The expression of equilibrium constant is basically the concentrations of the products to the reactant’s ratio. If K is greater than 1 , then the mixture comprises mostly products. If K is smaller than 1 , then the mixture comprises of reactants. If K is equal to one, then the reaction will reach equilibrium as an intermediate mixture, which, means there is same number of products and reactants present.
The equilibrium constant expression Kc needs to be determined.
Concept introduction:
The expression of equilibrium constant is basically the concentrations of the products to the reactant’s ratio. If K is greater than 1, then the mixture comprises mostly products. If K is smaller than 1, then the mixture comprises of reactants. If K is equal to one, then the reaction will reach equilibrium as an intermediate mixture, which, means there is same number of products and reactants present.
Interpretation Introduction
(b)
Interpretation:
The value of (Kc) needs to be determined.
Concept introduction:
The expression of equilibrium constant is basically the concentrations of the products to the reactant’s ratio. If K is greater than 1, then the mixture comprises mostly products. If K is smaller than 1, then the mixture comprises of reactants. If K is equal to one, then the reaction will reach equilibrium as an intermediate mixture, which, means there is same number of products and reactants present.
MISSED THIS? Read Section 19.9 (Pages 878-881); Watch IWE 19.10
Consider the following reaction:
CH3OH(g)
CO(g) + 2H2(g)
(Note that AG,CH3OH(g) = -162.3 kJ/mol and AG,co(g)=-137.2 kJ/mol.)
Part A
Calculate AG for this reaction at 25 °C under the following conditions:
PCH₂OH
Pco
PH2
0.815 atm
=
0.140 atm
0.170 atm
Express your answer in kilojoules to three significant figures.
Ο ΑΣΦ
AG = -150
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kJ
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Calculate the free energy change under nonstandard conditions (AGrxn) by using the following relationship:
AGrxn = AGrxn + RTInQ,
AGxn+RTInQ,
where AGxn is the standard free energy change, R is the ideal gas constant, T is the temperature in kelvins, a
is the reaction quotient.
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