Fluid Mechanics: Fundamentals and Applications
4th Edition
ISBN: 9781259696534
Author: Yunus A. Cengel Dr., John M. Cimbala
Publisher: McGraw-Hill Education
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Chapter 14, Problem 11CP
There are three main categories of dynamic pumps. List and define them.
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Chapter 14 Solutions
Fluid Mechanics: Fundamentals and Applications
Ch. 14 - What is the more common term for an...Ch. 14 - What the primary differences between fans,...Ch. 14 - List at least two common examples of fans, of...Ch. 14 - Discuss the primary difference between a porn...Ch. 14 - Explain why there is an “extra” term in the...Ch. 14 - For a turbine, discuss the difference between...Ch. 14 - Prob. 7CPCh. 14 - Prob. 8PCh. 14 - Prob. 9PCh. 14 - Prob. 10CP
Ch. 14 - There are three main categories of dynamic pumps....Ch. 14 - For each statement about cow cetrifugal the...Ch. 14 - Prob. 13CPCh. 14 - Consider flow through a water pump. For each...Ch. 14 - Write the equation that defines actual (available)...Ch. 14 - Consider a typical centrifugal liquid pump. For...Ch. 14 - Prob. 17CPCh. 14 - Consider steady, incompressible flow through two...Ch. 14 - Prob. 19CPCh. 14 - Prob. 20PCh. 14 - Suppose the pump of Fig. P1 4-19C is situated...Ch. 14 - Prob. 22PCh. 14 - Prob. 23EPCh. 14 - Consider the flow system sketched in Fig. PI 4-24....Ch. 14 - Prob. 25PCh. 14 - Repeat Prob. 14-25, but with a rough pipe-pipe...Ch. 14 - Consider the piping system of Fig. P14—24. with...Ch. 14 - The performance data for a centrifugal water pump...Ch. 14 - For the centrifugal water pump of Prob. 14-29,...Ch. 14 - Suppose the pump of Probs. 14-29 and 14-30 is used...Ch. 14 - Suppose you are looking into purchasing a water...Ch. 14 - The performance data of a water pump follow the...Ch. 14 - For the application at hand, the flow rate of...Ch. 14 - A water pump is used to pump water from one large...Ch. 14 - For the pump and piping system of Prob. 14-35E,...Ch. 14 - A water pump is used to pump water from one large...Ch. 14 - Suppose that the free surface of the inlet...Ch. 14 - Calculate the volume flow rate between the...Ch. 14 - Comparing the results of Probs. 14-39 and 14-43,...Ch. 14 - Prob. 45PCh. 14 - The performance data for a centrifugal water pump...Ch. 14 - Transform each column of the pump performance data...Ch. 14 - 14-51 A local ventilation system (a hood and duct...Ch. 14 - Prob. 52PCh. 14 - Repeat Prob. 14-51, ignoring all minor losses. How...Ch. 14 - Suppose the one- way of Fig. P14-51 malfunctions...Ch. 14 - A local ventilation system (a hood and duct...Ch. 14 - For the duct system and fan of Prob. 14-55E,...Ch. 14 - Repeat Prob. 14-55E, ignoring all minor losses....Ch. 14 - A self-priming centrifugal pump is used to pump...Ch. 14 - Repeat Prob. 14-60. but at a water temperature of...Ch. 14 - Repeat Prob. 14-60, but with the pipe diameter...Ch. 14 - Prob. 63EPCh. 14 - Prob. 64EPCh. 14 - Prob. 66PCh. 14 - Prob. 67PCh. 14 - Prob. 68PCh. 14 - Prob. 69PCh. 14 - Two water pumps are arranged in Series. The...Ch. 14 - The same two water pumps of Prob. 14-70 are...Ch. 14 - Prob. 72CPCh. 14 - Name and briefly describe the differences between...Ch. 14 - Discuss the meaning of reverse swirl in reaction...Ch. 14 - Prob. 75CPCh. 14 - Prob. 76CPCh. 14 - Prob. 77PCh. 14 - Prob. 78PCh. 14 - Prob. 79PCh. 14 - Prob. 80PCh. 14 - Wind ( =1.204kg/m3 ) blows through a HAWT wind...Ch. 14 - Prob. 82PCh. 14 - Prob. 84CPCh. 14 - A Francis radial-flow hydroturbine has the...Ch. 14 - Prob. 87PCh. 14 - Prob. 88PCh. 14 - Prob. 89PCh. 14 - Prob. 90CPCh. 14 - Prob. 91CPCh. 14 - Discuss which dimensionless pump performance...Ch. 14 - Prob. 93CPCh. 14 - Prob. 94PCh. 14 - Prob. 95PCh. 14 - Prob. 96PCh. 14 - Prob. 97PCh. 14 - Prob. 98PCh. 14 - Prob. 99PCh. 14 - Prob. 100EPCh. 14 - Prob. 101PCh. 14 - Calculate the pump specific speed of the pump of...Ch. 14 - Prob. 103PCh. 14 - Prob. 104PCh. 14 - Prob. 105PCh. 14 - Prob. 106PCh. 14 - Prob. 107EPCh. 14 - Prob. 108PCh. 14 - Prob. 109PCh. 14 - Prob. 110PCh. 14 - Prove that the model turbine (Prob. 14-109) and...Ch. 14 - Prob. 112PCh. 14 - Prob. 113PCh. 14 - Prob. 114PCh. 14 - Prob. 115CPCh. 14 - Prob. 116CPCh. 14 - Prob. 117CPCh. 14 - Prob. 118PCh. 14 - For two dynamically similar pumps, manipulate the...Ch. 14 - Prob. 120PCh. 14 - Prob. 121PCh. 14 - Prob. 122PCh. 14 - Calculate and compare the turbine specific speed...Ch. 14 - Prob. 124PCh. 14 - Prob. 125PCh. 14 - Prob. 126PCh. 14 - Prob. 127PCh. 14 - Prob. 128PCh. 14 - Prob. 129PCh. 14 - Prob. 130PCh. 14 - Prob. 131PCh. 14 - Prob. 132PCh. 14 - Prob. 133PCh. 14 - Prob. 134PCh. 14 - Prob. 135PCh. 14 - A two-lobe rotary positive-displacement pump moves...Ch. 14 - Prob. 137PCh. 14 - Prob. 138PCh. 14 - Prob. 139PCh. 14 - Prob. 140PCh. 14 - Which choice is correct for the comparison of the...Ch. 14 - Prob. 142PCh. 14 - In a hydroelectric power plant, water flows...Ch. 14 - Prob. 144PCh. 14 - Prob. 145PCh. 14 - Prob. 146PCh. 14 - Prob. 147PCh. 14 - Prob. 148PCh. 14 - Prob. 149PCh. 14 - Prob. 150PCh. 14 - Prob. 151P
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- Hello I was going over the solution for this probem and I'm a bit confused on the last part. Can you please explain to me 1^4 was used for the Co of the tubular cross section? Thank you!arrow_forwardBlood (HD = 0.45 in large diameter tubes) is forced through hollow fiber tubes that are 20 µm in diameter.Equating the volumetric flowrate expressions from (1) assuming marginal zone theory and (2) using an apparentviscosity for the blood, estimate the marginal zone thickness at this diameter. The viscosity of plasma is 1.2 cParrow_forwardQ2: Find the shear load on bolt A for the connection shown in Figure 2. Dimensions are in mm Fig. 2 24 0-0 0-0 A 180kN (10 Markarrow_forward
- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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