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The performance data of a water pump follow the curve fit
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Fluid Mechanics: Fundamentals and Applications
- Using Newton's second law, the movement of a body in a viscous fluid can be modeled. For this case it will be a one-dimensional movement. ec.1) F -FR = ma F: Force applied to the body. FR: Resistance that opposes the fluid to the movement. m: body mass a: body acceleration For a sphere with initial radius R0 = 1 meter and density 8960 kg/m^3 to which a constant force of 3 Kilo Newtons is applied, it is requested: Using Euler's method, find the velocity as a function of time for the first 5 seconds of movement, considering that v(0) = 10 m/s. Use a 1 second step. For this case use: ec.2) FR = 210Rv R: Radius of the sphere. v: velocity Where, in addition, the sphere disintegrates as time passes in this fluid, so its radius is given by the following function: ec.3) R = R0*e^(-t/250)arrow_forwardA pump 254 mm suction pipe and a 127 mm discharge pipe is used to deliver 52 L/s of water. The suction gage reads 15.6 kPa vacuum and the discharge gage located 100 cm above the suction gage which reads reads 108 kPa gage. Determine the following: 1. The total dynamic head in meter 2. The water power in kW 3. The motor horsepower if the pump efficiency is 76% Choices: 1. 13.856 14. 495 14.409 2. 7.631 7.348 8. 245 3. 12.960 14.935 13.935arrow_forwardvolume flow rate requirement of 21it/s with an of 60К Pa. A system has a index run ΔΡ Find an appropriate pump from the manufacturer's catalogue gives the following information for a centrifugal pump operating at 24rev/s: kPaQ lit/s 98.76 0.5 95 1 88.76 1.5 80 68.38 2.5 55 38.76 3.5 Two geometrically similar pumps are running at the same speed of 1000r.p.m. One has an impeller di ameter of 0. 4m and discharge of 301/s against a head of 20m. If the other pump gives half of this discharge rate, determine the head, diameter and power of the second pump.arrow_forward
- Problem #2: A velocity distribution is given as V = Please calculate the work flux (Iv) associated with molecular motions. -bx8,-byô, + bz8, where b is a constant and b‡0.arrow_forwardA closed thermodynamic system consists of a fixed amount of substance (i.e. mass) in which no substance can flow across the boundary, but energy can. For a closed themodynamic system we cannot add energy to the system, via substance (E ) (1.e. matter which contains energy is not allowed across the boundary) Across the Boundaries E° = No Q = = Yes W mass NO CLOSED = Yes SY STEM m = constant | energy YES Figure 1.1. If the substance inside the thermodynamic system shown in figure 1.1. (i.e. piston cylinder device) is air, is the system a Fixed closed system Moveable closed system A. В.arrow_forwardThe units for kinetic energy change in the following equation is m^2/s^2. To convert this to kJ/kg...arrow_forward
- A wind turbine gives the following data: Blade length= 55.5 m. Wind speed = 11 m/s Air density = 1.227 Kg/m3 Power coefficient = 0.55 Assuming equal efficiencies for gearbox and generator, If the Power output from wind turbine, P is 2.1 MW, then find a) Rotor Power Output, P- in M (* b) Wind Power, Pw in MW (: C) Efficiency of Generator Rotor Power Output, Pr in MWarrow_forwardThermodynamics: please help me in answering the following Practice problems and by step by step solution Thank you!arrow_forwardThe performance data for a centrifugal water pump are shown in Table for water at 77°F (gpm = gallons per minute). (a) For each row of data, calculate the pump efficiency (percent). Show all units and unit conversions for full credit. (b) Estimate the volume flow rate (gpm) and net head (ft) at the BEP of the pumparrow_forward
- WITH FRICTION Find the downward acceleration of ml if it has a mass of 40.9 kg and the kinetic coefficient of friction of m2 and m3 to the surface has the same value of 0.2. 5.00 kg T 3.00 kg 173 25.0° Select one: Oa 11.9831 m/s^2 ob 76410 m/s^2 Oc 15.7184 m/s^2 Od 40749 m/s^2arrow_forwardA three-fluid system (immiscible) is connected to a vacuum pump. The specific gravity values of the fluids (S₁, S₂) are given in the figure. To vaccum pump P P. S, = 0.88 Fluid I S₂ = 0.95 Fluid II 0.5 m Fluid Ill: Water Unit weight of water, Y = 9.81 kN/m Atmospheric pressure P = 95.43 kPa 1.5 m 1.0 m The gauge pressure value (in kN/m². up to two decimal places) of p, isarrow_forwardVelocity squared divided by double gravity is called the velocity head. If the mass entering a tank is greater than the mass exiting the tank, then the amount of mass in the tank will decrease through time. A flow in a pipe that has a Reynolds number of 105 would be considered a T F T F T F turbulent. d. T F The partial derivative of velocity with respect to time is called the convective acceleration. F The center of pressure is never above the centroid of a planar surface. An object submerged in oil (S = 0.88) will have a smaller buoyant force acting on it than when it is submerged in water. Turbulent flow in pipes tends to have a more uniform mean velocity profile than laminar flow in pipes. The Bernoulli equation requires that the two points in question are on the same streamline. e T F F h F i The weight of an object is different under water than it is out of the water. A pathline traces all particles that pass through a given point through time. F T Farrow_forward
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