Configuration of the given alkene has to be identified from the given options. Concept Introduction: Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it. A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond. A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond. Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups. Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13.6, Problem 3QQ

Interpretation Introduction

Interpretation:

Configuration of the given alkene has to be identified from the given options.

Concept Introduction:

Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.

A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.

A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.

Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.

Cis‑trans isomers are not constitutional isomers but they are stereoisomers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

19.78 Write the products of the following sequences of reactions. Refer to your reaction road- maps to see how the combined reactions allow you to "navigate" between the different functional groups. Note that you will need your old Chapters 6-11 and Chapters 15-18 roadmaps along with your new Chapter 19 roadmap for these. (a) 1. BHS 2. H₂O₂ 3. H₂CrO4 4. SOCI₂ (b) 1. Cl₂/hv 2. KOLBU 3. H₂O, catalytic H₂SO4 4. H₂CrO4 Reaction Roadmap An alkene 5. EtOH 6.0.5 Equiv. NaOEt/EtOH 7. Mild H₂O An alkane 1.0 2. (CH3)₂S 3. H₂CrO (d) (c) 4. Excess EtOH, catalytic H₂SO OH 4. Mild H₂O* 5.0.5 Equiv. NaOEt/EtOH An alkene 6. Mild H₂O* A carboxylic acid 7. Mild H₂O* 1. SOC₁₂ 2. EtOH 3.0.5 Equiv. NaOEt/E:OH 5.1.0 Equiv. NaOEt 6. NH₂ (e) 1. 0.5 Equiv. NaOEt/EtOH 2. Mild H₂O* Br (f) i H An aldehyde 1. Catalytic NaOE/EtOH 2. H₂O*, heat 3. (CH,CH₂)₂Culi 4. Mild H₂O* 5.1.0 Equiv. LDA Br An ester 4. NaOH, H₂O 5. Mild H₂O* 6. Heat 7. MgBr 8. Mild H₂O* 7. Mild H₂O+

Li+ is a hard acid. With this in mind, which if the following compounds should be most soluble in water? Group of answer choices LiBr LiI LiF LiCl

Q4: Write organic product(s) of the following reactions and show the curved-arrow mechanism of the reactions. Br MeOH OSO2CH3 MeOH