(a) Interpretation: Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H 2 is 0.10 M should be calculated. Concept introduction: The equilibrium constant, K c is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature. Equilibrium constant expression aA + bB ⇌ cC + dD K c = [ C ] c [ D ] d [ A ] a [ B ] b

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Answer 1

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Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai

Answer 2

Question

Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Expert Solution & Answer

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See solution

Answer 3

Question

Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Answer 6

Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Answer 7

Chapter 15, Problem 15.83SP

Interpretation Introduction

(a)

Interpretation:

Equilibrium concentration of H atoms at equilibrium, if the equilibrium concentration of H₂ is 0.10 M should be calculated.

Concept introduction:

The equilibrium constant, Kc is the ratio between product of the equilibrium concentrations of the products and the product of equilibrium concentrations of all reactants. All the concentrations are raised to the power of its coefficient in the balanced equation. Equilibrium constant for a particular reaction is always same at a particular temperature.

Equilibrium constant expression

aA + bB ⇌ cC + dDKc=[C]c[D]d[A]a[B]b

Answer 8

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Answer 10

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Answer 11

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Answer 12

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Answer 13

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Solution Summary: The author explains the equilibrium constant, K_c, which is the ratio between the products and the product of equilibrium concentrations of all reactants.

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(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Want to see the full answer?

Chapter 15 Solutions

Solution Summary: The author explains the equilibrium constant, K_c, which is the ratio between the products and the product of equilibrium concentrations of all reactants.

Videos

(b) Interpretation: Number of H atoms and H2 molecules present in 1.0 L of 0.10 M H2 at 500 K Concept introduction: Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.

Want to see the full answer?

Chapter 15 Solutions

(b)

Interpretation:

Number of H atoms and H₂ molecules present in 1.0 L of 0.10 M H₂ at 500 K

Concept introduction:

Avogadro’s number is number of units in one mole of any substance equal to 6.022×1023. These number of units may be atoms, molecules, ions or electrons etc.