
Concept explainers
(a)
Interpretation:
The physical state of ethene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(b)
Interpretation:
The physical state of 1-pentene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(c)
Interpretation:
The physical state of cyclobutene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(d)
Interpretation:
The physical state of cyclohexene at room temperature and pressure has to be indicated with the help of Figure 13-7.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.

Want to see the full answer?
Check out a sample textbook solution
Chapter 13 Solutions
Bundle: General, Organic, and Biological Chemistry, 7th + OWLv2 Quick Prep for General Chemistry, 4 terms (24 months) Printed Access Card
- elow are experimentally determined van Deemter plots of column efficiency, H, vs. flow rate. H is a quantitative measurement of band broadening. The left plot is for a liquid chromatography application and the night is for gas chromatography. Compare and contrast these two plots in terms of the three band broadening mechanisms presented in this activity. How are they similar? How do they differ? Justify your answers.? 0.4 H (mm) 0.2 0.1- 0.3- 0 0.5 H (mm) 8.0 7.0 6.0 5.0 4.0- 3.0 T +++ 1.0 1.5 0 2.0 4.0 Flow Rate, u (cm/s) 6.0 8.0 Flow Rate, u (cm/s)arrow_forwardPredict the products of this organic reaction: + H ZH NaBH3CN H+ n. ? Click and drag to start drawing a structure. Xarrow_forwardWhat is the missing reactant R in this organic reaction? + R H3O+ + • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure.arrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1 1. PPh3 2. n-BuLi 2 • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure.arrow_forwardThe product on the right-hand side of this reaction can be prepared from two organic reactants, under the conditions shown above and below the arrow. Draw 1 and 2 below, in any arrangement you like. 1+2 NaBH₂CN H+ N Click and drag to start drawing a structure. X $arrow_forwardExplain what is the maximum absorbance of in which caffeine absorbs?arrow_forward
- Explain reasons as to why the amount of caffeine extracted from both a singular extraction (5ml Mountain Dew) and a multiple extraction (2 x 5.0ml Mountain Dew) were severely high when compared to coca-cola?arrow_forwardProtecting Groups and Carbonyls 6) The synthesis generates allethrolone that exhibits high insect toxicity but low mammalian toxicity. They are used in pet shampoo, human lice shampoo, and industrial sprays for insects and mosquitos. Propose detailed mechanistic steps to generate the allethrolone label the different types of reagents (Grignard, acid/base protonation, acid/base deprotonation, reduction, oxidation, witting, aldol condensation, Robinson annulation, etc.) III + VI HS HS H+ CH,CH,Li III I II IV CI + P(Ph)3 V ༼ Hint: no strong base added VI S VII IX HO VIII -MgBr HgCl2,HgO HO. isomerization aqeuous solution H,SO, ༽༽༤༽༽ X MeOH Hint: enhances selectivity for reaction at the S X ☑arrow_forwardDraw the complete mechanism for the acid-catalyzed hydration of this alkene. esc 田 Explanation Check 1 888 Q A slock Add/Remove step Q F4 F5 F6 A བྲA F7 $ % 5 @ 4 2 3 & 6 87 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Ce W E R T Y U S D LL G H IK DD 요 F8 F9 F10 F1 * ( 8 9 0 O P J K L Z X C V B N M H He commandarrow_forward
- Explanation Check F1 H₂O H₂ Pd 1) MCPBA 2) H3O+ 1) Hg(OAc)2, H₂O 2) NaBH4 OH CI OH OH OH hydration halohydrin formation addition halogenation hydrogenation inhalation hydrogenation hydration ☐ halohydrin formation addition halogenation formation chelation hydrogenation halohydrin formation substitution hydration halogenation addition Ohalohydrin formation subtraction halogenation addition hydrogenation hydration F2 80 F3 σ F4 F5 F6 1 ! 2 # 3 $ 4 % 05 Q W & Å © 2025 McGraw Hill LLC. All Rights Reserved. F7 F8 ( 6 7 8 9 LU E R T Y U A F9arrow_forwardShow the mechanism steps to obtain the lowerenergy intermediate: *see imagearrow_forwardSoap is made by the previous reaction *see image. The main difference between one soap and another soap isthe length (number of carbons) of the carboxylic acid. However, if a soap irritates your skin, they mostlikely used too much lye.Detergents have the same chemical structure as soaps except for the functional group. Detergentshave sulfate (R-SO4H) and phosphate (R-PO4H2) functional groups. Draw the above carboxylic acidcarbon chain but as the two variants of detergents. *see imagearrow_forward
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning



